> > So, is : > > widget=lambda field, value, row: ... > > Working out of the box in last web2py stable? >
No, web2py will not pass a row to a widget -- it only passes a field and value. That's why I said to do: lambda field, value, row=row: ... In that case, you are specifying the "row" argument of the lambda with a default value (notice the "=row"), which of course you must define yourself in the preceding code (that's why I asked if you already had a row object). When web2py calls the widget, it will pass in the field and value, and the lambda function itself will then have access to the field, value, and row. Anthony -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/groups/opt_out.
