If you define a function you do not need the lambda
Field('slug', notnull=True, compute=get_brand),
On Aug 15, 2:45 am, Bruno Rocha <rochacbr...@gmail.com> wrote:
> Thank you Massimo! works very well. I just needed to change a little in
> order to get the brand.name instead brand.id in the slug
>
> This:
>
> def get_brand(r):
> import re
> brand = db(db.brand.id==r.brand).select().first()
> slug_regex = re.compile('[^\w-]')
> return slug_regex.sub('',brand.nome+'-%(model)s-%(year)s' %r).lower()
>
> and:
>
> Field('slug', notnull=True, compute= lambda r: get_brand(r)),
>
> to get: 'toyota-corolla-2010' as slug ( I still wants to get the r.id at
> the end)
>
> Tks.
>
> 2010/8/15 mdipierro <mdipie...@cs.depaul.edu>
>
>
>
> > import re
> > slug_regex = re.compile('[^\w-]')
>
> > Field('slug',compute=lambda r: slug_regex.sub('','%(brand)s-%(model)s-%
> > (year)s' %r).lower())
>
> > On Aug 14, 11:12 pm, Bruno Rocha <rochacbr...@gmail.com> wrote:
> > > I need a page slug for the cars in my car shop,
> > > instead havinghttp://.../default/car/2,
> > > I wanthttp://..../default/car/carbrand-carmodel-caryear-id
>
> > > so I defined a table:
>
> > > db.define_table('car'
> > > Field('brand', db.brand),
> > > Field('model'),
> > > Field('year','integer'),
> > > Field('slug')
> > > )
>
> > > but I do not want the user to fill the "slug" field, so I have to define
> > > default value to the slug field, concatenating 'brand' + 'model' + 'year'
> > +
> > > 'slug' joining with a '-',
> > > eg:
> > > id = 2
> > > brand = 'Toyota'
> > > model = 'Corolla'
> > > year = '2010'
> > > slug = 'toyota-corolla-2010-2'
>
> > > how can I get this to be automaticaly filled when inserting? (just like a
> > > trigger)
>
> --
>
> http://rochacbruno.com.br
