Nice trick!! Many thanks for that, I read read too fast your preceding post... I will see what I can do with that, it should solve my issue...
Richard On Fri, Feb 7, 2014 at 1:51 PM, Anthony <abasta...@gmail.com> wrote: > So, is : >> >> widget=lambda field, value, row: ... >> >> Working out of the box in last web2py stable? >> > > No, web2py will not pass a row to a widget -- it only passes a field and > value. That's why I said to do: > > lambda field, value, row=row: ... > > In that case, you are specifying the "row" argument of the lambda with a > default value (notice the "=row"), which of course you must define yourself > in the preceding code (that's why I asked if you already had a row object). > When web2py calls the widget, it will pass in the field and value, and the > lambda function itself will then have access to the field, value, and row. > > Anthony > > -- > Resources: > - http://web2py.com > - http://web2py.com/book (Documentation) > - http://github.com/web2py/web2py (Source code) > - https://code.google.com/p/web2py/issues/list (Report Issues) > --- > You received this message because you are subscribed to the Google Groups > "web2py-users" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to web2py+unsubscr...@googlegroups.com. > For more options, visit https://groups.google.com/groups/opt_out. > -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
