thanks a ton,
I ll try this and what would be appropriate place to insert the file , so
that it is not efficient.

thanks,

regards,

Tushar Tuteja


On 17 October 2013 00:22, Niphlod <niph...@gmail.com> wrote:

> the scheduler is running fine.
> In the data you pasted here there's the reason why the scheduler isn't
> picking up any new task.
> times_run is 3 and repeats is set to 3, so the task got executed 3 times
> already.
>
> Sidenote: append a "return 1" to your function, so you'll get
> scheduler_run records holding more details about the executions, until you
> figure out the issues you're having on what to choose when you queue the
> task.
>
> Also, please do
>
> sched = Scheduler(db, dict(fun=func))
>
> sched.queue_task('func', uuid='test_insert', repeats=3, period=10)
>
> without any worker running, so you can see what is inserted into the
> scheduler_task table correctly.
> Execute the sched.queue_task just one time only (if you put that in
> models, it will be executed at every request and that would be inefficient)
>
>
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-- 
Tushar Tuteja
Undergraduate Student(Fourth Year)
Civil Engineering
IIT Delhi
+919953061943
ttut...@gmail.com <ttut...@gmal.com>
ce1090...@civil.iitd.ernet.in
"The question isn't who is going to let me; its who is going to stop me!" -
Howard Roark

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- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
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