btw if you have different image type you can get the extension with
os.path.splitext(path)
On Jun 17, 11:41 am, selecta <gr...@delarue-berlin.de> wrote:
> The problem is that download creates a http response with attachment
> you should be able to write a function that just returns the content
> of the image
> def show()
> import gluon.contenttype
> response.headers['Content-Type'] =
> gluon.contenttype.contenttype('.jpg')
> filename, file =
> db.myimages.img_upload.retrieve( db.myimages[1].img_upload)
> return file.read()
>
> On Jun 16, 11:09 am, Vinicius Assef <vinicius...@gmail.com> wrote:
>
>
>
> > Hi guys.
>
> > I have a table (called anuncio) with an upload field (called foto), so
> > anuncio.foto is my upload field.
>
> > I'm showing and linking it with this piece of code in my view :
> > {{url = URL(c='anuncios',f='download', args=['uploads', anuncio.foto])}}
> > {{=A(IMG(_src=url), _href=url)}}
>
> > My /contollers/anuncios.py/download() function is the default, as seen
> > below:
> > def download():
> > return response.download(request,db)
>
> > When user clicks on this image, browser shows the download dialog,
> > asking him/her where to save the image.
> > But I'd like to simply show the image, not present the download
> > dialog. All these images will be public.
>
> > How I solved it:
> > 1) I entered in /myapp/static/images and created a symbolic link
> > called 'uploads' pointing to /myapp/uploads.
> > 2) In my view, I changed the: {{url = URL(...}} stuff by this: {{url =
> > URL(c='static', f='images', args=['uploads', anuncio.foto])}}
>
> > I think this isn't the best choice because I'm pointing URL() to a
> > fake controller and function, and I'm counting on an external
> > resource: a symbolic link in my filesystem.
>
> > How would be the "web2pythonic" way to do this?
>
> > --
> > Vinicius Assef.
