This is fine:
db.define_table('announce',
Field('picture','upload',uploadfolder=request.folder+'static/
pictures'),
)
but why do you need an action to download from the static folder? Why
not simply use
URL('static',record.picture)
On Jun 17, 5:56 am, Bruno Rocha <rochacbr...@gmail.com> wrote:
> For security reasons, web2py does not expose the 'uploads' folder to the
> user, this folder can be accessed only by the 'download' function.
>
> The best way is to set the upload path pointing to /static not to /upload
> and you will have your uploaded files to be served as static files,
> bypassing download function.
>
> under /static create a folder called 'picture'
>
> *Go to the table definition and do this:*
>
> *<model>*
> db.define_table('announce',
>
> Field('picture','upload',uploadfolder=request.folder+'static/pictures'),
> )
> *</model>*
>
> You are saying DAL to store uploades files in to that folder under static
> and store the ath in the field.
>
> Now in your controller create a function do handle that (different from
> download, it is a kind of viewer)
>
> *<controller>*
> def viewer():
> row = db(db.announce.id
> ==request.args(0)).select(db.announce.picture).first()
> redirect(URL('static','pictures',args=row.picture))
> *</controller>*
>
> *Now you can fo this:*
>
> http://server/app/default/viewer/3# record id
>
> then you got redirected to the image (no html page)
>
> example:http://127.0.0.1:8000/app/static/pictures/announce.picture.aaf5d3f777...
>
> you can always refer directly to the image path (not using the viewer
> function) but you always need to fetch the picture name from db.
>
> Hope it helps.
>
> Should go on the book?
>
> --
> Bruno Rocha
> [ About me:http://zerp.ly/rochacbruno]
> [ Aprenda a programar:http://CursoDePython.com.br]
>
> On Thu, Jun 16, 2011 at 6:09 AM, Vinicius Assef <vinicius...@gmail.com>wrote:
>
>
>
>
>
>
>
> > Hi guys.
>
> > I have a table (called anuncio) with an upload field (called foto), so
> > anuncio.foto is my upload field.
>
> > I'm showing and linking it with this piece of code in my view :
> > {{url = URL(c='anuncios',f='download', args=['uploads', anuncio.foto])}}
> > {{=A(IMG(_src=url), _href=url)}}
>
> > My /contollers/anuncios.py/download() function is the default, as seen
> > below:
> > def download():
> > return response.download(request,db)
>
> > When user clicks on this image, browser shows the download dialog,
> > asking him/her where to save the image.
> > But I'd like to simply show the image, not present the download
> > dialog. All these images will be public.
>
> > How I solved it:
> > 1) I entered in /myapp/static/images and created a symbolic link
> > called 'uploads' pointing to /myapp/uploads.
> > 2) In my view, I changed the: {{url = URL(...}} stuff by this: {{url =
> > URL(c='static', f='images', args=['uploads', anuncio.foto])}}
>
> > I think this isn't the best choice because I'm pointing URL() to a
> > fake controller and function, and I'm counting on an external
> > resource: a symbolic link in my filesystem.
>
> > How would be the "web2pythonic" way to do this?
>
> > --
> > Vinicius Assef.
