No More need to Reinvent the wheel and it just works :)
On Thu, Nov 13, 2008 at 9:18 PM, Phyo Arkar <[EMAIL PROTECTED]>wrote:
> In spirit of Dont Repeat Yourself And to avoid Copy Pasting :
>
> os.popen('curl -F "[EMAIL PROTECTED]" -F "[EMAIL PROTECTED]" -F "type=%s" -F
> "subgenre=%s" "
> http://127.0.0.1:81/ultest/uploader.php";' %
> (torrentfile,nfofile,subgenre,type) )
>
> This does the best trick :D
>
>
>
> On Thu, Nov 13, 2008 at 9:05 PM, mdipierro <[EMAIL PROTECTED]>wrote:
>
>>
>> makes sense. Let us know if the script above does the trick.
>>
>> Massimo
>>
>> On Nov 13, 2:49 pm, "Phyo Arkar" <[EMAIL PROTECTED]> wrote:
>> > Acutally , I am building a file upload script :D Which automaticlaly
>> files
>> > to a mirrored server via http.
>> >
>> > On Thu, Nov 13, 2008 at 7:56 PM, Yarko T <[EMAIL PROTECTED]> wrote:
>> > > Phyo is trying to build a bot! ;-)
>> >
>> > > On Thu, Nov 13, 2008 at 1:45 PM, Phyo Arkar <[EMAIL PROTECTED]
>> >wrote:
>> >
>> > >> Dear Ceej
>> >
>> > >> I would like to upload to a form , from a python script. (Client
>> side)
>> >
>> > >> Web2py do no thave upload (as client) rite?
>> >
>> > >> Thanks for reply anyways.
>> >
>> > >> Regards,
>> >
>> > >> Phyo.
>> >
>> > >> On Thu, Nov 13, 2008 at 7:15 PM, ceej <[EMAIL PROTECTED]>
>> wrote:
>> >
>> > >>> Phyo,
>> >
>> > >>> To get the data from the form that's submitted you can to
>> > >>> request.vars.file.file.read():
>> >
>> > >>> And to write it to uploads you can do something like
>> >
>> > >>> _folder='%(folder)suploads/'%{'folder': request.folder}
>> > >>> main_token=md5.new(str(datetime.datetime.now
>> > >>> ())).hexdigest()
>> > >>> if not os.path.exists(_folder):
>> > >>> os.makedirs('%sfile'%(_folder))
>> > >>> file = open('%syou_can_make_a_name.jpg'%(_folder),
>> 'wb')
>> > >>> file.write(request.vars.file.file.read())
>> > >>> file.close
>> >
>> > >>> On Nov 13, 10:33 am, "Phyo Arkar" <[EMAIL PROTECTED]> wrote:
>> > >>> > Dear All;
>> >
>> > >>> > How can i upload multipart form data files in python (web2py?)
>> >
>> > >>> > I cannot do it with
>> >
>> > >>> > urllib.urlencode
>> > >>> > urllib2.urlopen(url,data)
>> >
>> > >>> > Files will not be uploaded , just urls will b posted ..(server
>> backend
>> > >>> is
>> > >>> > php)
>> >
>> > >>> > def upload(torrentfile,nfofile,subgenre='Minimal',type=10):
>> > >>> > nfo_file=file(nfofile)
>> > >>> > torrent_file=file(torrentfile)
>> > >>> > data = {'nfo': nfo_file,
>> > >>> > 'desc': "",
>> > >>> > 'file': torrent_file,
>> > >>> > 'type': type,
>> > >>> > 'subgenre' : subgenre
>> > >>> > }
>> > >>> > uldata =urllib.urlencode(data)
>> > >>> > req = urllib2.Request(upload_url,uldata)
>> > >>> > resp = urllib2.urlopen(req)
>> > >>> > result = resp.read()
>> > >>> > print result
>> >>
>>
>
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