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Peter P. Benac wrote:
[snip]
>
> And your domain is my Mother's Maiden Name :)
>
> Regards,
> Pete
Remind me who you bank with? ;-)
C.
- --
Craig McLeanhttp://fukka.co.uk
[EMAIL PROTECTED] Where the fun never starts
Power
Thank you Mouss and to everyone for answering my logic question. I
now understand this better than I ever thought possible.
Dan
On May 3, 2006, at 15:14, mouss wrote:
Dan wrote:
Is:
A && (B || C || D || E || F)
equivalent to?:
A && (!B && !C && !D && !E && !F)
No. The DeMorgan laws
Dan wrote:
Is:
A && (B || C || D || E || F)
equivalent to?:
A && (!B && !C && !D && !E && !F)
No. The DeMorgan laws are:
! ( A && B)= !A || !B
!(A || B) == !A && !B
so you _dispatch_ the '!' and replace || with && and conversely.
example:
if it is _not_ spam _and_
> Is:
>
> A && (B || C || D || E || F)
if TRUE OR TRUE
true if either is true
> equivalent to?:
>
> A && (!B && !C && !D && !E && !F)
if FALSE AND FALSE
true if both are false
So no, they aren't equivalent.
Loren
>...
>I believe that's a fundamental logic rule, so yes.
>
>A && B == ~A || ~B
>
>--Russell
Almost:
-- Not to confuse things with C's short ciruit operations
|
v
( A and B ) equals ( not ( ( not A ) or ( not B ) ) )
^
any(@criteria) = not all(not @criteria)
Consider
Lifeboat1-has-a-seat OR
Lifeboat2-has-a-seat OR
...
LifeboatN-has-a-seat
vs.
Lifeboat1-is-full AND
Lifeboat2-is-full AND
...
LifeboatN-is-full
Thanks for the examples Matt, time for some testing
Dan
Dan wrote:
> Wow,
>
> I must be confusing this with any/all is/isn't. In various software
> (mail scripts, iTunes smart playlists, etc):
>
> any IS IS IS IS
>
> equals
>
> all NOT NOT NOT NOT
Exactly backwards.
any(@criteria) = not all(not @criteria)
Consider
Lifeboat1-ha
Wow,
I must be confusing this with any/all is/isn't. In various software
(mail scripts, iTunes smart playlists, etc):
any IS IS IS IS
equals
all NOT NOT NOT NOT
Dan
On May 2, 2006, at 15:11, Matt Kettler wrote:
Russell Miller wrote:
On Tuesday 02 May 2006 14
Russell Miller wrote:
> On Tuesday 02 May 2006 14:59, Dan wrote:
>> Is:
>>
>> A && (B || C || D || E || F)
>>
>> equivalent to?:
>>
>> A && (!B && !C && !D && !E && !F)
No the two are NOT equivalent.
The first statement will be true if A and any one of B-F is true.
The second statement will be t
No!1
In the first example if A is postive and any one of the () variable are
positive it will pass.
In the second example A would have to be positive and all the () variable
would have to be negative to pass.
And your domain is my Mother's Maiden Name :)
Regards,
Pete
>
> Is:
>
> A && (B ||
On Tuesday 02 May 2006 14:59, Dan wrote:
> Is:
>
> A && (B || C || D || E || F)
>
> equivalent to?:
>
> A && (!B && !C && !D && !E && !F)
>
I believe that's a fundamental logic rule, so yes.
A && B == ~A || ~B
--Russell
> as in:
>
> meta __FORGED_OUTLOOK_DOLLARS (__OUTLOOK_DOLLARS_MUA && !
> __O
Is:
A && (B || C || D || E || F)
equivalent to?:
A && (!B && !C && !D && !E && !F)
as in:
meta __FORGED_OUTLOOK_DOLLARS (__OUTLOOK_DOLLARS_MUA && !
__OUTLOOK_DOLLARS_MSGID && !__OUTLOOK_DOLLARS_OTHER && !__IMS_MSGID
&& !__UNUSABLE_MSGID)
Thanks,
Dan
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