Acutally , I am building a file upload script :D Which automaticlaly files
to a mirrored server via http.
On Thu, Nov 13, 2008 at 7:56 PM, Yarko T <[EMAIL PROTECTED]> wrote:
> Phyo is trying to build a bot! ;-)
>
>
> On Thu, Nov 13, 2008 at 1:45 PM, Phyo Arkar <[EMAIL PROTECTED]>wrote:
>
>> Dear Ceej
>>
>> I would like to upload to a form , from a python script. (Client side)
>>
>> Web2py do no thave upload (as client) rite?
>>
>> Thanks for reply anyways.
>>
>> Regards,
>>
>> Phyo.
>>
>>
>> On Thu, Nov 13, 2008 at 7:15 PM, ceej <[EMAIL PROTECTED]> wrote:
>>
>>>
>>> Phyo,
>>>
>>> To get the data from the form that's submitted you can to
>>> request.vars.file.file.read():
>>>
>>> And to write it to uploads you can do something like
>>>
>>> _folder='%(folder)suploads/'%{'folder': request.folder}
>>> main_token=md5.new(str(datetime.datetime.now
>>> ())).hexdigest()
>>> if not os.path.exists(_folder):
>>> os.makedirs('%sfile'%(_folder))
>>> file = open('%syou_can_make_a_name.jpg'%(_folder), 'wb')
>>> file.write(request.vars.file.file.read())
>>> file.close
>>>
>>> On Nov 13, 10:33 am, "Phyo Arkar" <[EMAIL PROTECTED]> wrote:
>>> > Dear All;
>>> >
>>> > How can i upload multipart form data files in python (web2py?)
>>> >
>>> > I cannot do it with
>>> >
>>> > urllib.urlencode
>>> > urllib2.urlopen(url,data)
>>> >
>>> > Files will not be uploaded , just urls will b posted ..(server backend
>>> is
>>> > php)
>>> >
>>> > def upload(torrentfile,nfofile,subgenre='Minimal',type=10):
>>> > nfo_file=file(nfofile)
>>> > torrent_file=file(torrentfile)
>>> > data = {'nfo': nfo_file,
>>> > 'desc': "",
>>> > 'file': torrent_file,
>>> > 'type': type,
>>> > 'subgenre' : subgenre
>>> > }
>>> > uldata =urllib.urlencode(data)
>>> > req = urllib2.Request(upload_url,uldata)
>>> > resp = urllib2.urlopen(req)
>>> > result = resp.read()
>>> > print result
>>>
>>>
>>
>>
>>
>
> >
>
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