url: http://escribe.com/health/thesilverlist/m60011.html Re: CS>Re: $$$ perpectives From: Robert Berger Date: Tue, 10 Jun 2003 08:09:33
> Hi Mike, > I am attaching a Wplot32 file "5x8 repro" You can open it with any > writing program. I finally got it via email. Thanks! > The first series of numbers is for conductance, the second is for > cell current, and the third is the cell voltage. > The integral of the current curve from 0 to 3.6 hr is 23.6405 > ma-hrs. The voltage is about constant 35 volts. If you plot the > current curve you will not that there is a 48 hour break at the 3 > hour point. Wplot32.exe does all kinds of transformations! It turns out the 16-bit version of WPLOT is compatible except for a few minor commands. I get the same integral of 23.6405 from zero to 3.8 hrs. To get the average current, I divide by 3.8 and get 6.2211842 mA. The total number of Coulombs is 85, and in 2 gal this produces 12.56 ppm. Here's the equations hrs = 3.8 ; hours I = 6.2211842e-3 ; current in Amperes gal = 2 ; number of gallons ml = 3785.41 * gal ; milliliters x = 1e6 * 107.87 / 96485 ; x = 1117.99 sec = hrs * 3600 + mnt * 60 ; seconds C = I * sec ; Coulombs ppm = x * C / ml ; parts per million ppmhr = x * I * 3600 / ml ; ppm per hr ;ppmhr = 2 Here's the results: C = +85.1057998560000 gal = +2.00000000000000 hrs = +3.80000000000000 I = +0.00622118420000 ml = +7570.82000000000 ppm = +12.5677378889782 ppmhr = +3.30729944446795 sec = +13680.0000000000 x = +1117.99761620977 Now you have to subtract the amount that forms particles. With your current density at the cathode being so high, I would expect a significant portion is lost making black sludge. So the total ppm will be lower. But you can put a small amount in a glass and add salt. Cover it so it won't evaporate, then compare the difference after running at 100uA/sq. in. > Your statement that you can feel the difference on the teeth > sounds suspiciously like the presence of NO3 in your product. Have > you checked it? Gee, Bob, if 0.8V across the cell causes a problem, then I'd really be concerned about putting 30V across it. I really don't think NO3 is a problem with this process. > When the actual conductance gets too far removed from the actual > AG+ PPM then the pH is low and NO3 or NO is being generated. My > TEM sample had 10 ppm and 12 uS/cm conductance. > Every run I make I have the acutal conductance, the actual ppm, > the pH , the NO3 and is applicable the NO. I have data plotted > over 500 individal runs. I try every protocol someone generates. I didn't notice the ppm on the plot. Did I miss it? > I need to get your exact specs. and duplicate your process. > "Ole Bob" Just reduce the current so you get 100uA/sq. in. at the cathode. Your regulator won't handle it, so put a resistor in series to your power supply. It won't be perfect, but should work well enough to get an idea. I use 17 in of 12 ga folded into a "W", and get about 3.85" wetted. You might want to reduce the volume of dw to something like 500ml. It will take a very long time to have much effect with 2 gal. I'd take the sock off so you can see there is no black sludge produced. Maybe try a new cathode rod to make sure. Best Regards, Mike Monett -- The silver-list is a moderated forum for discussion of colloidal silver. Instructions for unsubscribing may be found at: http://silverlist.org To post, address your message to: [email protected] Silver-list archive: http://escribe.com/health/thesilverlist/index.html List maintainer: Mike Devour <[email protected]>
