Dear Ivan,
first, it would pay-off in terms of readability to employ line breaks and
second to provide a reproducable code snippet and third which package you have
used. Now to your questions:
1) What happens if you provide colnames for your objects?
2) What happens if you omit the $ after count
Ben,
This example of pgfSweave looks like it would address my problem. I
installed this package, but I cannot determine how to use it to make R
convert LaTeX commands into mathematical symbols on an R plot. The
documentation does not seem to address this. I tried to mimic the
example from Yihui
We do not know the details of the kinds of computations you intend to do within
each iteration, but if, let's say, each iterations takes around 1 second, then
your simulation will run for the next 30+ years (on a single core). Even if
each iteration only takes a fraction of a second, you are sti
Dear Bernhard,
thank you very much for the response. Yes, I am using the packsges
"vars" with fuchrions VAR() and causality().
1)Giving colnames to the objects does unfortunately not change anything.
2) I am not sure if I understood you right. Did you mean to insert
Countml$Granger$p.value rath
Hi,
Through pgfSweave you can use the tikz device, which is the one that
can interpret Latex code (package tikzDevice). I would start with a
minimal self-contained plot with this function. see ?tikz for
examples.
HTH,
baptiste
On 15 April 2011 20:03, Michael McAssey wrote:
> Ben,
>
> This e
Hello Ivan,
see example(causality) for the first question and use count[[i]] and not
count$[[i]] for the second. The following works for me:
example(causality)
test1 <- causality(var.2c, "e")
test2 <- causality(var.2c, "prod")
tl <- list(test1, test2)
res <- matrix(NA, ncol = 1, nrow = length(tl
Dear R users,
I presume there is something foul with system:
a <- c(1,2,3,4)
as.matrix(a, ncol=2)
Output:
[,1]
[1,]1
[2,]2
[3,]3
[4,]4
The vignette for as.matrix says nrow (ncol) will be deduced from length
and ncol (nrow). It does not work even when I additionally specif
Liviu Andronic writes:
> Not a solution that would work in all cases, have you tried reducing
> the font size?
Yes, I have done this. I've also eliminated all the stuff that beamer
puts on the screen (title bars, navigation symbols, etc), to the point
that I probably shouldn't be using beamer
Hallo Michael,
check ?matrix and compare to as.matrix.
as.matrix does not provide a ncol argument. To get a 2 by 2 matrix use
matrix(a, ncol=2)
Regards
Adrian
Am 15.04.2011 11:42, schrieb Michael Bach:
Dear R users,
I presume there is something foul with system:
a<- c(1,2,3,4)
as.matrix(a,
Sorry, my previous mail was incomplete.
I mean, one of my xyplot is build with the command "doubleYScale" (in order to
overlap two line with different Y-axis).
But "doubleYScale" doesn't run with the nice command that you have suggested:
first plot:
a<-xyplot(NDVI_P10~dek_num
| Ye
Hi
r-help-boun...@r-project.org napsal dne 15.04.2011 01:34:22:
> Hi everyone.
>
> I am quite frustrated that this doesn't work, as all the functions
within
> work fine by themselves. I'd also like any pointers to how to avoid
'for'
> loops in my code. I understand it's less than desirable, bu
Baptiste,
Thank you. The examples in the documentation for tikz helped me solve
this problem, and give me a good tool for future plots. I only need
to figure out how to incorporate LaTeX packages like amssymb so that I
can use \mathbb{} to put the real numbers symbol in my plot.
Regards,
Micha
On 04/14/2011 11:48 PM, Jurgens de Bruin wrote:
Hi,
I do not have much R experience just the basics, so please excuse
any obvious questions.
I would like to create bubble plot that have Categorical data on the x and y
axis and then the diameter if the bubble the value related to x and y.
Atta
Hi Adrian,
thanks for the hint. The problem was that it showed me help for matrix
when I did ?as.matrix. I thought it was some kind of convention that
data type conversion functions start with "as.", so now I will take more
care in the future.
With matrix() it works as expected, thanks again.
Hi,
Could you not simplify your a and b plots into one like
xyplot(NDVI_P10 + AVG_NDVI_P10 ~ dek_num | Year,
data=data, lty = 3:2, col = c("darkgrey", "black"), ..., [etc]
auto.key = list(lines = TRUE, points = FALSE))
Otherwise please provide a commented, minimal, self-contained,
reprod
On 04/14/2011 10:49 PM, Serdar Akin wrote:
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal
Generate random numbers from a multinomial.
?rmultinom
# The following will generate n multinomial vectors each of size m
rmultinom(n, size=m, prob=m^(-1/8)) # you need to specify probabilities
appropriately
Ravi.
From: r-help-boun...@r-project.org [r-he
Hello..
How do I get str() to show all variables in a data frame? It seems to be
"list output truncated" at about 99 variables, the data frame has over
600 but i can't seem to figure out how to show all variables, we see
list.len() but again can't seem to figure this out - help will be
appreciated
Hi,
I've got something strange going on. I'm trying to compile a vignette using
Sweave("vignette.Rnw"), and in the first code chunk that illustrates an
example, I noticed from the output text I have inside the function, that it is
running it twice, because the sequence of message() statements i
It has always been my understanding that deviance for GLMs is defined
by;
D = -2(loglikelihood(model) - loglikelihood(saturated model))
and this can be calculated by (or at least usually is);
D = -2(loglikelihood(model))
As is done so in the code for 'polr' by Brian Ripley (in the
On 15/04/2011 7:00 AM, Dario Strbenac wrote:
Hi,
I've got something strange going on. I'm trying to compile a vignette using
Sweave("vignette.Rnw"), and in the first code chunk that illustrates an
example, I noticed from the output text I have inside the function, that it is running it
twice,
On Apr 15, 2011, at 7:19 AM, zubin wrote:
> Hello..
>
> How do I get str() to show all variables in a data frame? It seems to be
> "list output truncated" at about 99 variables, the data frame has over
> 600 but i can't seem to figure out how to show all variables, we see
> list.len() but again c
On 15/04/2011 8:19 AM, zubin wrote:
Hello..
How do I get str() to show all variables in a data frame? It seems to be
"list output truncated" at about 99 variables, the data frame has over
600 but i can't seem to figure out how to show all variables, we see
list.len() but again can't seem to figu
On 4/14/2011 7:22 PM, Dirk Eddelbuettel wrote:
Sorry, but this is the r-help list. The 'R Spam' list is over at /dev/null.
Clearly a fortune candidate!
--
Michael Friendly Email: friendly AT yorku DOT ca
Professor, Psychology Dept.
York University Voice: 416 736-5115 x66249 Fax: 4
On 04/15/2011 01:13 AM, Jurgens de Bruin wrote:
> Thanks for the reply...
>
> with reproducible I am believe you require a dataset?
yes -- but you can make one up if you like. e.g.
dd <- expand.grid(drugclass=LETTERS[1:5],
plant=c("cactus","sequoia","mistletoe"))
set.seed(101)
dd$fitvalue
On Thu, Apr 14, 2011 at 11:47 PM, Christian Gunning wrote:
> On Thu, Apr 14, 2011 at 7:02 PM,
> wrote:
>
>> I was able to write a very short C++ function using the Rcpp package
>> that provided about a 1000-fold increase in speed relative to the best
>> I could do in R. I don't have the script o
Hello,
I am exporting a graph in "gml" format from igraph 0.5.5. When I open the
file in Cytoscape v.2.7 I can't map the color attribute that I assign to the
graph when I export it from igraph. Could anyone help me in this?
Thanks.
--
Warm Regards,
Sandeep Amberkar
BioQuant,BQ26,
Im Neuenheimer
Listers,
I have created a cross-tab matrix using the following code:
S <-
c(1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,1,2,3,1,1,2,3,1,2,2)
F <-
c(1,2,3,1,2,3,1,1,1,1,2,3,1,1,3,2,2,2,1,2,3,1,1,1,1,2,3,3,1,3,1,3,1,1,2,3,1,1,3,2,3,2,1,1,1,2,3,1,1,2)
table(S,F)
f
Hi Dmitry,
Nothing is seriously wrong.
You want to set the fourth column name, so take column names THEN
the fourth element:
colnames(PiD)[4] <- "total"
Thank you for providing a clear and simple reproducible example.
Sarah
On Fri, Apr 15, 2011 at 9:29 AM, Dmitry Berman wrote:
> Listers,
>
>
which(data==max(data),arr.ind=TRUE)
gives you the indices of the largest element.
which(data==data[order(data)[2]],arr.ind=TRUE)
the indices of the second largest.
Best
Jannis
On 04/14/2011 10:23 PM, Nicolas Gutierrez wrote:
hi All,
I have a matrix Ufi (x by y)
1 2 3 4 5
1 0 0 0 0
perfect! thx
On 4/15/2011 8:43 AM, Duncan Murdoch wrote:
> On 15/04/2011 8:19 AM, zubin wrote:
>> Hello..
>>
>> How do I get str() to show all variables in a data frame? It seems to be
>> "list output truncated" at about 99 variables, the data frame has over
>> 600 but i can't seem to figure out h
Kevin Wright gmail.com> writes:
>
> > I am trying to teach myself R and replicate some previous SAS analysis.
> > Could someone please help me translate the following SAS code into R.
> >
> > Proc mixed method=ml
> > Class Group Treatment Stream Time Year;
> > Model Logrpk=Treatment Time Treatme
Hi.
Have a look also at ?addmargins.
addmargins(table(fS,fF),c(1,2),FUN=list(total.row=sum,total.col=sum))
Andrija
On Fri, Apr 15, 2011 at 3:29 PM, Dmitry Berman wrote:
> Listers,
>
> I have created a cross-tab matrix using the following code:
>
> S <-
>
> c(1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3
On 14.04.2011 18:04, Paul78 wrote:
I have got the same problem. Can anybody help me why R just shuts down?
1. please quote the original message, mailing list readers do not see it
and it is hard to access it.
2. please specify a reproducible example as the posting guide quoted
below suggest
On 14.04.2011 18:14, rbali wrote:
Same problem with Vista
1. Please quote the original message, mailing list readers are not able
to follow otherwise!
2. Peter Dalgaard wrote that it is a bug in the ctv package, so
everything is said already. And rather than posting here, why not ask
the c
Sorry, I've just reversed the names of dimensions :)
addmargins(table(fS,fF),c(1,2),FUN=list(total.col=sum,total.row=sum))
Andrija
On Fri, Apr 15, 2011 at 3:50 PM, andrija djurovic wrote:
> Hi.
>
> Have a look also at ?addmargins.
>
> addmargins(table(fS,fF),c(1,2),FUN=list(total.row=sum,tot
Hi Michael,
It helps to look at the "Usage" section of the help pages. There you
will see that matrix() has an ncol argument, but as.matrix() does not.
Best,
Ista
On Fri, Apr 15, 2011 at 7:08 AM, Michael Bach wrote:
> Hi Adrian,
>
> thanks for the hint. The problem was that it showed me help fo
Hello,
quick question I reckon.
Is there a way to add to time series to a dataframe without knowing their
name in advance?
I can figure it out the following but wondered if there is a better way
Thanks
Paolo
a = data.frame(i = rep(100, 12))
colnames(a)[length(colnames)] = i
[[alter
Hi,
the problem is that igraph puts node colors into the GML file as
simple vertex attributes, but this is not what Cytoscape expects.
Plus, it seems that Cytoscape does not read all the node/edge
attributes from the GML file, only the ones it interprets, so the
color information is lost.
Sadly,
Dear R users,
Hi. I am using prediction function in ROCR package.
y consists of two classes 0 and 1.
However, since I am using cross-validation, a sampled small number of
y may consist of only one class
>y
[1] 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
In this case, prediction function gives an erro
On 13.04.2011 02:11, jkang wrote:
I have an ubuntu image with R installed. I want to install a list of
packages that does not come with R. eg. cluster, gplots, hacks, mapdata.
etc. Over time this list may grow.
Is there a config file that can tell R what and where to install additional
packa
On 14.04.2011 19:48, droberts wrote:
I apologize for the slow response, but I just registered with Nabble.
>
The duleg function in labdsv was renamed indval to be more consistent with
its use in the literature. Typing ?indval will provide more information.
As an aside, all R functions have
On 14.04.2011 12:47, taby gathoni wrote:
Hi R-users,
This is a generic question, is there a way to plot a line graph for the output
from crosstable function? one of the inputs to the crosstab function is
categorical.
Generic answer: probably yes.
According to the posting guide, you have
On 12.04.2011 21:52, Zd Gibbs wrote:
Sorry, the first version was incomplete. I'm trying again.
I am running a regression equation and i want to enter in 12 IV then stepwise
enter 8 variables and not have an origin.
DV is "shfl".
I want to enter in the following 12 independent dummy variable
On 15.04.2011 17:00, Soyeon Kim wrote:
Dear R users,
Hi. I am using prediction function in ROCR package.
y consists of two classes 0 and 1.
However, since I am using cross-validation, a sampled small number of
y may consist of only one class
y
[1] 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
Sounds like homework. Anyway, lookup rank correlations (Spearman,
Kendall, etc.) and correpsonding tests.
Uwe Ligges
On 14.04.2011 17:00, Baoqiang Cao wrote:
Hi,
I have to one set of inputs and their observed true values of each
input. Now I have a model takes the input and predict a value.
Hi,
I am a complete newcomer to R and although I can plot standard box-plots I am
struggling with this...
I have two treatments - A & B, and 2 variables 1 & 2. I want to compare
boxplots of variable 1 with variable 2 for each treatment. I would also like
them to all be on the same graphic.
I
I am making the question clear. Please help.
> Dear R experts
>
> I was using kinship package to fit mixed model with kinship matrix.
> The package looks like lme4, but I could find a way to extract p-value
> out of it. I need to extract is as I need to analyse large number of
> variables (> 10
I calculate an anova test in the following way:
expdata<-read.table("/home/dorien/UA/meta-music/optimuse/optimuse1-build-desktop/results/results_processedCP",
header=TRUE)
names(expdata)<-c('nh1','nh2','nh3','randsize','aweights','tt1','tt2','tt3','path','iters','type','length','tos','tws','time'
I have a question, What is the maximum storage capacity of data that R has?
Thanks
Pamela Santelices Elgueta
Estadístico
Instituto Nacional de Estadísticas
Fono: (56-2) 7962491
Paseo Bulnes 209 oficina 82
Santiago
[[alternative HTML version deleted]]
__
baptiste auguie-5 wrote:
>
>
> I wish to modify programmatically only a few factor levels, according
> to a named list. I came up with this function..
>
> .
> It seems to work, but the original order of the levels is changed.
>
>
The split-and-unite policy you use makes it a bit diff
dorien wrote:
>
> I calculate an anova test in the following way:
>
> ... aov example
>
> I want to check the fit of the model with Rsquared
>
Try summary(lm(...)) instead.
Dieter
--
View this message in context:
http://r.789695.n4.nabble.com/Rsquared-for-anova-tp3452399p3452434.html
Se
On 15/04/2011 12:05 PM, Pamela Santelices Elgueta wrote:
I have a question, What is the maximum storage capacity of data that R has?
There isn't a simple answer to this question. Vectors have a maximum
length of about 2 billion entries, and matrices are stored as vectors.
Most often you w
Hi there,
I have two data sets, one of locations at different elevations (x,y,z) and
the other of points that make up topographic contours (also x,y,z). I have
used:
result<-apply(distppll(data2,cbind(topocon[-nrow(topocon),],topocon[-1,])),1,min)
where 'data2' are my measurement coordinates (x,
Thanks Petr,
Actually, I figured it out last night. Please read on only if you're sort of
interested.
You're absolutely right, I hastily changed my function to be more 'readable'
without thinking that I was using a name that was already a function.
What I wanted was a cross-tabulation of f1 and
Hi,
I have found quite a few posts on normality checking of response variables, but
I am still in doubt about that. As it is easy to understand I'm not a
statistician so be patient please.
I want to estimate the possible effects of some predictors on my response
variable that is nº of males an
Dear list,
I want to loop over a list through lapply and at the same time I want to
extract some information from the names of the list elements. lapply does
not seem to carry the names. Is there anyway to access the names of a list
within lapply? Thanks.
Jun
[[alternative HTML version d
Normality of the predictors doesn't belong to the assumptions of the GLM,
so you don't have to check this.
Note, however, that there are all kinds of potential problems which to
detect is fairly hopeless with n=11 and three predictors, so you shouldn't
be too confident about your results anywa
Hi Jun,
On Fri, Apr 15, 2011 at 11:14 AM, Jun Shen wrote:
> Dear list,
>
> I want to loop over a list through lapply and at the same time I want to
> extract some information from the names of the list elements. lapply does
> not seem to carry the names. Is there anyway to access the names of a l
Try this:
lapply(mtcars, function(.)names(mtcars)[match.call()[[2]][[3]]])
On Fri, Apr 15, 2011 at 3:14 PM, Jun Shen wrote:
> Dear list,
>
> I want to loop over a list through lapply and at the same time I want to
> extract some information from the names of the list elements. lapply does
> not
Hello, R friends...
I am very new to R, and I need some help. I am trying to construct a
simulation for my dissertation.
I need to create 1000 datasets of 1000 subjects with the following variables...
Treatment variable - Drawn from a binomial distribution (1 run, prob=.13)
Covariate 1 - Drawn
Hi,
I was wondering I'm going about this in the correct way. I need to test if
there are coding sequences or exons in hg19 which match a string of 100bp
"D" i.e. [A,G or T]. However I'm getting a strange result.
I get a hit on chr7, using the 100bp search however when I search with 60bp
sequence o
What have you tried so far?
It is often helpful to begin with a much simpler problem, then add
complexity incrementally until you've constructed the desired model.
Best wishes.
Charles Annis, P.E.
charles.an...@statisticalengineering.com
561-352-9699
http://www.StatisticalEngineering.com
Here's a script of what I have so far. I have a few problems. First, the
correlations. Next, recoding that categorical variable into dichotomous
variables. Finally, the iterative filename thing.
Thanks!
S
-Original Message-
From: Charles Annis, P.E. [mailto:charles.an...@statistica
Am 15.04.2011 20:14, schrieb Christian Hennig:
Normality of the predictors doesn't belong to the assumptions of the
GLM, so you don't have to check this.
Note, however, that there are all kinds of potential problems which to
detect is fairly hopeless with n=11 and three predictors, so you
should
Hi Shane,
See ?rbinom, ?rnorm, ?mvrnorm (in the MASS package), ?sample, ?for and
?write.table
Best,
Ista
On Fri, Apr 15, 2011 at 2:49 PM, Shane Phillips
wrote:
> Hello, R friends...
>
> I am very new to R, and I need some help. I am trying to construct a
> simulation for my dissertation.
>
> I
Thanks, Joshua and Henrique.
Henrique's solution is very interesting. Could you explain a bit more? What
does this grammar mean?
match.call()[[2]][[3]]
Jun
On Fri, Apr 15, 2011 at 1:27 PM, Henrique Dallazuanna wrote:
> Try this:
>
> lapply(mtcars, function(.)names(mtcars)[match.call()[[2]][[3]
Hi,
When I install R in Ubuntu/Linux, is it possible to view only the error
messages without the installation progress? And how?
Regards,
Iurie Malai
Moldova Pedagogical State University
[[alternative HTML version deleted]]
__
R-help@r-project
Sorry,
I meant: when installing R packages with 'install.packages()'.
2011/4/15 Iurie Malai
> Hi,
>
> When I install R in Ubuntu/Linux, is it possible to view only the error
> messages without the installation progress? And how?
>
> Regards,
> Iurie Malai
> Moldova Pedagogical State University
Hi all,
Suppose I have 2 data.frame , a and b, how can I add them together to get c?
Thanks
> a
A
a 1
b 2
c 3
> b
A
a 6
c 1
> c
A
a 7
b 2
c 4
--
Best,
Zhenjiang
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing lis
On 15 April 2011 12:03, Shane Phillips wrote:
> Here's a script of what I have so far. I have a few problems. First, the
> correlations. Next, recoding that categorical variable into dichotomous
> variables. Finally, the iterative filename thing.
>
Where?
Perhaps give the list one questio
Try performing stratified sampling when doing cv.
cran.r-project.org/web/packages/ipred
On Fri, Apr 15, 2011 at 11:00 AM, Soyeon Kim wrote:
> Dear R users,
>
> Hi. I am using prediction function in ROCR package.
> y consists of two classes 0 and 1.
> However, since I am using cross-validation, a
Hi:
Here's one approach:
> df1 <- data.frame(x = letters[1:3], y = 1:3)
> df2 <- data.frame(x = c('a', 'c'), z = c(6, 1))
> dfm <- merge(df1, df2, all.x = TRUE)
> dfm
x y z
1 a 1 6
2 b 2 NA
3 c 3 1
sumdf <- data.frame(x = dfm$x, y = rowSums(dfm[, -1], na.rm = TRUE))
x y
1 a 7
2 b 2
3 c 4
How to make a launcher for Rattle?
Regards,
Iurie Malai
Moldova Pedagogical State University
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Hello R users!
I have several data frames where some of the variables have many missing
observations. For example, Q1 in one of my data frames has over 66% of its
observations missing. I have tried imputation with mice but it does not work
for all the data frames and I get the following message
Thanks, Dennis! I'll go with it. It's surprising there is no ready way to do
that. I imagine it should be a common data manipulation to add two
data.frame from two different sources. It could happen that one data.frame
is missing some rows while the other have some more.
On Fri, Apr 15, 2011 at 5:
Rita Carreira hotmail.com> writes:
> I have several data frames where some of the variables have many
> missing observations. For example, Q1 in
> one of my data frames has over 66% of its observations missing.
> I have tried imputation with mice but it does
> not work for all the data frames an
Amos Folarin gmail.com> writes:
> I was wondering I'm going about this in the correct way. I need to test if
> there are coding sequences or exons in hg19 which match a string of 100bp
> "D" i.e. [A,G or T]. However I'm getting a strange result.
>
> I get a hit on chr7, using the 100bp search ho
I tried this:
sh -c 'R_DEFAULT_PACKAGES="$R_DEFAULT_PACKAGES rattle" R "$@"'
but without success. I get this message:
R version 2.13.0 (2011-04-13)
Copyright (C) 2011 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
Platform: i486-pc-linux-gnu (32-bit)
R is free software and comes
I apologize for my last post. here is the script I forgot to paste!
subject=1:1000
treat=rbinom(1*1000,1,.13)
gender=rbinom(1*1000,1,.5)
eth=runif(1*1000, min=1, max=4)
cogat=rnorm(1*1000, 100, 16)
map=rnorm(1*1000, 200, 9)
growth=0
simtest=data.frame (subject=subject, treat=treat, gender=gender,
Sacha Viquerat web.de> writes:
>
> Am 15.04.2011 20:14, schrieb Christian Hennig:
> > Normality of the predictors doesn't belong to the assumptions of the
> > GLM, so you don't have to check this.
> >
> > On Fri, 15 Apr 2011, Simone Santoro wrote:
> >
> >> I want to estimate the possible effects
See below:
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
-Original Message-
From: Jeremy Miles
Date: Fri, 15 Apr 2011 14:17:13 -0700
To: Shane Phillips
Cc: "r-help@r-project.org"
Subject: Re: [R] Monte Carlo Simulati
The filenames can be done within a loop, like this:
for (id in 1:1000) {
## the filename
fname <- paste('sample', formatC(id,width=4,flag='0'),'.tsv',sep='')
## more stuff
}
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1
On Fri, Apr 15, 2011 at 6:10 PM, zhenjiang xu wrote:
> Thanks, Dennis! I'll go with it. It's surprising there is no ready way to do
> that. I imagine it should be a common data manipulation to add two
> data.frame from two different sources. It could happen that one data.frame
> is missing some ro
On 16/04/11 04:18, sam.e wrote:
Hi there,
I have two data sets, one of locations at different elevations (x,y,z) and
the other of points that make up topographic contours (also x,y,z). I have
used:
result<-apply(distppll(data2,cbind(topocon[-nrow(topocon),],topocon[-1,])),1,min)
where 'data2' a
On 16/04/11 00:38, Duncan Murdoch wrote:
In version 2.14.0 in the fall, this will no longer be the default
behaviour. Perhaps it will be possible to suppress the multiple runs
before then, but I think it is unlikely that the default will change.
It already ***is*** the fall (or autumn, mo
I recently installed version 2.13, however when I click the manual
from the console, the error message appears
Error: 'doc\manual\refman.pdf' not found
Error: 'doc\manual\R-intro.pdf' not found
Does anyone know about what's happening?
Thank you very much
__
Hi Everyone,
I am trying to figure out the spatstat package for the first time and am having
some trouble. Unfortunately, I can't post my data set but I'll hopefully post
enough details for some help.
I want to model the intensity of a spatial point process using 2 covariates
from my data. Aft
On 11-04-15 10:20 PM, Fred wrote:
I recently installed version 2.13, however when I click the manual
from the console, the error message appears
Error: 'doc\manual\refman.pdf' not found
Error: 'doc\manual\R-intro.pdf' not found
Does anyone know about what's happening?
We just noticed this a
I am having the same problem on R-2.13.0. Anybody have ideas? Thanks!
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R-h
Hi,
Thank you for your suggestion.
I am stil quite new to the syntax of R. I tried in a few ways but all
produced errors:
> fit <- lm((tos~nh1*nh2*nh3*randsize*aweights*tt1*tt2*tt3*iters*length,
data=expdata))
Error: unexpected ',' in "fit <-
lm((tos~nh1*nh2*nh3*randsize*aweights*tt1*tt2*tt3*ite
Hi R community,
I am new bird to R and moved recently from SAS. I am no means expert on
either but very curious learner. So your help crucial for me to learn R.
I have already got positive expression.
I was trying to fit a mixed model in animal experiment but stuck at simple
point. The following
Hi,
Is there a function somewhere that does a "patterned" jitter of data?
I've googled and the problem is that I don't know what to google for.
The setting is in grouped data. I have plots which overlay jittered
points on a boxplot. I simply jitter the "x-value", and the "y-value"
has no
My question was how can we estimate effects and define correct
model equivalent to SAS code provided.
On Fri, Apr 15, 2011 at 10:21 PM, Nilaya Sharma wrote:
> Hi R community,
>
> I am new bird to R and moved recently from SAS. I am no means expert on
> either but very curious learner. So your hel
I am desperate for help and thank you to everyone providing input.
I am using lme4 for a mixed linear model, and trying to replicate a SAS
analysis (see thread below).
Variables:
Dependent = logrkm; Independent = Group (Streams grouped by similarity),
Treatment (3 treatments), Stream, Time (1 or
Hi friends,
Does anyone know how to make truncated y axis with cut mark (\\) in R plot?
Many
thanks!
Bill
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Thanks, Gabor. It's a nice workaround. I'll look more at zoo library.
On Fri, Apr 15, 2011 at 7:10 PM, Gabor Grothendieck wrote:
> On Fri, Apr 15, 2011 at 6:10 PM, zhenjiang xu
> wrote:
> > Thanks, Dennis! I'll go with it. It's surprising there is no ready way to
> do
> > that. I imagine it sho
I sometimes get errors of this form:
Error: cannot allocate vector of size 13.8 Gb
I've also seen "Gb" used in R documents. Is "Gb" being used to refer to
gigabyte? We usually refer to bytes and gigabytes when discussing memory
usage, but the lowercase "b" more often refers to bits. Accord
This is a result of bugs in rattle.
The first bug is that you are explicitly asked on its help page not to
use installed.packages() in that way.
Second, packages should be able to be loaded in a session with just
base loaded, so rattle's startup code should have
utils::installed.packages().
Dear all,
I hope this is the right place to ask this question.
I am reviewing a research where the analyst(s) are using a linear regression
model. The dependent variable (DV) is a continuous measure. The independent
variables (IVs) are a mixture of linear and categorical variables.
The author
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