Peaks of COP 200 then.
2013/5/13 Patrick Ellul <[email protected]> > I thought he might have done a typo, and mean 10 kWh/h so I emailed him to > ask. > > He confirmed that it was a typo, and he meant 10kWh/h for the ecat, just > like it has always been. > > If that is the case: > > 0.91 * 35% of the time = 0.3185 kWh/h > *10* * 65% of the time = 6.5 kWh/h > > total output = 6.8185 kWh/h > input = 0.9 * 35% of the time = 0.315 kWh/h > > COP = 21.65 > > > On Tue, May 14, 2013 at 11:25 AM, Alan Fletcher <[email protected]> wrote: > >> > If you split the time between activator and ecat as he suggests you >> > get slightly different numbers: >> > >> > 0.91 * 35% of the time = 0.3185 kWh/h >> > 1 * 65% of the time = 0.65 kWh/h >> > >> > >> > total output = 0.9685 kWh/h >> > input = 0.9 * 35% of the time = 0.315 kWh/h >> > >> > >> > COP = 3.07 >> >> That's how I did it at first ... then I reread his statement and thought >> he was talking about the total. >> >> Either way, MUCH less than 100-200 -- and less than his usual guaranteed >> COP of 6. >> >> (And I have no idea of the implication of Terry's "The magic ratio that >> FE people have sought!" ) >> >> > > > -- > Patrick > > www.tRacePerfect.com > The daily puzzle everyone can finish but not everyone can perfect! > The quickest puzzle ever! > -- Daniel Rocha - RJ [email protected]
