Hi Dave,
Thank you for your helpful advice. I will take a look at the multicomp package.
I was wondering where the lme() function outputs the interaction
between condition*difficulty?
Below is the output to the code I had originally sent. Which one of
these is condition*difficulty?
Fixed effect
Dear R users,
I am sorry to disturb you! But I really need your help for the usage of
sigPathwy.
Actually, I want a sliding window analysis for possible chromosome expression
pattern mining. My research microorganism is a plant pathogen, Gibberella zeae,
and I first used SAS to divid
Hi Dave,
Thank you for your helpful advice. I will take a look at the multicomp package.
I was wondering where the lme() function outputs the interaction
between condition*difficulty?
Below is the output to the code I had originally sent. Which one of
these is condition*difficulty?
Fixed effect
Thanks to all of you for your answers!
Peter's is definitely the easiest :)
for (i in 1:4) {
temp <- data.frame(a=(i+1):(i+10), b=LETTERS[(i+1):(i+10)])
filename <- paste("file", i, sep="")
assign(filename, temp)
save(list=c(filename), file=paste(filename, ".rda", sep=""))
}
Tao, I do
Dear All,
I am very new to T. I need to fit a ARIMA model to my time
series. So I found the auto correlation functions and partial auto
correlation function in R. Now I want to save these valuse along with the
significance levels to a file. How to do that?. I tried some function in R
Hi Dennis,
What is the problem with using eval(parse(text=...))? Is there a reason
why not to use it?
Of course, in that case, "list" within save() is much easier and works
perfectly.
In any case, thanks for your explanations :)
Ivan
Le 5/20/2010 10:26, Dennis Murphy a écrit :
> Hi:
>
> On Thu
Hello,
I have an Excel file on a drive and I extract data from it into R session.
Once I have extracted the data, I want to delete that Excel file from the drive.
Can I do that from within R, please?
Thank you for help!
Regards,
Sergey
__
R-help@r-pro
Check out:
?unlink
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) |
www.r-statistics.com (English)
file_to_delete = file.choose()
file.remove(file_to_delete)
Best,
Dave Deriso
UCSD Psychology
On Thu, May 20, 2010 at 1:46 AM, Sergey Goriatchev wrote:
> Hello,
>
> I have an Excel file on a drive and I extract data from it into R session.
> Once I have extracted the data, I want to delete that E
Thank you, Dave!
Regards,
Sergey
On Thu, May 20, 2010 at 10:55, Dave Deriso wrote:
> file_to_delete = file.choose()
> file.remove(file_to_delete)
>
> Best,
> Dave Deriso
> UCSD Psychology
>
> On Thu, May 20, 2010 at 1:46 AM, Sergey Goriatchev wrote:
>> Hello,
>>
>> I have an Excel file on a dri
Dear Dave,
I think you want this model.
lme(value~condition:diff - 1,random=~1|subject)
Note that I removed the replicate ID from the model. Include it in the model
makes only sense if you can expect a similar replication effects the
first/second/thirth time that a subject performs your test.
Thanks, Tal
Will check it out.
Regards,
Sergey
On Thu, May 20, 2010 at 10:51, Tal Galili wrote:
> Check out:
> ?unlink
>
>
>
>
> Contact
> Details:---
> Contact me: tal.gal...@gmail.com | 972-52-7275845
> Read me: www.talgalil
Dear R users,
I am trying to minimize two function simultaneously in R,
function(x)
minimize x[1],x[2],x[3]
mean(distribution(x1,x2,x3) ) - observed mean
std(distribution(x1,x2,x3)) - observed std
What I want to achieve is that simulated mean and standard deviation
of distribution related to
Dear colleagues, the code below generated the two effects plots that I
have attached. I hope they are not stripped.
The original two models are as follows:
green_shift_mod=glm(green_shift ~ educ+party_id+educ:party_id,
family=binomial, data=x)
carbon_tax_mod=glm(carbon_tax ~ educ+party_id+edu
Hi Thierry,
Thank you so much for your response! I ran the model and I obtained
some strange results (see below). Is there a simple way to compute a
condition x difference interaction with the lme? Also, I read in the R
Book (Crawley, 2007) that repeated measures on the same day would be
temporal
I am receiving the above error ( full r session output below) the
script runs OK in windows. and "genotypes" and "ploidy" are both
correct arguments
any suggestions would be most welcome
Nevil Amos
MERG/ACB
Monash University School of Biological Sciences
> library(Geneland)
Loading
Hi all,
I would like to read the results of the commands type in the terminal window in
Microsoft Word. As a blind user my options are somewhat limited and are time
consuming if I want to see the results of the commands that I have type
earlier. for example if my first two commands were
x<-c
Dear Dave,
The model is correct. But it is not testing the hypotheses you want. The null
hypothesis is that each level of the interaction is zero, which is clearly not
the fact.
I misread you question, therefore my advise was not accurate. Since you are
explicitly interested in comparing all l
Hi list,
I need to process a Rnw file and and a csv file (both are encoded in
UTF-8) under Windows XP (R Version 2.11.0, i386, mingw32).
I can source and run the Rnw file:
> Stangle("Bericht.Rnw")
Writing to file Bericht.R
> source(file("Bericht.R", encoding="UTF-8"))
which runs fine, but runn
Hello,
you may want to contact directly the maintainer of Geneland for that kind of
issue. In any case, this post would be best suited for R-sig-genetics:
https://stat.ethz.ch/mailman/listinfo/r-sig-genetics
Best regards,
Thibaut
--
##
Dr Thibaut JOMBART
MRC
On Thu, 2010-05-20 at 01:35 -0700, Fred wrote:
> Dear R users,
>
> I am trying to minimize two function simultaneously in R,
>
> function(x)
>
> minimize x[1],x[2],x[3]
>
> mean(distribution(x1,x2,x3) ) - observed mean
>
> std(distribution(x1,x2,x3)) - observed std
>
> What I want to achieve
Great, thanks, Sveb
2010/5/20 Duncan Murdoch :
> Sven Garbade wrote:
>>
>> Hi list,
>>
>> I need to process a Rnw file and and a csv file (both are encoded in
>> UTF-8) under Windows XP (R Version 2.11.0, i386, mingw32).
>>
>
> Take a look at this post:
>
> http://tolstoy.newcastle.edu.au/R/e10/h
This is to announce that we plan to release R version 2.11.1 on Monday,
May 31, 2010.
Those directly involved should review the generic schedule at
http://developer.r-project.org/release-checklist.html
The source tarballs will be made available daily (barring build
troubles) via
http://cran.r-pr
May I ask for the help on how to plot Item characteristic curve (ICC) one
item each. I have fit 3 parameter model for a test with 40 items.Currently I
get ICC for all the 40 items in a single graph making it difficult to
interpret.
Thanks and Regards,
--
Maulik Shah
[[alternative HTML ve
Sven Garbade wrote:
Hi list,
I need to process a Rnw file and and a csv file (both are encoded in
UTF-8) under Windows XP (R Version 2.11.0, i386, mingw32).
Take a look at this post:
http://tolstoy.newcastle.edu.au/R/e10/help/10/05/4889.html
which discussed this issue recently.
Duncan M
Dear All,
I have data some thisng like this :
> data <- read.csv(file='ipsample.csv',sep=',' , header=TRUE)
> data
State Jan Feb Mar Apr May Jun
1 AAA11022 0
2 BBB 1298 1195 1212 1244 1158 845
3 CCC 00012 1
4 DDD5 11 17 15 10
Dear R-users,
A new package called `lavaan' (for latent variable analysis) has been
uploaded to CRAN. The current version of lavaan (0.3-1) can be used for
path analysis, confirmatory factor analysis, structural equation
modeling, and growth curve modeling.
More information can be found on t
The problem is that the acf function (like many R functions) returns a list
containing many different things. For example, I have a short series in
the vector z:
> acz <- acf(z)
> str(acz)
List of 6
$ acf : num [1:11, 1, 1] 1 -0.0668 -0.7401 0.0627 0.5954 ...
$ type : chr "correlation"
$ n.u
Dear Everyone,
I 've just begun to use the library ncdf and I would like to compare
meteorological observational data with forecast data, so to make verification.
The netcdf files I'm using contain data of many different parameters in many
different stations. I could read easily that I need
Dear list,
I would like to know if is it possible to add a legend to a pie3D??
Thanks for your attention!
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-
On 05/20/2010 09:06 PM, n.via...@libero.it wrote:
Dear list,
I would like to know if is it possible to add a legend to a pie3D??
Thanks for your attention!
Hi n.vialma,
You sure can. Try adding this to the example:
legend(-1,1,c("Haters","Opposers","Apathizers","Lovers"),fill=rainbow(4))
Jim
Hi,
I have tried looking at the archives but havent found any answer that works
till now (Sorry if i have missed anything)
I am a newbie to R and i am trying to carry out hierarchical clustering
using hclust -> as.dendrogram and then plotting the results as a dendrogram
using the plot function p
Hi,
I think that one of the cex arguments in par() can be what you're
looking for. But since I've never plotted any dendrogram, I don't know
which one, if any.
HTH,
Ivan
Le 5/20/2010 14:08, Ayesha Jadoon a écrit :
Hi,
I have tried looking at the archives but havent found any answer that work
Dear users,
I would like to process all the lists from all *.rda files that I have
in one folder.
Up to now, I can load all the *.rda files without any problem.
The problem is when I want to access the list saved within each *.rda
file (only one list per rda file).
Here is my code:
fpath <-
Hello,
I couldn't find information on whether the logarithmic integrals
Li_m(x) = integral_0^x log(t)^(-m) dt
for x >= 0 are available in R?
Best wishes
Oliver
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE
>
> Dear Marco,
>
> I was trying using lattice barchart() but your suggestion will do the
> trick.
>
> Many thanks
>
> Javier
Lattice is great but a bit hard for me to learn and customize. I think
you should use ltext() in this case or edit panel.barchart() by hand,
but I don't know how.
Try this:
(data[,-(1:2)] - data[,2]) * prop.table(data[,2]) + data[,2]
On Thu, May 20, 2010 at 7:38 AM, Mohan L wrote:
> Dear All,
>
> I have data some thisng like this :
>
> > data <- read.csv(file='ipsample.csv',sep=',' , header=TRUE)
>
> > data
> State Jan Feb Mar Apr May Jun
> 1 AA
On 05/19/2010 09:15 PM, ?? wrote:
> Dear R users,
>
>
>
> I am sorry to disturb you! But I really need your help for the usage
> of sigPathwy.
Please ask questions about Bioconductor packages on the Bioconductor
mailing list, as other Bioconductor users are the ones mostly likely to
have ex
On May 20, 2010, at 1:01 AM, Joshua Wiley wrote:
Dear Mohan,
First, I would like to modify my code slightly to:
data <- rbind(data,data.frame(State="Total",t(apply(data[,-1], 2, sum,
na.rm=TRUE
This actually will add a 7th level to your factor automatically. The
reason I wanted to chang
? merge
> obs <- read.table(textConnection("12866 14.4
+
+ 12844 14.1
+
+ 12843 16.5
+ 12860 14.9
+ 128519.8
+
+ 12846 15.3"), col.names=c('station', 'obs'))
> fore <- read.table(textConnection("12830 12.808611
+ 12836 12.725081
+ 12843 15.241580
+ 12844 15.185887
+ 12846 1
Hello,
I have a dataframe:
dd <- data.frame(b = c("chr2", "chr1", "chr15", "chr13"),
x = c("A", "D", "A", "C"), y = c(8, 3, 9, 9),
z = c(1, 1, 1, 2))
>dd
b x y z
1 chr2 A 8 1
2 chr1 D 3 1
3 chr15 A 9 1
4 chr13 C 9 2
Now I want to sort them according column "b", but onl
Hey all
I am relatively new to analysis in R
(and am a geneticist so apologies for rubbish questions ),
I have a question regarding repeated measures analysis
this was what i have done so far
1)ph<-make.rm(constant=c("sid","pheno1","snp","sex","age"),repeated=c("measure1","measure2"),data=fil
On May 20, 2010, at 6:38 AM, Mohan L wrote:
Dear All,
I have data some thisng like this :
data <- read.csv(file='ipsample.csv',sep=',' , header=TRUE)
data
State Jan Feb Mar Apr May Jun
1 AAA11022 0
2 BBB 1298 1195 1212 1244 1158 845
3 CCC 000
I've found the answer:
get() is exactly what I need, I completely forgot about this function.
There might be a better way, but that works for me.
Ivan
Le 5/20/2010 14:13, Ivan Calandra a écrit :
Dear users,
I would like to process all the lists from all *.rda files that I have
in one folder.
Look at the RColorBrewer package to understand how you can create the
colors you want. Also do "?colorRampPalette"
On Wed, May 19, 2010 at 4:24 PM, Changbin Du wrote:
> Thanks, Phil!
>
> Does that mean only eight colors can be used in R plot?
> THe following codes works for me, but, if I use the
> dd
b x y z
1 chr2 A 8 1
2 chr1 D 3 1
3 chr15 A 9 1
4 chr13 C 9 2
> # add column with just numbers
> dd$sort <- as.integer(gsub("\\D+", "", dd$b))
> dd[order(dd$sort),] # notice it is a numeric, not character order
b x y z sort
2 chr1 D 3 11
1 chr2 A 8 12
4 chr13 C 9 2 1
On May 20, 2010, at 3:38 AM, nuncio m wrote:
Dear All,
I am very new to T. I need to fit a ARIMA model to my time
series. So I found the auto correlation functions and partial auto
correlation function in R. Now I want to save these valuse along
with the
significance levels to a fi
On May 20, 2010, at 8:17 AM, Ivan Calandra wrote:
Hi,
I think that one of the cex arguments in par() can be what you're
looking for. But since I've never plotted any dendrogram, I don't
know which one, if any.
?par
Appears that the first effort should be to use cex.lab = 0.3 or some
su
Try this.
dd[order(gsub("chr","",dd$b)),]
You need regular expressions if chr is not the only characterstring
that is prepended to the numbers.
look for
?strsplit
Nikhil Kaza
University of North Carolina
nikhil.l...@gmail.com
On May 20, 2010, at 8:28 AM, Yuan Jian wrote:
Hello,
I have
The solution given by Jim is more correct
dd[order(as.numeric(substr(dd$b,4,5))),]
regards
M
jim holtman a écrit :
dd
b x y z
1 chr2 A 8 1
2 chr1 D 3 1
3 chr15 A 9 1
4 chr13 C 9 2
# add column with just numbers
dd$sort <- as.integer(gsub("\\D+", "", dd$b))
dd[order(dd$sort),]
Hi again,
Have you also tried cex.lab? And values <0.8, maybe 0.5 or even 0.3?
Output as Pdf/Ps shouldn't be a problem, or is it?
I cannot help you more without a reproducible example (read the posting
guide, it's linked at the bottom of every email from the list), though
even with it, I'm no
On 05/20/2010 01:42 AM, Marc Carpentier wrote:
Thank you for your responses, but I don't think you're right about the doc...
I carefully looked at it before posting and ran the examples, looked in
Vanderbilt Biostat doc, and just looked again example(nomogram) :
1st example : categorical*contino
Hi Yuan,
Try
dd[order(as.numeric(gsub("[^0-9]", "", dd$b))), ]
HTH,
Jorge
On Thu, May 20, 2010 at 8:28 AM, Yuan Jian <> wrote:
> Hello,
>
> I have a dataframe:
> dd <- data.frame(b = c("chr2", "chr1", "chr15", "chr13"),
> x = c("A", "D", "A", "C"), y = c(8, 3, 9, 9),
>z = c(1, 1,
That would not work in "optim". The objective function must take in a
vector of parameters and return a scalar value. Your objective function
does not return a scalar.
This would work:
test <- function(x, ...){
m.error <- mean(distribution(x)) - observed.mean
sd.error <- std(distribution(x))
I got an offlist response saying my advice was not correct, not
surprising in the absence of a reproducible example on which to test.
Looking at the help page, which seems the sensible place for anyone to
start, we see that the second plotting example for dendrograms uses
lab.cex and it nee
On Thu, May 20, 2010 at 3:06 PM, Ivan Calandra
wrote:
> I've found the answer:
> get() is exactly what I need, I completely forgot about this function.
>
> There might be a better way, but that works for me.
I R.utils, there are saveObject() and loadObject(), which allows you
to save and load obj
Hi
Sorry to be honest, i hit reply before i realised!
Thanks a bunch!
It worked! I can visualise the labels!
Ayesha Jadoon
PhD student
PSD, FWB
Kings college London
SE1 9NH
UK
On Thu, May 20, 2010 at 2:38 PM, David Winsemius wrote:
> I got an offlist response saying my advice was not correct,
Hi Henrik,
Thank you for this suggestion, it does sound easier indeed!
Ivan
Le 5/20/2010 15:50, Henrik Bengtsson a écrit :
On Thu, May 20, 2010 at 3:06 PM, Ivan Calandra
wrote:
I've found the answer:
get() is exactly what I need, I completely forgot about this function.
There might be
Hello all,
I've been pouring through the various spatial packages, but haven't come
across the right thing yet.
Given a set of points in 2-d space X, i'm trying to find the subset of
points in Y proximate to each point in X. Furthermore, the proximity
threshold of each point in X differs (X$thre
On May 20, 2010, at 10:02 AM, Alexander Shenkin wrote:
Hello all,
I've been pouring through the various spatial packages, but haven't
come
across the right thing yet.
There is a SIG for such questions.
Given a set of points in 2-d space X, i'm trying to find the subset of
points in Y p
DeaR users.
These days i'm working on fitting an extended Cox model with
time-dependent covariables and possibly time-varying effects. My
data are in counting process format as described in Therneau&Grambsh's
`Modeling Survival Data', page 68. I'm trying to follow Harrell's
`Regression Modeling
Hi,
Is there a built in function that returns a character vector of all subclasses
of a given superclass?
showClass(Class = "SomeClass") contains the info that I want, but I don't know
how to access it.
getSubClasses <- function(superClass) return(setdiff(getClasses(.GlobalEnv),
superClass))
Hello,
I have a zoo time series object (say a) with the following time
stamp/format
[1] "1950-01-03 GMT" "1950-01-04 GMT" "1950-01-05 GMT" "1950-01-06 GMT"
[5] "1950-01-09 GMT" "1950-01-10 GMT"
and another (say b) with
[1] "1950-01-05" "1950-01-06" "1950-01-09" "1950-01-10" "1950-01-11"
On 05/20/2010 07:47 AM, Albert-Jan Roskam wrote:
> Hi,
>
> Is there a built in function that returns a character vector of all
> subclasses of a given superclass? showClass(Class = "SomeClass")
> contains the info that I want, but I don't know how to access it.
Hi Albert-Jan --
Maybe
> slotNam
try:
as.POSIXct(datestr, format="%y-%m-%d")
for the first timeseries...
-c
On 5/20/2010 10:48 AM, Research wrote:
Hello,
I have a zoo time series object (say a) with the following time
stamp/format
[1] "1950-01-03 GMT" "1950-01-04 GMT" "1950-01-05 GMT" "1950-01-06 GMT"
[5] "1950-01-09 GM
Dear Brian,
many thanks for reply it helped a great deal. But firstly an apology for
not providing the "at a minimum",my (newbe) error, sorry for making you
guess.
The info is/was:
> sessionInfo()
R version 2.10.0 (2009-10-26)
i386-pc-mingw32
locale:
[1] LC_COLLATE=German_Germany.1252 LC_CTYP
The warning message does tell you exactly what was wrong. You are
trying to merge zoo objects that have two different index classes.
The first is "POSIXct" and the second is "Date" class. Next time
please provide your data in reproducible form
as shown here:
> library(zoo)
> z1 <- zoo(1:6, as.D
Hi Martin,
Great, the second solution is precisely what I've been looking for. Thanks a
lot!
Cheers!!
Albert-Jan
~~
All right, but apart from the sanitation, the medicine, education, wine, public
order, irrigation, roads, a f
On 5/20/2010 9:18 AM, David Winsemius wrote:
>
> On May 20, 2010, at 10:02 AM, Alexander Shenkin wrote:
>
>> Hello all,
>>
>> I've been pouring through the various spatial packages, but haven't come
>> across the right thing yet.
>
> There is a SIG for such questions.
thanks - just joined it.
dear R wizards:
not important. more a curiosity or esthetics question.
is there a way to extend the standard lm command, so that it takes a new
argument that handles fixed effects? right now, I have (provided to me
from an expert---I would have never figured this one out):
diffid <- functi
Hello,
Let's say that I have a data frame of n numbers I want to transfer
into a Excel spreadsheet. I have opened the conection to the file
using ODBC, and I can query the content of these n cells without
problem. However, how do I transfer my new values to these cells?
I.e., overwite them.
Shoul
Hi,
Thanks for the inputs. I talked to my coworker, who has been the one doing
the analysis. Perhaps I wasn't making myself clear about the “differences in
spatial scales”. Here is what he says:
"The truth is that measuring scales (i.e all area related variable are
measured in m2) and spatial d
Try, ofr a factor:
> x <-c("A","B","C")
> x <- factor(x)
> levels(x)
[1] "A" "B" "C"
> x <- factor(x,levels=levels(x)[c(3,2,1)])
> levels(x)
[1] "C" "B" "A"
Rock, DRF
--
View this message in context:
http://r.789695.n4.nabble.com/factor-tp879983p2224639.html
Sent from the R help mailing list a
On Wed, 19 May 2010, Sabatier, Jennifer F. (CDC/OID/NCHHSTP) wrote:
Hi R-help,
Yes, this is my second request for assistance in a single day
I am attempting to use svychisq() inside a function I made. The goal
of this function is to produce a table of summary statistics that I can
later
Hi R-help,
I posted about this late yesterday but got no response. I may have put
TMI in the original request. Not to mention I couldn't cut and paste
yesterday because I was working R off a non-network computer while
asking for help on a network computer.
Essentially, I have this user-define
On Thu, 20 May 2010, ivo welch wrote:
dear R wizards:
not important. more a curiosity or esthetics question.
is there a way to extend the standard lm command, so that it takes a new
argument that handles fixed effects? right now, I have (provided to me
from an expert---I would have never fi
Dear List,
I'd like to call pyhton function from within R. I tried installing the latest
version of RSPython:
wget http://www.omegahat.org/RSPython/RSPython_0.7-1.tar.gz
R CMD INSTALL --clean RSPython_0.7-1.tar.gz
I get a compile error (posted below).
Did anyone else run against this ? Is the
Dear R-Experts, Dear friends of dung.
I have a statistical Problem, to which nobody I asked could give me an answer.
Maybe you can.
I was in the African-Savanna and made a Dung-Monitoring. This means I walked
randomly over the field and for every Dung-Event I found I noted following
parameters
hi thomas---
thanks for the answer. the problem with the "+factor(fmid)" is not just
that it provides uninteresting coefficients and that it eats more memory,
but that it is also MUCH slower when there are (hundred of) thousands of
fixed effects.
Does Bill Venables describe how to do extend the
kaveh vakili ulb.ac.be> writes:
>
> Dear List,
>
> I'd like to call pyhton function from within R. I tried installing the latest
> version of RSPython:
>
> wget http://www.omegahat.org/RSPython/RSPython_0.7-1.tar.gz
> R CMD INSTALL --clean RSPython_0.7-1.tar.gz
>
> I get a compile error (po
Dear R-users,
I've recently switched to Ubuntu and I've decided to use Kate to edit my
R code. I really like how Kate allows one to simply pipe their code to
the terminal. However, I would find it even better if I could actually
get the Kate console to display error messages (or any console ou
On Thu, May 20, 2010 at 3:20 PM, Lucia Rueda wrote:
>
> Hi,
>
> Thanks for the inputs. I talked to my coworker, who has been the one doing
> the analysis. Perhaps I wasn't making myself clear about the differences
> in
> spatial scales. Here is what he says:
>
> "The truth is that measuring sc
Dear group,
I am trying to write functions, but as a beginner, everything is not so
obvious.
Let's say I want the results in a list of elemts like this :
tot1, tot2, etc
Here is a function:
toto <-
function(x,y)
{
for(i in x:y){
paste(c("tot",i),collapse="")<-(i*2)
}
}
If I type this :
>to
Try this:
paste("tot", 4:16, sep = "")
Or:
func <- function(x,y)
{
paste("tot", x:y, sep = "")
}
func(4,16)
Contact
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On Thu, 20 May 2010, ivo welch wrote:
hi thomas---
thanks for the answer. the problem with the "+factor(fmid)" is not just
that it provides uninteresting coefficients and that it eats more memory,
but that it is also MUCH slower when there are (hundred of) thousands of
fixed effects.
There i
Hello,
I'm having trouble discovering what's going wrong with my use of natural
joins via sqldf.
Following the instructions under 4i at http://code.google.com/p/sqldf/,
which discusses creating indices to speed joins, I have been only unreliably
able to get natural joins to work.
For example,
>
this is self-reply only to insert my real name
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
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Dear R experts,
I have a question about the result of difftime() function: Does it
take into account the different number of days in each month. In my
example, I have the following:
> firstDay
[1] "2010-02-20"
> lastDay
[1] "2010-05-20 16:00:00"
> difftime(lastDay,firstDay,units='days')
Time diff
On 2010-05-20 08:52, Shi, Tao wrote:
Will,
I'm wondering if you have any
insights after looking at the cor.test source code. It seems to be fine to me, as the p
value is either calculated by "your first method" or a
.C code.
...Tao
Dear Tao,
I think the described problem of p-values < 2.
On May 20, 2010, at 11:12 AM, Alexander Shenkin wrote:
On 5/20/2010 9:18 AM, David Winsemius wrote:
On May 20, 2010, at 10:02 AM, Alexander Shenkin wrote:
Hello all,
I've been pouring through the various spatial packages, but
haven't come
across the right thing yet.
There is a SIG for
Hi,
the problem is not about the environment, but about the
paste(c("tot", i), collapse = "")
which is not recognized as an object.
Maybe assign() could do the trick
You could also do it this way (though it's not exactly what you want,
but it might be better):
toto <- function(x,y){
tot
The "breakpoint" you mentioned is irrelevant here. Clustering 15672
genes (I assume this is a microarray data) requires lots of memory. I
suggest you either filter your gene list down to thousands or just plot
the column dendrogram without showing the heatmap.
plot(hclust(dist(x)))
...Tao
There are two problems:
1. A natural join will join all columns with the same names in the two
tables and that includes not only Tid but also dfName and since there
are no rows that have the same Tid and dfName the result has zero
rows.
2. the heuristic it uses fails when you retrieve the same co
On May 20, 2010, at 11:08 AM, Stella Pachidi wrote:
> Dear R experts,
>
> I have a question about the result of difftime() function: Does it
> take into account the different number of days in each month. In my
> example, I have the following:
>
>> firstDay
> [1] "2010-02-20"
>> lastDay
> [1] "2
Dne Čt 20. května 2010 17:50:42 Luc Villandre napsal(a):
> Dear R-users,
>
> I've recently switched to Ubuntu and I've decided to use Kate to edit my
> R code. I really like how Kate allows one to simply pipe their code to
> the terminal. However, I would find it even better if I could actually
>
Dear list,
I´m calculating time differences between series of time stamps and I noticed
something odd:
If I do this...
> time1=strptime("2009 05 31 22 57 00",format="%Y %m %d %H %M")
> time2=strptime("2009 05 31 23 07 00",format="%Y %m %d %H %M")
>
> diff(c(time1,time2),units="mins")
Time differ
We've scheduled more R courses for June 2010 in Washington DC,
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May - June 2010
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*** R Fundamentals and Programming Techniques
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Although that works I had meant to write:
> names(B)[2] <- "dfNameB"
> # ... other commands
> sqldf('select * from main.A natural join main.B')
so that now only Tid is in common so the natural join just picks it up
and also the heuristic works again since we no longer retrieve
duplicate column na
I know this was asked and answered in 2005, I just want to make sure the
answer still holds in 2010.
Question:
If I have the mixed-model with
lmer( y ~ x1 + x2 + (1 | id) + (z1 | w ) , ... )
there is no way for me to specify a correlation structure for the random
effects? Right?
If I want to s
Please provide information as to what version you are using; works fine for me:
> time3=strptime("2009 06 01 00 47 00",format="%Y %m %d %H %M")
> time4=strptime("2009 06 01 00 57 00",format="%Y %m %d %H %M")
>
> diff(c(time3,time4))
Time difference of 10 mins
>
I have version 2.10.1
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