import re
slug_regex = re.compile('[^\w-]')
Field('slug',compute=lambda r: slug_regex.sub('','%(brand)s-%(model)s-%
(year)s' %r).lower())
On Aug 14, 11:12 pm, Bruno Rocha <rochacbr...@gmail.com> wrote:
> I need a page slug for the cars in my car shop,
> instead havinghttp://.../default/car/2,
> I wanthttp://..../default/car/carbrand-carmodel-caryear-id
>
> so I defined a table:
>
> db.define_table('car'
> Field('brand', db.brand),
> Field('model'),
> Field('year','integer'),
> Field('slug')
> )
>
> but I do not want the user to fill the "slug" field, so I have to define
> default value to the slug field, concatenating 'brand' + 'model' + 'year' +
> 'slug' joining with a '-',
> eg:
> id = 2
> brand = 'Toyota'
> model = 'Corolla'
> year = '2010'
> slug = 'toyota-corolla-2010-2'
>
> how can I get this to be automaticaly filled when inserting? (just like a
> trigger)
