Hi Sydney,
This mailing list is a text-only list so your pictures are not coming
through.
I am guessing that you are clicking on the setup (installation) program and
not on R.
That would explain why you are being led to the installation process again.
You can try to search for another desktop icon
Another alternative is to use ggplot2 to create the various plots, then put
them into
a list and use cowplot::plot_grid to plot the grid of plots with a
specified number of
rows and columns. Here's some pseudo code to give you the general idea
Step 1: generate the plots and put them into a list
fo
Charles writes about saving execution time by eliminating redundancies.
If you see redundancies related to calling a time-consuming function
multiple times with the same arguments, a very easy way to speed up your
program is to memoise the functions using the package memoise.
HTH,
Eric
On Wed,
Hi Eman,
It helps if you create a small example that reproduces the problem and then
post the code with your question.
This will help people determine what is causing the problem.
Best,
Eric
On Mon, Feb 11, 2019 at 11:52 AM إيمان إسماعيل محمد <
emanismail...@gmail.com> wrote:
> I need to s
Hi Isaac,
I am sure you will get lots of answers to this. Here is one using the dplyr
package.
Assuming that your data frame is called 'a', then
library(dplyr)
b <- dplyr::group_by(a,plot) %>% dplyr::summarise( mean(lai) )
b
# A tibble: 4 x 2
plot `mean(lai)`
1 104243.
2 10
Hi Javad,
You have a number of problems with your code, such as:
1. you should set df1 and df2 without factors
2. you define a function f(x,y) but the body of the function never refers
to x and y
The following code does what I think you are looking for:
df1 = data.frame(x1 = letters[1:26],x2 = NA
You have some choices
fitchange$coefficients[2]
zz$coefficients[2,1]
Note that class(zz$coefficients) shows that it is a matrix.
HTH,
Eric
On Fri, Feb 22, 2019 at 9:45 AM Sorkin, John
wrote:
> I am trying to obtain the coefficients from a regression (performed using
> lm). I would like to
These two pathnames are different
/usr/lib/R/library/lib/later/later.so
/usr/lib/R/library/later.so
Was that your intention?
On Wed, Feb 27, 2019 at 11:45 PM Rich Shepard
wrote:
> On Wed, 27 Feb 2019, William Dunlap wrote:
>
> > Did you use 'R CMD ldd .../later.so', as I recommended?
>
> Bill
Hi John,
Is the subject line of your question correct? Ubuntu 10.04?
If that is not a typo, that could be contributing to your problem. I
believe that the current stable release of Ubuntu is 18.04.
According to the following link ubuntu 10.04 was released almost 10 years
ago and was "retired" about
"Is there any way ..."
Two quick answers:
1. using base R functions and data types the answer is 'no' - a double
(i.e. numeric) contains about 15 significant digits.
So 5.678e-100 is fine but 0.01 + 5.678e-100 will keep the
.0100 as the significant digits and "drop" the digits 80
Hi John,
dplyr::lag expects a vector. The following should work
dplyr::lag(temp[,1],2)
HTH,
Eric
On Mon, Mar 25, 2019 at 9:45 AM John wrote:
> Hi,
>
>I have a dataset whose row names corresponds to months. When I apply lag
> function (dplyr package) on this dataset, I get NAs with warning
Doing a web search on
R CRAN GJR GARCH
brought up the rugarch package. The models you mentioned are discussed in
the documentation to that package
https://cran.r-project.org/web/packages/rugarch/vignettes/Introduction_to_the_rugarch_package.pdf
On Mon, Mar 25, 2019 at 2:06 PM Amon kiregu wrot
You may be calling a function when you think you are referring to an array.
You can reproduce this error message as follows:
f <- function(x) {x}
f[1]
HTH,
Eric
On Mon, Apr 1, 2019 at 5:49 PM Simrit Rattan
wrote:
> hey everyone :),
> Subject: Re: Error message: object of type 'closure' is not
You might want to post this to the group R-Sig-Finance
https://stat.ethz.ch/mailman/listinfo/r-sig-finance
and also check their archives
On Wed, Apr 3, 2019 at 1:11 AM H wrote:
> I am relatively new to analyzing financial data but have some experience
> with R. I understand that the data avai
And just for fun, yet another way
> cumsum((1:200)*c(1,-1))
On Tue, Apr 9, 2019 at 9:51 PM David L Carlson wrote:
> Here's another approach:
>
> > x <- c(rbind(1:100, -(1:100)))
> > head(x); tail(x)
> [1] 1 -1 2 -2 3 -3
> [1] 98 -98 99 -99 100 -100
>
> ---
I don't have your data. Are the x-values the same in both plots?
Does this example cover the situation?
f1 <- function(x) { x^3 - 2 }
f2 <- function(x) { 2 - x^2 }
xV <- seq(from=0,to=2,length=50)
y1 <- f1(xV)
y2 <- f2(xV)
y3 <- .5*(y1+y2)
plot(x=xV,y=y1,col="blue",lwd=2,type='l',xlab="x",ylab="y
Hi,
I am not sure if the request is about a 'simple way' or requires
dplyr. Here's an approach without using dplyr that is just 2 lines
(not counting creating the data or outputting the result).
n <- 500
myDf <- data.frame( gender=sample(c("Man","Woman","Other"), n, replace = TRUE),
Hi Stefano,
If you mean from 9am on one day to 9am on the following day, you can
do a trick. Simply subtract 9hrs from each timestamp and then you want
midnight to midnight for these adjusted times, which you can get using
the method you followed.
I googled and found that lubridate::hours() can be
e R as.difftime function is perfectly usable to create this offset
> without pulling in lubridate.
>
> On September 21, 2020 8:06:51 AM PDT, Eric Berger
> wrote:
> >Hi Stefano,
> >If you mean from 9am on one day to 9am on the following day, you can
> >do a trick. S
Hi,
I tried running your code but it is not complete. When you create the xts
you refer to data$PRICE but this has never been defined.
I generated synthetic data and used that to create the xts object as
follows:
x <- runif( length(tm), min=90, max=110 )
data<-xts(x=x,order.by=tm)
When I used th
Hi Ablaye,
The CRAN repository has thousands of available R packages. To help
people find relevant packages amid such a huge collection, there are
some 'task view' pages that group packages according to a particular
task. I am guessing that you are interested in kernels because of
their use in mach
Do you make regular backups? If not, this should push you into such a
routine.
One approach is to use an external drive. External drives are not expensive
and can typically have plenty of room to hold all your code and data.
Just before having your computer serviced, copy your code and data onto th
Hi John,
I was thinking that you created df1 in a way that set the 'year'
column as a factor when this is not what you wanted to do.
The data.frame() function takes an argument stringsAsFactors which
controls this behavior.
For R versions 3.6.3 or earlier, the default setting is
stringsAsFactors=TR
Hi Rolf,
This is not addressing your implementation, but reformulates the goal.
Specifically, the covariance matrix is normally written as \Sigma (not
\sigma^2).
So to specify the upper left element you would write (in Latex)
\Sigma_{11}.
No superscript (so no problem!)
HTH,
Eric
On Wed, Dec 9,
As the error message says, move the '+' sign from the start of the second
line to the end of the preceding line.
On Sat, Dec 19, 2020 at 10:29 PM Rosato, Kyle wrote:
> For some simple reason, I am unable to see the mistake:
>
> ggplot(filter(nlsw88, !(is.na(union))), aes(y = wage, x = union, fi
Hi Ben,
A few comments:
1. you might want to also post this question to the more focused group
r-sig-finance
2. as Duncan writes, it would be helpful if you included some topics that
are not covered in the packages you mentioned
3. in my experience, the authors/maintainers of the packages you
Hi Ben,
Abby makes a good suggestion on Rmetrics, although it is no longer current
in CRAN.
The www.rmetrics.org site looks quite interesting (although not clear
whether there are any recent additions.)
The suggestion did bring to mind another excellent resource: quantlib - a
library for computat
zx<-strsplit("age,exercise,income,white,black,hispanic,base,somcol,grad,employed,unable,homeowner,married,divorced,widowed",",")
On Tue, Jan 5, 2021 at 11:01 AM Steven Yen wrote:
> Thank you, Jeff. IMO, we are all here to make R work better to suit our
> various needs. All I am asking is an ea
;nongov" "married"
>
> > x<-strsplit("hhsize,urban,male,
> + gov,nongov,married",","); x
> [[1]]
> [1] "hhsize""urban" "male"
> "\ngov"
> [5] &qu
sc"
> "tert"
> [9] "gov" "nongov" "married"
>
> > eq1<-my.formula(y="cig",x=x); eq1
> cig ~ hhsize + urban + male + age3045 + age4659 + age60 + highsc +
> tert + gov + nongov + married
> > eq2<-my.formula(y="c
Hi Sacha,
I never used these packages before but I installed them and tried your
code. I have a few observations that may help.
1. the statement
ypred = predict(fit18,newdata=Testing)
is wrong. Checkout the help page (?robustgam) which shows in the
Examples section at the bottom to use so
> fit18<-robustgam(x,y, sp=4356,family=true.family,smooth.basis='ps',K=3)
>
> ypred=pred.robustgam(fit18,data.frame(X=Testing))
> MSE = mean((y-ypred)^2)
> MSE
> lst[i]<-MSE
> }
> mean(unlist(lst))
>
>
>
>
for ( file in filelist )
On Wed, Jan 20, 2021 at 2:21 PM Miluji Sb wrote:
> Thank you for your reply and the solution. Yes, I would like the date to be
> the column header for all the files in the list.
>
> This is what tried following your suggestion;
>
> filelist = list.files(pattern = ".*.t
desired <- paste(site,depth,sep="")
On Wed, Feb 17, 2021 at 11:10 PM Parkhurst, David
wrote:
> If I have a vector of site abbreviations and a vector of depths in those
> water bodies, is there a simple way in R to combine them to make a third
> vector?
> Examples:
>
> sitedepth des
The str() function is your friend. Try
str(Output)
On Thu, Feb 25, 2021 at 12:09 PM David Winsemius
wrote:
>
> On 2/25/21 7:24 AM, Göran Djurfeldt wrote:
> > Help! I am going crazy for a very simple reason. I can’t access the
> output from for instance the lme4 package in R. I have been able to
Why not use standard matrix multiplication which is straightforward here:
x %*% diag(1/s)
HTH,
Eric
On Wed, Mar 3, 2021 at 7:13 AM Harold Doran <
harold.do...@cambiumassessment.com> wrote:
> To make sure the scalar is used instead of using the recycled vector s,
> maybe like this
>
> x <- matr
Untested
b1=boxcox( DV ~ IV1 + IV2, data= newdata, main="My main title\n My
Subtitle")
On Thu, Mar 4, 2021 at 11:56 AM DY Kim wrote:
> Greetings!
>
> I am currently using R x64 4.0.4.
>
> I used the box-cox power transformation to create a range of lambdas and
> log-likelihood values using th
Hi Carlos,
That is strange. The function read_csv is in the readr package.
You could try
library(readr)
readr::read_csv(etc)
Let us know what happens.
Eric
On Mon, Mar 8, 2021 at 3:57 PM Hasan Diwan wrote:
> function (file, col_names = TRUE, col_types = NULL, locale =
> default_locale(),
>
I have no familiarity with these packages but I did a search in CRAN on
api_create and found it is defined in the plotly package. I then confirmed
that the seurat package does reference plotly.
You might try installing the plotly package before trying to install seurat.
HTH,
Eric
On Sat, Mar 20
Try replacing
ggplot(ToothGrowth, ... )
with
ggplot(mydata,...)
HTH,
Eric
On Wed, Mar 31, 2021 at 12:20 PM Mahmood Naderan-Tahan <
mahmood.nade...@ugent.be> wrote:
> Hi
>
> I would like to use the violin plot as described in the manual [1]. In the
> example, I see
>
> ToothGrowth$dose <- as.fac
If your workflow involves debugging and rerunning the code, you may
experience differences between starting from a clean RStudio session and
simply restarting your application. This can be caused by your environment
having variables, shared objects etc defined. It is generally quite quick
to close
Hi Ani,
Before the for loops add the following line
when[,-1] <- when[,-1]%%12 + 1
This changes the month numbering so that Dec becomes 1, Jan becomes 2, etc
Then your for loop does what you want.
HTH,
Eric
On Wed, Apr 21, 2021 at 11:09 AM ani jaya wrote:
> Dear r community,
>
> I have a d
Hi Ramdas,
I have no idea what might be causing this but it would probably help those
who might be able to help if you supply additional information, such as the
output of sessionInfo() in an R session.
Also try to send your emails to the list in plain text (not HTML).
Good luck,
Eric
On Mon, Ma
If your data frame is named x then
y <- x[ x$id %in% c(1,2), ]
would create a new data frame y that has what you want.
On Mon, May 17, 2021 at 5:33 PM Admire Tarisirayi Chirume <
atchir...@gmail.com> wrote:
> Can someone help on how to filter my data frame below such that it retains
> a countr
Hi Victor,
This issue has been raised in earlier entries in this list. I have not dug
into it myself but the following link was posted as being helpful.
https://askubuntu.com/questions/1286545/what-commands-exactly-should-replace-the-deprecated-apt-key/1307181#1307181
HTH,
Eric
On Sat, May 22,
This is part of the R-4.1.0 release which came out a few days ago.
See
1. https://stat.ethz.ch/pipermail/r-announce/2021/000670.html
2.
https://www.jumpingrivers.com/blog/new-features-r410-pipe-anonymous-functions/
3.
https://community.rstudio.com/t/psa-r-4-1-0-release-requires-rstudio-preview/1052
Hi Roger,
I have no experience with Centos 8 but I checked that it is possible to run
docker on it.
You might consider creating an ubuntu docker image with all the R tools
that you need, and then run the image on the Centos 8 machine.
You can specify a mount so that your docker image, including its
Typo
num <- num + i
should be
num <- num + 1
On Sat, Jun 5, 2021 at 9:38 AM Hasan Diwan wrote:
> unlist(sapply(seq(1,100), function(n) { if(n %% 2) n })) yields:
>
> [1] 1 3 5 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45
> 47 49
> [26] 51 53 55 57 59 61 63 65 67 69 71 73 75 7
You are missing the second closing parenthesis. This is what the error
message is telling you.
On Wed, Jun 9, 2021 at 2:44 AM Jeff Reichman
wrote:
> R-Help Forum
>
>
>
> Anyone know why the following line of code would error out: myObject <-
> read_fst(unz("Dataset.zip", filename = "filename.f
It's also possible to save a character and gain the added advantage of
being less understandable :-)
num[!!num%%2]
On Wed, Jun 9, 2021 at 12:56 PM Martin Maechler
wrote:
> > David Carlsonon Sun, 6 Jun 2021 15:21:34 -0400 writes:
>
> > There is really no need for a loop:
> > num <- 1:1
;
> myObject <- read.csv(unz("C:/Users/reichmaj/Documents/My_Reference_Library
> /Regression /Dataset.zip", filename = "myFile.csv"))
>
>
>
> My only though is I can’t use the two function s together when dealing
> with fst files ??
>
>
>
> *From:* Eric B
Hi André,
It's not 100% clear to me what you are asking. I am interpreting the
question as selecting the data from those dates for which all of
1,2,3,4,5,6,7,8 appear in the ID column.
My approach determines the dates satisfying this property, which I put into
a vector dtV. Then I take the rows of
In my code, instead of 't', I name a vector of indices with a meaningful
name, such as idxV, to make it obvious.
Alternatively, a minor change in your style would be to replace your
definition of t by
t <- as.logical(c(1,1,1,0,0))
HTH,
Eric
On Wed, Jun 23, 2021 at 6:11 PM Phillips Rogfield
wr
If no one comes up with a better suggestion:
a. Change the column name to "Y" so that you get the plot you want
b. Use axis labels and legend text to show the text that you want. (The
user never has to know that you changed the column name 😃)
HTH,
Eric
On Wed, Jun 23, 2021 at 9:58 PM Mahmood Nade
> ??'%du%'
shows it is in the igraph package (disjoint union)
On Wed, Jun 30, 2021 at 1:03 PM Federico Calboli <
federico.calb...@kuleuven.be> wrote:
> Hello All,
>
> I am playing with igraph (which seems to work for what I have used it).
> Nevetheless:
>
> demo('community', package="igraph")
You can do the same steps but without so much intermediate saving to
shorten it
f <- function(x) {
do.call(rbind,lapply(1:nrow(x),
function(r) {paste(x[r,], collapse="_")}))
}
df_combo <- cbind(df,Combo=f(df[,c(4,2)]))
HTH,
Eric
On Thu, Jul 1, 2021 at 5:37 PM Micha Sil
Lovely one-liner Bert. Chapeau
On Thu, Jul 1, 2021 at 10:16 PM Berry, Charles
wrote:
>
>
> > On Jul 1, 2021, at 11:24 AM, Bert Gunter wrote:
> >
> > Why not simply:
> >
> > ## reprex
> > set.seed(123)
> > df = data.frame("A"=sample(letters, 10), "B"=sample(letters, 10),
> >"C"=s
Modify the summ() function to start like this
summ <- function(Tabname){
query <- sprintf(" SELECT * FROM %s",Tabname)
res <- dbGetQuery(con, query)
etc
HTH,
Eric
On Fri, Jul 2, 2021 at 9:39 PM Kai Yang via R-help
wrote:
> Hello List,
>
> The previous post look massy. I repost my questio
ot;GEMD.DISC_SESSION_TYPE", "GEMD.DISCREPANCIES",
> "GEMD.DISCREPANCY_QUERY_TEMP", "GEMD.DISCRETE_VALUES",
> "GEMD.ENTERED_DATA_ENTRY_PAGES", "GEMD.ENTRY_GROUPS",
> "GEMD.ExportSampleListNames", "GEMD.FORM_STATUS_BY_SUBJEC
200+ times of the script
> to summary each table. So, I'm trying to write the function to do this.
> this is my goal.
>
>
> First of all, I'm not sure if this is the right way to do the summary
> report, because I'm a new R user. So please correct me if my idea is
Hi Laurent,
I am not sure how to get apply() to work but the following uses lapply()
and returns the matrices in a list.
lapply(1:3, FUN = function(i) diag( svd(x[i,,])$d ))
HTH,
Eric
On Mon, Jul 5, 2021 at 5:56 PM Laurent Rhelp wrote:
> Dear R-Help,
>
> I have an array x made up of three mat
Hi Evan,
I assume you know how to get the data into a data frame (e.g. via read.csv).
Here I will create the example data explicitly, creating a data frame x.
x <- data.frame( label=c("ABC","DDG","ABB"), count=c(3,5,2) )
Then create a character vector with the data as you want it.
y <- unlist(sa
much nicer
On Wed, Jul 7, 2021 at 10:58 AM Ivan Krylov wrote:
> On Tue, 6 Jul 2021 09:27:20 -0400
> Evan Cooch wrote:
>
> > I was wondering if there was an elegant/simple way to do this?
>
> rep(label, times = count) should give you a character vector with the
> answer ready for writeLines().
>
it complained about ASSAY_DEFINITIONS not about RESPONDENTS.
Can you try with the ASSAY_DEFINITIONS file?
On Fri, Jul 9, 2021 at 9:10 PM Kai Yang via R-help
wrote:
> Hello List,
> I use for loop to read csv difference file into data frame rr. The data
> frame rr will be deleted after a comp
This error can result from v with NAs.
e.g. to reproduce the error message
> v <- as.numeric(NA)
> if (is.numeric(v) && any(v < 0)) cat("hello world\n")
see also
https://stackoverflow.com/questions/7355187/error-in-if-while-condition-missing-value-where-true-false-needed
HTH,
Eric
[[al
While the base R solution using 'factor' appears to win based on elegance,
chapeau to the creativity of the other suggestions.
For those who are not aware, R 4.1.0 introduced two features: (1) native
pipe |> and (2) new shorter syntax for anonymous functions.
Erich's suggestion used the native pipe
Alternatively with base graphics
N <- 500 ## number of points (arbitrary)
degrees <- seq(from=0,to=180,length=N)
degreesToRadians <- function(d) { pi * d / 180.0} ## vectorIzed!
plot(x=degrees,y=sin(degreesToRadians(degrees)),type='l',
xlab="x",ylab="sin(x)",main="sin(x) vs x\nx is in degree
Hi,
I was able to reproduce this problem on R 4.0.3 on Ubuntu 20.04.
I removed the CRAN sos package and installed the github version per
Spencer's advice.
After that it worked fine.
Eric
On Sat, Aug 7, 2021 at 1:50 PM Rui Barradas wrote:
> Hello,
>
> R 4.1.0 on Ubuntu 20.04.
> I cannot reprodu
Hi Luigi,
I would take a slightly different approach. Maybe this is helpful.
idV <- grep("var[123]",colnames(df))
df[,idV][df[,idV]=="a"] <- "z"
df
var1 var2 var3 var4 var5
1zAz1 light
2bBb4 light
3cCc9 heavy
4zDz 16 heavy
5b
In that case, another interesting test would be to check whether the
problem exists when you don't use doParallel().
On Thu, Aug 19, 2021 at 2:28 PM Shah Alam wrote:
>
> Dear All,
>
> Thanks a lot for your valuable suggestions. I am going to implement one by
> one.
>
> Jan:
>
> Yes, I am using t
x %>% transmute( a=pmin(Source,Target), b=pmax(Source,Target)) %>%
unique() %>% rename(Source=a, Target=b)
On Fri, Aug 20, 2021 at 2:12 PM Greg Minshall wrote:
> Kimmo,
>
> i'll be curious to see other, maybe more elegant, answers. in the
> meantime, this seems to work.
>
>
> x = dat
Nice Rui.
Here's a version in base R with no apply().
unique(data.frame(V1=pmin(x$Source,x$Target), V2=pmax(x$Source,x$Target)))
On Fri, Aug 20, 2021 at 6:43 PM Rui Barradas wrote:
> Hello,
>
> This seems elegant to me but it's also the slowest, courtesy sort.
>
> apply(x, 1, sort) |> t() |> un
One approach would be to put some (non-confidential) projects on a site such as
GitHub so that people can examine your work.
Sent from my iPhone
> On 27 Aug 2021, at 9:18, akshay kulkarni wrote:
>
> dear members,
>I am a stock trader and a data science freelancer.
As Achim wrote in point (2), Makefile is your friend.
On Sat, Aug 28, 2021 at 12:39 PM Rolf Turner
wrote:
>
> On Sat, 28 Aug 2021 09:47:03 +0200
> Achim Zeileis wrote:
>
> > On Sat, 28 Aug 2021, Rolf Turner wrote:
> >
> > > I have found that tools::texi2pf() ignores changes to the *.bib file
>
Hi Rich,
Your request is a bit open-ended but here's a suggestion that might help
get you an answer.
Provide dummy data (e.g. 5-10 lines), say like the contents of a csv file,
and calculate by hand what you'd like to see in the plot. (And describe
what the plot would look like.)
It sounds like what
You might also try asking the author directly if he knows of any
implementations of his procedures.
I searched online and found his website at:
https://www.unic.ac.cy/pouloukas-stavros/
You can also find his email there.
On Mon, Aug 30, 2021 at 12:29 PM AbouEl-Makarim Aboueissa <
abouelmakarim1..
Thanks Greg!
On Tue, Aug 31, 2021 at 1:49 PM Greg Minshall wrote:
> by the way, and "fwiw", the emacs org mode community seems to like using
> latexmk for moving latex files towards .pdf'ishness:
>
> https://mg.readthedocs.io/latexmk.html
>
> cheers, Greg
>
> ___
Instructions can be found at https://github.com/kloke/npsm
On Wed, Sep 1, 2021 at 6:27 PM wrote:
> I need to install the package "npsm" to follow Kloke & McKean book.
> However,
> npsm is no longer on CRAN. So, please let me know in detail how to proceed
> to install it.
>
>
>
> Thanks.
>
>
>
>
This code is not correct:
disc_by_month %>%
group_by(year, month) %>%
summarize(disc_by_month, vol = mean(cfs, na.rm = TRUE))
It should be:
disc %>% group_by(year,month) %>% summarize(vol=mean(cfs,na.rm=TRUE)
On Tue, Sep 14, 2021 at 12:51 AM Rich Shepard
wrote:
> On Mon, 13 Sep 2
Before you create vel_by_month you can check vel for NAs and NaNs by
sum(is.na(vel))
sum(unlist(lapply(vel,is.nan)))
HTH,
Eric
On Tue, Sep 14, 2021 at 6:21 PM Rich Shepard
wrote:
> The data file begins this way:
> year,month,day,hour,min,fps
> 2016,03,03,12,00,1.74
> 2016,03,03,12,10,1.75
> 2
ch Shepard wrote:
>
> On Tue, 14 Sep 2021, Eric Berger wrote:
>
> > Before you create vel_by_month you can check vel for NAs and NaNs by
> >
> > sum(is.na(vel))
> > sum(unlist(lapply(vel,is.nan)))
>
> Eric,
>
> There should not be any missing values in
You are getting this because you asked for the contents of a row that
is beyond the number of rows in your data frame.
On Thu, Sep 16, 2021 at 5:12 PM Ana Marija wrote:
>
> Hi All,
>
> I have lines in file that look like this:
>
> > df[14509227,]
> SNP A1 A2 freq b se p N
> 1: NA
Alternatively you can modify the test as follows:
length(unique(df_b$q)) == 1
On Thu, Sep 30, 2021 at 7:22 PM Bert Gunter wrote:
> I haven't followed this thread closely, but to your question I think
> maybe this is what you want"
>
> > z <- c("","")
> > all(z == "")
> [1] TRUE
> > z <- c("a"
Hi Anne,
It would be helpful to include at least part of behavioral_df for people to
understand the issue better.
Please do the following in R and post the output.
dput( head( behavioral_df) )
Also, set your email to plain text as HTML is stripped from emails on this
list.
Best,
Eric
On Tue,
df[(df$Y>0.2) & (df$X<10),][2,]
On Thu, Oct 14, 2021 at 10:52 AM Luigi Marongiu
wrote:
> Hello,
> I have selected a subset of a dataframe with the vector syntax (if
> this is the name):
> ```
> > df[(df$Y>0.2) & (df$X<10),]
> YX
> 10 0.2200642 1.591589
> 13 0.2941828 1.48595
As Duncan notes, it is easy to get the current implementation. Just type
the function name at the prompt:
> intersect
{
y <- as.vector(y)
unique(y[match(as.vector(x), y, 0L)])
}
On Sun, Oct 17, 2021 at 12:49 PM Duncan Murdoch
wrote:
> On 15/10/2021 4:31 p.m., petr smirnov wrote:
> > Hi
You can check out Wikipedia for regular expressions:
https://en.wikipedia.org/wiki/Regular_expression
On Fri, Oct 22, 2021 at 3:48 PM Steven Yen wrote:
> Thanks, it works!
>
> What can I read to understand more about this part "\\..*$" of the
> pattern? And more such as ^ and $ that I know f
Hi Lampros,
I cannot answer your question but I believe the correct place to post
such a question would be the r-package-devel list
https://stat.ethz.ch/mailman/listinfo/r-package-devel
Good luck
On Fri, Oct 22, 2021 at 2:13 PM lampros mouselimis
wrote:
>
> Dear R-help team,
>
> I'm the mainta
The tibble shows the 'date' column as type date but you are comparing
io a string.
Perhaps replace that piece by
date == as.Date("2021-10-23")
Not tested.
HTH,
Eric
On Mon, Oct 25, 2021 at 2:26 PM Dr Eberhard W Lisse wrote:
>
> Hi,
>
> I have data from JHU via the 'coronavirus' package which ha
I think a Cheat Sheet that gives a side-by-side comparison of numpy
and R would be relevant here.
I found something like that for pandas and R (link below), but not for numpy.
https://github.com/yl3738/Python-vs.-R-Cheatsheet/blob/main/community%20contribution_CC%20group14.pdf
On Thu, Oct 28, 20
I have no experience with this but I did a search and found the following
which looks close to what you are looking for
https://stackoverflow.com/questions/69755844/is-it-possible-to-draw-the-following-diagram-in-r
On Mon, Nov 1, 2021 at 5:06 PM bharat rawlley via R-help <
r-help@r-project.org>
> R.oo::charToInt(x)
# [1] 97 98 99
On Mon, Nov 1, 2021 at 9:48 PM Alice wrote:
>
> Dear members,
>
> How to translate the charter to the underline inter?
> I tried this:
>
> > x <- c("a","b","c")
>
> > as.numeric(x)
>
> [1] NA NA NA
>
> Warning message:
>
> NAs introduced by coercion
>
>
> It
x[ x > 2]
On Mon, Nov 1, 2021 at 9:49 PM Alice wrote:
>
> How to slice the array with the condition?
> For example, in perl I can get the elements greater than 2.
>
> $ perl -le '@x=(1,2,3,4,5);@y=grep {$_>2} @x;print "@y"'
>
> 3 4 5
>
>
> in R I know which(x>2), but it will return the indexes in
Hi Olga,
There are many people reading this list who are happy to try to help.
Please provide some additional information about what you are trying
to do and where you are stuck.
Good luck,
Eric
On Mon, Nov 1, 2021 at 9:49 PM Olga Pervushina
wrote:
>
>
> Dear Sir/Madam,
>
> I am working on a sta
One choice is
new.env(hash=TRUE)
in the base package
On Tue, Nov 2, 2021 at 11:48 AM Yonghua Peng wrote:
> I know this is a newbie question. But how do I implement the hash structure
> which is available in other languages (in python it's dict)?
>
> I know there is the list, but list's names c
Hi Stephen,
Does the problem still occur if you connect remotely to your computer from
a different computer?
e.g. via remote desktop?
On Wed, Nov 17, 2021 at 6:50 PM Stephen Hartley <
stephen.hartley@gmail.com> wrote:
> So I've got an odd problem that I can't seem to nail down, and I'm not
>
k (coincidental timing). So I doubt this is pertinent but
>> thought I should mention it just in case.
>>
>>
>>
>> Sent from Mail for Windows
>>
>>
>>
>> From: Eric Berger
>> Sent: Wednesday, November 17, 2021 1:04 PM
>> To: Stephe
Hi Philip,
This is a recurring question and there are many ways to do this.
My preference is to use the lubridate package.
library(lubridate)
a <- "15/01/2010"
b <- dmy(a)
b
# "2010-01-15"
class(b)
# [1] "Date"
HTH,
Eric
On Sat, Nov 20, 2021 at 7:09 PM Philip Monk wrote:
> Hello,
>
> Simple b
Hi Thomas,
I could not reproduce your problem. Both examples worked fine for me.
Here is my setup:
R version 4.1.2 (2021-11-01)
Platform: x86_64-pc-linux-gnu (64-bit)
Running under: Ubuntu 20.04.3 LTS
Matrix products: default
BLAS: /usr/lib/x86_64-linux-gnu/openblas-pthread/libblas.so.3
LAPACK
Hi Kai,
Check out https://www.bioconductor.org
or the help there at
https://www.bioconductor.org/help/
You can also post your question there.
Best,
Eric
On Fri, Dec 3, 2021 at 2:22 AM Kai Yang via R-help
wrote:
> Hello R team,we have a huge SOMAscan data set. This is an aptamer-based
> protec
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