Hi André,
It's not 100% clear to me what you are asking. I am interpreting the
question as selecting the data from those dates for which all of
1,2,3,4,5,6,7,8 appear in the ID column.
My approach determines the dates satisfying this property, which I put into
a vector dtV. Then I take the rows of A for which the date is in the vector
dtV.
library(dplyr)
dtV <- A %>% mutate(x=2^(ID-1)) %>% group_by(Date) %>%
summarise(y=(sum(unique(x))%%256==255)) %>% filter(y==TRUE) %>% select(Date)
B <- A[ A$Date %in% dtV$Date, ]
B is the subset of A that you want.
HTH,
Eric
On Mon, Jun 21, 2021 at 10:23 AM André Luis Neves <andrl...@ualberta.ca>
wrote:
> Dear R users,
>
> I want to select only the data containing a continuous number of *ID* from
> 1-8 in each *DATE*. Note, I do not want to select data that do not contain
> a continuous number in *ID *from 1-8 (eg. Data on *DATE* 1/2/2020, and
> 01/03/2020). The dataset is a huge matrix with 24 columns and 1.5 million
> rows, but I have prepared a reproducible code for your reference below.
>
> Here it is the reproducible code:
>
> A =
>
> data.frame(c("01/01/2020","01/01/2020","01/01/2020","01/01/2020","01/01/2020","01/01/2020","01/01/2020",
>
>
>
> "01/01/2020","01/01/2020","01/01/2020","01/01/2020","01/01/2020","01/02/2020","01/02/2020",
>
>
>
> "01/02/2020","01/02/2020","01/03/2020","01/03/2020","01/03/2020","01/03/2020","01/03/2020",
>
>
>
> "01/03/2020","01/03/2020","01/04/2020","01/04/2020","01/04/2020","01/04/2020","01/04/2020",
> "01/04/2020","01/04/2020","01/04/2020","01/04/2020"),
> c(23,22,12,24,26,19,34,15,17,19,23,33,
>
> 23,34,25,23,25,24,34,33,31,32,24,22,21,23,22,22,21,23,23,21),
> c(13,11,12,9,8,9,7,10,11,9,6,11,
> 9,8,9,10,11,12,9,8,10,4,6,9,8,9,10,11,14,12,13,11),
> c(1,2,3,4,5,6,7,8,9,10,11,12,1,2,3,4,1,2,
> 3,4,5,6,7,1,2,3,4,5,6,7,8,9))
> colnames(A) <- c("Date", "CO2", "CH4", "ID")
> A
>
> Thank you,
> --
> Andre
>
> [[alternative HTML version deleted]]
>
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