Thank you Mouss and to everyone for answering my logic question. I
now understand this better than I ever thought possible.
Dan
On May 3, 2006, at 15:14, mouss wrote:
Dan wrote:
Is:
A && (B || C || D || E || F)
equivalent to?:
A && (!B && !C && !D && !E && !F)
No. The DeMorgan laws are:
! ( A && B) = !A || !B
!(A || B) == !A && !B
so you _dispatch_ the '!' and replace || with && and conversely.
example:
if it is _not_ spam _and_ it is not virus, deliver it; else
quarantine it
is the same as
if it is _either_ spam _or_ virus, quarantine it. else deliver it
