On Tuesday 02 May 2006 14:59, Dan wrote: > Is: > > A && (B || C || D || E || F) > > equivalent to?: > > A && (!B && !C && !D && !E && !F) > I believe that's a fundamental logic rule, so yes.
A && B == ~A || ~B --Russell > as in: > > meta __FORGED_OUTLOOK_DOLLARS (__OUTLOOK_DOLLARS_MUA && ! > __OUTLOOK_DOLLARS_MSGID && !__OUTLOOK_DOLLARS_OTHER && !__IMS_MSGID > && !__UNUSABLE_MSGID) > > > Thanks, > Dan
