Dear all:
My analysis (7-21-05) was intended for those who are not conversant with
logic. A much shorter abstracted version follows.
Assume that p implies not q. Equivalently, p implies (not possible) q. But,
for any p and q, p implies (q or not q) or, equivalently, p implies possible
q. There is no contradiction. However, contradiction arises when (not possible)
q is interpreted incorrectly as not (possibly q).
The answer to the question, thus, depends on how not possible q is parsed.
If not possible q is read with accent in not, many people would interpret it as
not (possible q), leading to contradiction.
Regards to all,
Lotfi
--
Lotfi A. Zadeh
Professor in the Graduate School, Computer Science Division
Department of Electrical Engineering and Computer Sciences
University of California
Berkeley, CA 94720 -1776
Director, Berkeley Initiative in Soft Computing (BISC)
_______________________________________________
uai mailing list
uai@ENGR.ORST.EDU
https://secure.engr.oregonstate.edu/mailman/listinfo/uai
