This looks like homework to me.
Here's a hint, though:
p<-(1/10 2/5 2/5 2/5 2/5 1/10 1/10 1/10 1/10 1/10)
This is not how you create a vector in R.
for (i in 1 to x)
This is not how you create a for loop in R.
Sarah
On Mon, Oct 22, 2012 at 2:41 PM, Rlotus <yerl...@hotmail.com> wrote:
> I have an array of probabilities....it is p. So if user types x=1 then
> probability is p1=1/10.
> If user types x=2 it means that p2= p1+p2
> if user types x=3 it means that p3=p1+p2+p3....and so on.
> So i created a code..... but it doesnt work properly. Help me plz to fix it)
> Thank u in advance.
>
> psidp=function(x){
> p<-(1/10 2/5 2/5 2/5 2/5 1/10 1/10 1/10 1/10 1/10)
> i==0;
> if (x!=0){
> for (i in 1 to x)
> {p[i]=p[i]+p[i-1]
> p[i]
> }
>
> }
>
>
>
--
Sarah Goslee
http://www.functionaldiversity.org
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