char const *s and const char *s are both same...try using char *const s..it
will give error then

On Wed, Jul 27, 2011 at 7:21 PM, Kamakshii Aggarwal
<[email protected]>wrote:

> @magesh:so acc to you the code below should give error?
> #include<stdio.h>
>
> int main(int argc,char *argv[])
> {
>   char const *s="";
>  char str[]="hello";
>  s=str;
>  while(*s){
>            printf("%c",*s++);
>            }
>
>  system("pause");
>
>   return 0;
> }
>
>
> On Wed, Jul 27, 2011 at 7:12 PM, <[email protected]> wrote:
>
>> ** Its not a const pointer. It is pointer to constant. So only modifying
>> the value of s will cause error. For constant to pointer the const has to be
>> between * and the keyword
>>
>> Sent from BlackBerry® on Airtel
>> ------------------------------
>> *From: * Kamakshii Aggarwal <[email protected]>
>> *Sender: * [email protected]
>> *Date: *Wed, 27 Jul 2011 19:09:20 +0530
>> *To: *<[email protected]>
>> *ReplyTo: * [email protected]
>> *Subject: *[algogeeks] output
>>
>> #include<stdio.h>
>>
>> int main(int argc,char *argv[])
>> {
>>  const char *s="";
>>  char str[]="hello";
>>  s=str;
>>  while(*s){
>>            printf("%c",*s++);
>>            }
>>
>>  system("pause");
>>
>>   return 0;
>> }
>> o/p is hello.
>> why the above code is running normally even when constant char pointer is
>> being incremented...??plss help...
>> --
>> Regards,
>> Kamakshi
>> [email protected]
>>
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>
>
>
> --
> Regards,
> Kamakshi
> [email protected]
>
> --
> You received this message because you are subscribed to the Google Groups
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> To post to this group, send email to [email protected].
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>



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