OK, This is the post where I make a total fool out of myself, my contrite apologies. I don't know if I had edited it to many times and was just not seeing it. At the end of the day when I read the email and opened the code there it was. I even recoded the previous part and it worked fine. Once again I apologize and I do appreciate all your help.
thanks --jerry On Tuesday, May 15, 2012 1:33:05 PM UTC-5, Anthony wrote: > > outside of the string passed to the message variable in the call to dict >> my code is exactly the same, I didn't have any luck with the version above >> this so I coded this instead. As far as the syntax error, I would be happy >> to know where it is as I can't see it. And yes the trace is pointing to a >> piece of code that doesn't show in my file. >> non-keyword arg after keyword arg (default.py, line 14) >> and line 14 is the last line of my code that I am showing here. >> *return dict(message="hello", session.counter)* >> > Yes, that's the syntax error that several people have now pointed out to > you. You have passed session.counter to dict() as a non-keyword argument > (and it only takes keyword arguments, where the argument names become the > dict keys). You have mis-copied that line from the book -- it should be: > > return dict(message="Hello from MyApp", counter=session.counter) > > > Anthony >
