Hello,
Try ?cumsum.
cumsum(p)
Hope this helps,
Rui Barradas
Em 22-10-2012 19:41, Rlotus escreveu:
I have an array of probabilities....it is p. So if user types x=1 then
probability is p1=1/10.
If user types x=2 it means that p2= p1+p2
if user types x=3 it means that p3=p1+p2+p3....and so on.
So i created a code..... but it doesnt work properly. Help me plz to fix it)
Thank u in advance.
psidp=function(x){
p<-(1/10 2/5 2/5 2/5 2/5 1/10 1/10 1/10 1/10 1/10)
i==0;
if (x!=0){
for (i in 1 to x)
{p[i]=p[i]+p[i-1]
p[i]
}
}
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