Sorry between * and the variable name.
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-----Original Message-----
From: Kamakshii Aggarwal <[email protected]>
Sender: [email protected]
Date: Wed, 27 Jul 2011 19:21:13
To: <[email protected]>
Reply-To: [email protected]
Subject: Re: [algogeeks] output
@magesh:so acc to you the code below should give error?
#include<stdio.h>
int main(int argc,char *argv[])
{
char const *s="";
char str[]="hello";
s=str;
while(*s){
printf("%c",*s++);
}
system("pause");
return 0;
}
On Wed, Jul 27, 2011 at 7:12 PM, <[email protected]> wrote:
> ** Its not a const pointer. It is pointer to constant. So only modifying
> the value of s will cause error. For constant to pointer the const has to be
> between * and the keyword
>
> Sent from BlackBerry® on Airtel
> ------------------------------
> *From: * Kamakshii Aggarwal <[email protected]>
> *Sender: * [email protected]
> *Date: *Wed, 27 Jul 2011 19:09:20 +0530
> *To: *<[email protected]>
> *ReplyTo: * [email protected]
> *Subject: *[algogeeks] output
>
> #include<stdio.h>
>
> int main(int argc,char *argv[])
> {
> const char *s="";
> char str[]="hello";
> s=str;
> while(*s){
> printf("%c",*s++);
> }
>
> system("pause");
>
> return 0;
> }
> o/p is hello.
> why the above code is running normally even when constant char pointer is
> being incremented...??plss help...
> --
> Regards,
> Kamakshi
> [email protected]
>
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--
Regards,
Kamakshi
[email protected]
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