@abhinav:thanks.:)
On Wed, Jul 27, 2011 at 9:23 PM, Abhinav Arora <[email protected]>wrote:
> Look we wish to allocate memory for an array of 3 integer pointers.
> so when we do dynamic allocation we always store the result in a pointer to
> the required data type.
> for example if you wish to dynamically allocate int arr[3[]
> u will write :
>
> int *p=malloc(3*sizeof(int));
>
> So now when you do it for an array of integer pointers the result of malloc
> should point to the first element of the dynamically allocated array. The
> elements of the array are pointers hence the memory allocated will be saved
> in a pointer that will correspond to the pointer to the first element. Since
> the elements are pointers so the result of malloc will be saved to a pointer
> to a pointer.
>
> My sample program which i compiled in Dev C++ is as follows :
>
>
> #include<stdio.h>
> #include<conio.h>
> main()
> {
> int a,b,c;
> int **p;
> p=malloc(3*sizeof(int *));
> a=b=c=1;
> p[0]=&a;
> p[1]=&b;
> p[2]=&c;
> printf("%d %d %d",*p[0],*p[1],*p[2]);
> getch();
> }
>
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--
Regards,
Kamakshi
[email protected]
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