thanks a lot.
I also found that using "stringsAsFactors=FALSE" helps
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Hi,
Each > help.start() generates a new tree of the R help system, somewhere
in 127.0.0.1:xxx, each xxx being difeerent. This tree disappears when
exiting R. How can the current help tree copied to a permanent place for
reference outside a running R? This would be practical for not having to
Two issues, one was that i just wanted to do some calculation and then save it
without having to load the rest again beforehand and have to delete variables
in my working environment so they don't get saved as well. The second was the
issue that i'd like to have most of the data in one big file,
Dear r-users,
I would like to convert my Matlab code to R-code, however it dies not work as
expected. Hope somebody can help me to match Matlab and r codes.
R code:
rr <- function(r,cxn)
{
tol <- 1E-4;
for(i in 1:n)
{
t1 <- (1+(i-1)*r)*log((1+(i-1)*r))
t2 <- (i-1)*(1-r)*log(1-r)
rri <- ((t1+t
Please do your work to form a well-posed (context including!) question,
like I've asked before.
On Monday, October 22, 2012, sheenmaria wrote:
> Sir,
> This code give the answer but i have a doubt,
> i need to retrieve the data of more than one tickers so i used the code
> like this
>
> v=c(
With NetCDF I would recommend working on understanding your data in a
more native way. Both rgdal and raster put their own take (via ncdf
and GDAL respectively) on how the data are to be interpreted. Both are
limited in the GIS way of requiring regular grids and a set of 2D
layers, rather than mor
Hello Vignesh, we did not get any attachments, maybe you could upload them
somewhere?
On 19.10.2012, at 09:46, Vignesh Prajapati wrote:
> As I found the memory problem with local machine/micro instance(amazon) for
> building SVM model in R on large dataset(2,01,478 rows with 11 variables),
> the
On Monday, October 22, 2012, nymphita wrote:
> Hello all,
> I'm trying to group several consecutives rows (and assigning them the same
> value) while leaving some of the rows empty (when a certain condition is
> not
> fulfilled).
>
> My data are locations (xy coordinates), the date/time at which t
On Monday, October 22, 2012, Christian Hoffmann wrote:
> Hi,
>
> Each > help.start() generates a new tree of the R help system, somewhere
> in 127.0.0.1:xxx, each xxx being difeerent. This tree disappears when
> exiting R. How can the current help tree copied to a permanent place for
> reference o
Perfect, thanks
-Original Message-
From: Rui Barradas [mailto:ruipbarra...@sapo.pt]
Sent: Wednesday, October 17, 2012 9:49 PM
To: Pancho Mulongeni
Cc: r-help@r-project.org
Subject: Re: [R] Setting all rows of a certain level to NA in a factor
Hello,
Try the following.
b <- factor(ife
thank you very much
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On 22-10-2012, at 09:49, Roslina Zakaria wrote:
> Dear r-users,
>
> I would like to convert my Matlab code to R-code, however it dies not work as
> expected. Hope somebody can help me to match Matlab and r codes.
>
> R code:
>
> rr <- function(r,cxn)
> {
> tol <- 1E-4;
>
> for(i in 1:n)
> {
On 22-10-2012, at 06:39, nymphita wrote:
> Hello all,
> I'm trying to group several consecutives rows (and assigning them the same
> value) while leaving some of the rows empty (when a certain condition is not
> fulfilled).
>
> My data are locations (xy coordinates), the date/time at which they
Hi
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of David Arnold
> Sent: Monday, October 22, 2012 4:26 AM
> To: r-help@r-project.org
> Subject: [R] Margin annotation
>
> I have this code:
>
> x=seq(80-3*15,80+3*15,length=200)
Hi
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of asafwe
> Sent: Monday, October 22, 2012 4:02 AM
> To: r-help@r-project.org
> Subject: [R] Counting duplicates in a dataframe
>
> Hello,
>
> I am looking at a two-way ANOVA d
Hi
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of noobmin
> Sent: Monday, October 22, 2012 2:28 AM
> To: r-help@r-project.org
> Subject: [R] How to use tapply with more than one variables grouped
>
> I'm studying alone the R
You can run dynamic panel data models with plm -see the package's vignette
"Panel Data Econometrics in R: The plm Package" by Yves Croissant and Giovanni
Millo (section 5.4)
Check Giovanni Petris, Sonia Petrone, Patrizia Campagnoli's monograph "Dynamic
Linear Models with R" as well.
Hope this he
On 10/22/2012 06:24 PM, Christian Hoffmann wrote:
Hi,
Each > help.start() generates a new tree of the R help system, somewhere
in 127.0.0.1:xxx, each xxx being difeerent. This tree disappears when
exiting R. How can the current help tree copied to a permanent place for
reference outside a runnin
Dear All,
Anybody know if *4253H twice filter* is implemented in R?
*Description of filter:* Applies a series of running medians of varying
window size and a weighted average filter, with re-roughing, to the NDVI
time series
*Reference*: Velleman, P. (1980). Definition and comparison of robust
no
Have a look at
library(sos)
findFn("twice filter")
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie & Kwaliteitszorg / team Biometrics & Quality Assurance
Kliniekstraat 25
1070 Anderlecht
Belgium
+ 32 2 525 02 51
+ 32 54 43 61
Dear R-User,
I met the problem to test equality of variance.
Two sample units:
conjps<-c(9.41,10.45,10.78,10.73,11.11,11.12,11.59,11.04,11.63)
ms<-c(4.11,5.10,5.70,6.46,6.04,6.16, 6.24,6.32,7.33)
Then I use the F test to test:
Test Equality
of
Two Variances
F
test to compare two variance
Hello! I would like to make a scatterplot of my data, but the problem is that
several points have the same x and y values and are represented as only one
point. I wonder if there is a way to represent the data points, but with
point size representing the frequency of the depicted x-y value?
Thank
Hi all,
I'm planning to work through the book "Analyzing Linguistic Data" by
R.H. Baayen, which is an introduction to R used for, well, what the
title says. ;-) On the first page of the book, Baayen says that in order
to work with the book, R needs to download and install a number of
packages from
Hello everyone,
I am developing a web application and I would like to perform two kind of
statistical/modeling operations.
(1) Batch analysis from data stored in the backend of my app (HBase
cluster). Typically, this operation needs to be performed on regular basis,
say every night. The size of
Hi
I was trying to implement Egarch (1,1) with Student t distribution using
rugarch. But I was not getting any value.
Following were the commands that I was using:
library(rugarch)
spec=ugarchspec(variance.model=list(model="eGARCH", garchOrder=c(1,1)),
mean.model=list(armaOrder=c(1,1), arfima=FA
Hi,
I have a problem about the Latin letters in R. I try to get data from
facebook to oracle and while R is reading the data, it cannot write some
letters like "ü,Å,Ä" etc and just mark as "?". I know these are the Latin
letters and R cannot read it but is there any tool or function to convert
t
interTable <-data.frame (Tapply ($ contb_receipt_amt date, list ($ cand_nm
date, $ contbr_st date), sum))
I got create a table with the sum total contribution (contb_receipt_amt) of
each presidential candidate (cand_nm) in each state (contbr_st). How could
from interTable create a table of states
Hello,
I am a new user of R and Linux (debian squeeze), and I am trying to install
the ncdf library.
First I don't know wich is the best to use (ncdf or ncdf4), But not matter
the one I tried to install, it always failled.
I try to find a solution to this common problem on the web, but I never fin
Hi,
Is there any Unicode Support for JSON that helps to read Latin letters?
Thanks
[[alternative HTML version deleted]]
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PLEASE do read the posting guide http://www
Thanks, that has worked like a dream!
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htt
This is perilously close to a straightforward homework question which is not
usually answwered here but you get brownie points for saying you are a student.
Also you did not follow the posting guidelines so we have no idea what are
doing, what package(s) you may be using etc. Have a look at
Hi, I am trying to remove a series of records from a large dataframe. The
script I have written works fine but takes a long time to run. Can anyone
suggest a quicker way to do this?
Here is an example of the code I've written. The end result of this bit of
code would be a dataframe with any record
On 12-10-22 3:24 AM, Christian Hoffmann wrote:
Hi,
Each > help.start() generates a new tree of the R help system, somewhere
in 127.0.0.1:xxx, each xxx being difeerent. This tree disappears when
exiting R. How can the current help tree copied to a permanent place for
reference outside a running R
Sent from my iPhone
Begin forwarded message:
> From: Michael Muratet
> Date: October 21, 2012 12:08:55 PM CDT
> To: r-help@r-project.org
> Subject: Navigating a grid.
>
> Greetings
>
> I am trying to make a multiple panel plot from a tool (genoPlotR) that is
> layered on grid. My code and s
Hello,
If I understand it well,
idx <- !dat$id %in% bad$id
dat[idx, ]
Also, to create bad you are complicating, this would do:
bad <- data.frame(id = c(1,4))
Hope this helps,
Rui Barradas
Em 22-10-2012 12:04, penguins escreveu:
Hi, I am trying to remove a series of records from a large dat
Not in ggplot2 as far as I know. As Jim Lemon says the plotrix package should
handle this.
An alternative that probably gives better data interpretation might be to use
facet.grid() or perhaps facet_wrap() in ggplot2.
Crude example
library(ggplot2)
xx <- data.frame(aa = c(10, 12, 15, 55,
Therneau doesn't know the answer either.
The predictions are positively correlated since they all depend on the same beta-hat from
the original model. The same will be true for any model: logistic, poisson, linear, ...
Terry T
On 10/20/2012 06:06 PM, Omar De la Cruz C. wrote:
I have a follow
You need to install netcdf, including its development files. The notes
you quote are pretty specific about that. Googling for that leads to
http://packages.debian.org/source/squeeze/netcdf
and it seems you need libnetcdf-dev and libnetcdf6 installed.
On 22/10/2012 11:39, claire1234 wrote:
H
Design has been superceeded by rms -- give that a shot.
Cheers,
Michael
On Mon, Oct 22, 2012 at 10:51 AM, Joost Kremers
wrote:
> Hi all,
>
> I'm planning to work through the book "Analyzing Linguistic Data" by
> R.H. Baayen, which is an introduction to R used for, well, what the
> title says. ;-
Hi Tammy,
I'm afraid this is pretty obviously homework, so we can't really do
much to help you. It's not a personal thing: just the considered
opinion of this list to believe that giving you answers (or even hefty
hints) may undermine whatever intent your teacher has in assigning the
problem. Ther
I think it's more generally encouraged to "jitter" the points in this
circumstance.
RMW
On Mon, Oct 22, 2012 at 9:34 AM, swertie wrote:
> Hello! I would like to make a scatterplot of my data, but the problem is that
> several points have the same x and y values and are represented as only one
>
Shortly ago I did something similar to what you intend to.
The data frame was called 'fore'. There were eight different variables and I
wanted to plot each one by column, and depict the frequencies in terms of the
size of the dots. The problem I ran into is that the plots got extremely big
for
Hello all,
Please review the following simple code:
# make a factor:
x <- factor(c("one", "two"))
# what should be the output to the following expression?
c(x, "3")# <===
# I expected it to be as the output of:
c(as.character(x), "3")
# But in fact, the output is wh
Hi
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of noobmin
> Sent: Monday, October 22, 2012 12:31 PM
> To: r-help@r-project.org
> Subject: Re: [R] How to use tapply with more than one variables grouped
>
> interTable <-data.
Tal:
There was a recent discussion on this list about this (Sam Steingold
was the OP IIRC).
The issue is ?c . In particular:
"c is sometimes used for its side effect of removing attributes except
names, for example to turn an array into a vector."
Hence, the factor attribute is removed and you
Inline.
On Mon, Oct 22, 2012 at 6:55 AM, PIKAL Petr wrote:
> Hi
>
>
>> -Original Message-
>> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
>> project.org] On Behalf Of noobmin
>> Sent: Monday, October 22, 2012 12:31 PM
>> To: r-help@r-project.org
>> Subject: Re: [R] How to
Hi
> -Original Message-
> From: Bert Gunter [mailto:gunter.ber...@gene.com]
> Sent: Monday, October 22, 2012 4:00 PM
> To: PIKAL Petr
> Cc: noobmin; r-help@r-project.org
> Subject: Re: [R] How to use tapply with more than one variables grouped
>
> Inline.
>
> On Mon, Oct 22, 2012 at 6:55
Hi,
In the FAQ for Mac http://cran.r-project.org/bin/macosx/RMacOSX-FAQ.html
there is
7.2 Saving the image
You can can (???) the content of the quartz device window into a PDF file.
This is not explained!
This is a very simple way to export high quality graphics from R into
other applications
Hi all,
I'm trying to create a function where it can process a vector and also give
a vector output accordingly
#input: a,b anc c are constants, data is the vector
#set the function
fun<-function(a,b,c,data)
{
N=as.vector()
for (i in min(data):max(data)){
if(i>c){
N<-(a*(i-c)^0.5)+(b*(i-c))}
else
N=as.vector()
This doesn't mean anything in R: you can read the help using
?as.vector
to see what the required arguments are.
Do you want to loop over the elements of data? That's not what your
loop is doing. Instead it is looping over each element of the sequence
from the min to the max *value*
Dear Dr. Murrell
Sorry to bother you at home, so to speak, but my emails to r-help@r-project.org
are falling into the void.
I am trying to make a multiple panel plot with 26 rows and 2 columns
with plots from a tool (genoPlotR) that is layered on grid. My code
and session info are below.
Thank you very much for your answer; my Gooogleing was not good engouh.
Claire
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Hello, I have the following sample dataset.
sex <- as.factor(c(rep(0,12),rep(1,12)))
char <-
c("x","x","x","x","y","y","y","y","z","z","z","z","x","x","x","x","y","y","y","y","z","z","z","z")
a <- runif(24,0,2)
b <- runif(24,4,10)
data <- data.frame(cbind(sex,char,a,b))
I would like to generate a
I haven't determined the root cause of the numerical accuracy bug yet (I
haven't determined a way to compare the values used when the code is run
from R as opposed to from a Fortran test), but I did have another issue with
retrieving the matrix from the Fortran code that I hoped you might be able
t
Hello everyone,
I have been trying to perform a Friedman test for a while with no success.
I have tried the command: > friedman.test (y~A|B, data = mydata), but it
doesn't work .
I searched youtube for help, but still could not find much. Can anyone help
me with that!
Thank you very much,
Pedro
Dear Simon & R-Users.I have applied your solution also for larger buffer
window,and it's working well.
But I'm getting the problem harder.I have two vectors: x<-
c(0,0,0,0,1,0,0,0,0,1,0,0,0) y<- c(0,-10,0,-10,0,0,0,0,-10,0,0,0,0)
And I want to know where the value -1 in x have at least 2 values
On Mon, Oct 22 2012, R. Michael Weylandt wrote:
> Design has been superceeded by rms -- give that a shot.
I know, but it doesn't look like it's a dorp-in replacement for Design,
so I suspect the code in the book won't work with it...
Joost
> On Mon, Oct 22, 2012 at 10:51 AM, Joost Kremers
>
I want to connect R with HTML/PHP pages to take input from user,do some
statistical processing on it & show results to HTML page again.
I search on net,i got Rserve package,but examples are mainly for java
langaure & not for PHP
i am wondering how to connect it to PHP-Apache-MySQL
Is there any g
Hi,
You can also use ?merge()
dat$ind_dat<-TRUE
bad$ind_bad<-TRUE
res<-merge(dat,bad,all=TRUE)
res1<-res[is.na(res$ind_bad),][,1:3]
res1
# id year age
#5 2 2 Adult
#6 2 2
#7 2 3
#8 2 2
#9 2 2 Adult
#10 3 2
#11 3 3 Adult
#12 3 4
A.K.
- Ori
Hi,
try this:
dat1<-read.table(text="
Observation Gender Dosage Alertness
1 1 m a 8
2 2 m a 12
3 3 m a 13
4 4 m a 12
5 5 m b 6
6 6 m b
Thank you very much. I managed to do it with a similar approach and it looks
like what I expected.
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Thank you for your comment. I would be very interested, but I did not know
about jitter. Would you have a small example?
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Rui,
Thanks a lot for your help. Unfortunately this doesn't work though:
1> is.border <- function(idx, DF){
1+ i1 <- DF$ix %in% (DF$ix[idx] + c(-1, 1)) & DF$iy == DF$iy[idx]
1+ i2 <- DF$iy %in% (DF$iy[idx] + c(-1, 1)) & DF$ix == DF$ix[idx]
1+ any(DF$country[idx] != DF$country[i1 | i
Please stop posting Mac-specific questions on R-help. You have been
asked not to do so before
There _is_ a quartz.save() function in R.app, whose FAQ you are reading.
The RMacOSX-FAQ is not part of R: it is part of the separate Mac-GUI
project. You really do need to contact the authors
Hello,
I'm using VAR models in R in order to obtain impulse responses of stock
market shock on US economy.
I have series of quarterly changes in real gdp, S&P 500 and quarterly level
of unemployment for 1985 - 2012 period.
My series are stationary. So I did all the steps below. However I don't
und
thank you. yes I want to loop over the elements of the data. I want the
output to be corresponded to the input by unchanging index. at the same
time, the data that is more than c value should follow the
function (a*(data-c)^0.5)+(b*(data-c), and the rest (same or less than c)
should return a zero.
Hello,
In your original post, there was a column named 'country', it now seems
to be 'name', therefore my function shouldn't work. To see the output of
head(9 is helpfull but the better way is dput(). Try the following:
exmpl <- sub[, c("name", "idxy", "ix", iy")]
dput( head(exmpl, 30) ) # p
Greetings
I went back over the examples in the R Graphics book on the grid
webpage and saw an example which I have adapted and seems to work:
pushViewport(viewport(layout=grid.layout(nrow=26,ncol=2)))
pushViewport(viewport(layout.pos.col=1,layout.pos.row=1))
plot_gene_map(dna_segs=list(segs[
Hi,
I would like to xor (bitwise) two matrices filled with binary values
(0,1). The result of such XOR is expected to be 0,1.
But apparently neither of xor nor bitXor is working in this case.
I got ": binary operation on non-conformable arrays" error message
when I used xor (M1,M2) .
The proble
Hello,
I'm not the greatest expert in ggplto2 but you're overcomplicating (if
the word exists).
1. In a black&white plot don't use argument color nor scale_color_manual().
2. your second plot object, p0, is completely unnecessary.
3. if you want it to look like the graph in the link, it's geom
Hi Rui,
Thanks for the quick reply! It was my mistake not to notice $country in
thr fourth line of your code. I went back and changed it to $name, and
got the following output when I mapped the borders:
http://i.imgur.com/DQ3IB.png
Here is the output of your function:
1> exmpl <- sub[, c(
Hello,
Your error message means that the arrays have different dim attributes.
check with
dim(M1) == dim(M2)
They must be the same.
If they are, the result is not 0/1 but FALSE/TRUE, which you can treat
as or coerce to integer.
Hope this helps,
Rui Barradas
Em 22-10-2012 16:44, shahab esc
example(jitter)
library('ggplot2')
example(geom_jitter)
RMW
On Monday, October 22, 2012, swertie wrote:
> Thank you for your comment. I would be very interested, but I did not know
> about jitter. Would you have a small example?
>
>
>
>
> --
> View this message in context:
> http://r.789695.n4.n
Try this -- this uses the vectorization which you need to read up on
in the Intro to R:
> #set the function
> fun<-function(a,b,c,data)
+ {
+ N <- numeric(length(data)) # initialize to zero
+ indx <- data > c # determine which data is greater than c
+ N[indx] <- (a * (data[indx] - c) ^ 0.5) + (b
Then what about:
fun<-function(a,b,c,data) {
ifelse(data > c, (a*(data-c)^0.5)+(b*(data-c)), 0)
}
y=c(100,210,320,130,170,120,220,90,55,45)
fun(1,0.2,150,data=y)
> fun(1,0.2,150,data=y)
[1] 0.00 77471.67 130418.05 0.00 44725.36 0.00 83680.00
[8] 0.00 0
Your attachments did not make it through to the official R-help mailing list.
Nabble R is not R-help.
I downloaded the files from the links to Nabble.
See further down for my comments.
On 22-10-2012, at 14:24, paulfjbrowne wrote:
> I haven't determined the root cause of the numerical accuracy bu
Incorrect. The code is 90% compatible. Look at
http://biostat.mc.vanderbilt.edu/Rrms for differences.
Frank
Joost Kremers wrote
> On Mon, Oct 22 2012, R. Michael Weylandt <
> michael.weylandt@
> > wrote:
>> Design has been superceeded by rms -- give that a shot.
>
> I know, but it doesn't l
On Mon, Oct 22, 2012 at 3:35 PM, sagarnikam123 wrote:
> I want to connect R with HTML/PHP pages to take input from user,do some
> statistical processing on it & show results to HTML page again.
> I search on net,i got Rserve package,but examples are mainly for java
> langaure & not for PHP
> i
HI,
Have u tried the example in the link
(http://stat.ethz.ch/R-manual/R-patched/library/stats/html/friedman.test.html).
It is working for me.
wb <- aggregate(warpbreaks$breaks,
by = list(w = warpbreaks$wool,
t = warpbreaks$tension),
FUN = mean)
friedman.test(x ~ w | t, data = wb)
# Fried
WARNING: Use with caution!
There is a way to effect the catenation of factors: The data.frame
method for rbind() does this. E.g.
set.seed(42)
f1 <- factor(sample(letters[1:3],42,TRUE))
f2 <- factor(sample(letters[1:4],66,TRUE))
d1 <- data.frame(f=f1)
d2 <- data.frame(f=f2)
dd <- rbind(d1,d2)
Hi
Apologies for the slow response.
This part of the problem is I think just a bit of a misunderstanding.
The diagram drawn by grid.show.viewport() is drawn within a *subset* of
the current page (or viewport), to allow room for labelling, which is
why your subsequent "real" viewports do not a
Thanks Rui, your solution works great and is so fast!
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HI,
Another way:
dat1<-read.table(text="
Observation Gender Dosage Alertness
1 1 m a 8
2 2 m a 12
3 3 m a 13
4 4 m a 12
5 5 m b 6
6 6 m b
Hi there,
I am exporting plm results (from the plm package) to Latex using the
texreg function (from the texreg package).
How can I force the exported results to appear in scientific format?
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https://stat.ethz.ch/mai
Hi all,
I'm working with a large data set (on the order of 300X300) and trying to
apply a function which compares the elements of all possible 2x2
submatrices. There are rc(r-1)(c-1) such submatrices, so obviously the naive
method of looping through the rows and columns is computationally unfeasib
Hello,
Another usefull link is
http://www.r-statistics.com/2010/02/post-hoc-analysis-for-friedmans-test-r-code/
Hope this helps,
Rui Barradas
Em 22-10-2012 20:18, arun escreveu:
HI,
Have u tried the example in the link
(http://stat.ethz.ch/R-manual/R-patched/library/stats/html/friedman.test.
thank you, that looks good
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thank you so much for helping! Now i got how to do it ;)
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R-help@r-project.org mai
I have an array of probabilitiesit is p. So if user types x=1 then
probability is p1=1/10.
If user types x=2 it means that p2= p1+p2
if user types x=3 it means that p3=p1+p2+p3and so on.
So i created a code. but it doesnt work properly. Help me plz to fix it)
Thank u in advance.
psidp
Dheeraj,
You need to give us some more hints of what
you get and what you don't get.
My guess is that what has happened is that the
optimization algorithm didn't converge.
The R-sig-finance mailing list would be a more
appropriate place for this discussion (you have
to subscribe before you can
300x300 isn't terribly large; looping should work just fine. But I'm
confused about a 2x2 submatrix:
I would have thought that a submatrix would be adjacent elements, like
x[1:2, 1:2]
or
x[13:14, 296:297]
but your loop compares all possible sets of four elements, so the
matrix position doesn't matt
This looks like homework to me.
Here's a hint, though:
p<-(1/10 2/5 2/5 2/5 2/5 1/10 1/10 1/10 1/10 1/10)
This is not how you create a vector in R.
for (i in 1 to x)
This is not how you create a for loop in R.
Sarah
On Mon, Oct 22, 2012 at 2:41 PM, Rlotus wrote:
> I have an array of probabil
Hello,
If your matrix is in the order of 300x300, the problem of extracting all
possible submatrices and applying a function will allways be a large
one, but the use of ?combn may reduce it a bit if the order of
rows/columns in the submatrices doesn't matter. It can reduce it from
300^4 = 8.1
Hello,
Try ?cumsum.
cumsum(p)
Hope this helps,
Rui Barradas
Em 22-10-2012 19:41, Rlotus escreveu:
I have an array of probabilitiesit is p. So if user types x=1 then
probability is p1=1/10.
If user types x=2 it means that p2= p1+p2
if user types x=3 it means that p3=p1+p2+p3and so on.
On Fri, Oct 19, 2012 at 6:28 PM, Ali Tofigh wrote:
> On Wed, Oct 17, 2012 at 4:08 PM, ilai wrote:
> > On Wed, Oct 17, 2012 at 11:10 AM, Ali Tofigh
> wrote:
>
> ## this works as intended with a mix of plot.new() and grid.newpage
> pdf("test3.pdf")
> plot.new(); my.plot(); grid.newpage(); my.plot
On Oct 22, 2012, at 1:51 AM, PIKAL Petr wrote:
> Hi
>
>> -Original Message-
>> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
>> project.org] On Behalf Of David Arnold
>> Sent: Monday, October 22, 2012 4:26 AM
>> To: r-help@r-project.org
>> Subject: [R] Margin annotation
>>
On Oct 22, 2012, at 7:48 AM, arun wrote:
> HI,
> Another way:
> dat1<-read.table(text="
> Observation Gender Dosage Alertness
> 11 m a8
> 22 m a12
> 33 m a13
> 44 m a12
> 5
Dear Paul,
Thank you very much for helping, works perfectly fine.
I now see the scaling when looking at grid.show.layout(), but I would have never
come up with looking there in the first place :-)
Cheers,
Marius
Paul Murrell writes:
> Hi
>
> Apologies for the slow response.
>
> This part o
I think this is what you want.
p <- c(1/10, 2/5, 2/5, 2/5, 2/5, 1/10, 1/10, 1/10, 1/10, 1/10)
psidp <- function(x){
if (x>0&&x<=10)
{
return(sum(p[1:x]))
}
else{
return("Input integer between 1 and 10")
}}
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Dear Gabor
You got solution for your problem?
"I have just got a laptop with win 7 64 bit installed on it. I
installed R and quite a few packages I use. When I try to start
BiodiversityR the library loads without any problems but when starting
the GUI it gives me the following error message:
So
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