when swap is called ,as it is a macro ,before compilation its code is
replaced and the code before compilation bcomes:
> # define swap(a,b) temp=a; a=b; b=temp;
> main( )
> {
> int i, j, temp;
> i=5;
> j=10;
> temp=0;
> if( i > j)
>
//code replaced here
> temp=a; //not executed (false)
>
a=b; //a=10(from b=10)
b=temp; //b=0 (from temp=0)
> printf( “%d %d %d”, i, j, temp);
> }
>
> and that is why u get output 10,0,0...
>
>
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