makes sense. Let us know if the script above does the trick.
Massimo
On Nov 13, 2:49 pm, "Phyo Arkar" <[EMAIL PROTECTED]> wrote:
> Acutally , I am building a file upload script :D Which automaticlaly files
> to a mirrored server via http.
>
> On Thu, Nov 13, 2008 at 7:56 PM, Yarko T <[EMAIL PROTECTED]> wrote:
> > Phyo is trying to build a bot! ;-)
>
> > On Thu, Nov 13, 2008 at 1:45 PM, Phyo Arkar <[EMAIL PROTECTED]>wrote:
>
> >> Dear Ceej
>
> >> I would like to upload to a form , from a python script. (Client side)
>
> >> Web2py do no thave upload (as client) rite?
>
> >> Thanks for reply anyways.
>
> >> Regards,
>
> >> Phyo.
>
> >> On Thu, Nov 13, 2008 at 7:15 PM, ceej <[EMAIL PROTECTED]> wrote:
>
> >>> Phyo,
>
> >>> To get the data from the form that's submitted you can to
> >>> request.vars.file.file.read():
>
> >>> And to write it to uploads you can do something like
>
> >>> _folder='%(folder)suploads/'%{'folder': request.folder}
> >>> main_token=md5.new(str(datetime.datetime.now
> >>> ())).hexdigest()
> >>> if not os.path.exists(_folder):
> >>> os.makedirs('%sfile'%(_folder))
> >>> file = open('%syou_can_make_a_name.jpg'%(_folder), 'wb')
> >>> file.write(request.vars.file.file.read())
> >>> file.close
>
> >>> On Nov 13, 10:33 am, "Phyo Arkar" <[EMAIL PROTECTED]> wrote:
> >>> > Dear All;
>
> >>> > How can i upload multipart form data files in python (web2py?)
>
> >>> > I cannot do it with
>
> >>> > urllib.urlencode
> >>> > urllib2.urlopen(url,data)
>
> >>> > Files will not be uploaded , just urls will b posted ..(server backend
> >>> is
> >>> > php)
>
> >>> > def upload(torrentfile,nfofile,subgenre='Minimal',type=10):
> >>> > nfo_file=file(nfofile)
> >>> > torrent_file=file(torrentfile)
> >>> > data = {'nfo': nfo_file,
> >>> > 'desc': "",
> >>> > 'file': torrent_file,
> >>> > 'type': type,
> >>> > 'subgenre' : subgenre
> >>> > }
> >>> > uldata =urllib.urlencode(data)
> >>> > req = urllib2.Request(upload_url,uldata)
> >>> > resp = urllib2.urlopen(req)
> >>> > result = resp.read()
> >>> > print result
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