I am trying to do everything in the lambda, without the need to def the
function.
Tks..
2010/8/15 mdipierro <mdipie...@cs.depaul.edu>
> If you define a function you do not need the lambda
>
> Field('slug', notnull=True, compute=get_brand),
>
> On Aug 15, 2:45 am, Bruno Rocha <rochacbr...@gmail.com> wrote:
> > Thank you Massimo! works very well. I just needed to change a little in
> > order to get the brand.name instead brand.id in the slug
> >
> > This:
> >
> > def get_brand(r):
> > import re
> > brand = db(db.brand.id==r.brand).select().first()
> > slug_regex = re.compile('[^\w-]')
> > return slug_regex.sub('',brand.nome+'-%(model)s-%(year)s' %r).lower()
> >
> > and:
> >
> > Field('slug', notnull=True, compute= lambda r: get_brand(r)),
> >
> > to get: 'toyota-corolla-2010' as slug ( I still wants to get the r.idat
> > the end)
> >
> > Tks.
> >
> > 2010/8/15 mdipierro <mdipie...@cs.depaul.edu>
> >
> >
> >
> > > import re
> > > slug_regex = re.compile('[^\w-]')
> >
> > > Field('slug',compute=lambda r: slug_regex.sub('','%(brand)s-%(model)s-%
> > > (year)s' %r).lower())
> >
> > > On Aug 14, 11:12 pm, Bruno Rocha <rochacbr...@gmail.com> wrote:
> > > > I need a page slug for the cars in my car shop,
> > > > instead havinghttp://.../default/car/2,
> > > > I wanthttp://..../default/car/carbrand-carmodel-caryear-id
> >
> > > > so I defined a table:
> >
> > > > db.define_table('car'
> > > > Field('brand', db.brand),
> > > > Field('model'),
> > > > Field('year','integer'),
> > > > Field('slug')
> > > > )
> >
> > > > but I do not want the user to fill the "slug" field, so I have to
> define
> > > > default value to the slug field, concatenating 'brand' + 'model' +
> 'year'
> > > +
> > > > 'slug' joining with a '-',
> > > > eg:
> > > > id = 2
> > > > brand = 'Toyota'
> > > > model = 'Corolla'
> > > > year = '2010'
> > > > slug = 'toyota-corolla-2010-2'
> >
> > > > how can I get this to be automaticaly filled when inserting? (just
> like a
> > > > trigger)
> >
> > --
> >
> > http://rochacbruno.com.br
>
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