On Thu, Nov 14, 2013 at 04:56:49PM +0000, Paul Hodges wrote: > 1 ground > 2 power > 3 W+, X-, Y- > 4 W-, X+, Y- > 5 W-, X-, Y+ > > then > > W is (3, 0.5(4+5)) > X is (4, 0.5(3+5)) > Y is (5, 0.5(3+4)) > > That's better; things cancel out properly that way.
Shouldn't that be W is (3, 0.5 (4, 5)) X is (4, 0.5 (3, 5)) Y is (5, 0.5 (3, 4)) assuming (x, y) stands for x - y ? But this is not really balanced - you can't obtain W,X,Y without referring to ground. It could be 'impedance balanced' combined with some matrixing. You need at least 4 signal wires to have 3 balanced connections, e.g.: A = ground B = W + X + Y C = -W + X + Y D = W - X + Y E = W + X - Y (with phantom power on B,C,D,E) Then W = 0.5 (B - C) X = 0.5 (B - D) Y = 0.5 (B - E) which can be obtained without using the ground wire. Ciao, -- FA A world of exhaustive, reliable metadata would be an utopia. It's also a pipe-dream, founded on self-delusion, nerd hubris and hysterically inflated market opportunities. (Cory Doctorow) _______________________________________________ Sursound mailing list Sursound@music.vt.edu https://mail.music.vt.edu/mailman/listinfo/sursound
