That's what I am looking for. Thanks for being so helpful, I appreciate it
very much.
On Sun, Feb 23, 2014 at 10:16 PM, Gabor Grothendieck <
ggrothendi...@gmail.com> wrote:
> On Sun, Feb 23, 2014 at 9:06 PM, C W wrote:
> > Is there a way to rbind this? Do I have to use use a package like 'zoo
On Sun, Feb 23, 2014 at 9:06 PM, C W wrote:
> Is there a way to rbind this? Do I have to use use a package like 'zoo' and
> merge()?
>
> p <- predict(model, data.frame(t = 1, q = factor(1, 1:4))
> rbind(tsdat, p)
>
If you want to append this to the end of the series then try this:
ts(c(tsdat,
Is there a way to rbind this? Do I have to use use a package like 'zoo'
and merge()?
p <- predict(model, data.frame(t = 1, q = factor(1, 1:4))
rbind(tsdat, p)
On Sun, Feb 23, 2014 at 8:43 PM, C W wrote:
> I guess this is for anyone in the future.
>
> > predict(model, data.frame(t = 1, q = fac
I guess this is for anyone in the future.
> predict(model, data.frame(t = 1, q = factor(1, 1:4))
This would be the answer. Thanks again, Gabor!
Mike
On Sun, Feb 23, 2014 at 8:23 PM, Gabor Grothendieck wrote:
> On Sun, Feb 23, 2014 at 7:40 PM, C W wrote:
> > Gabor,
> > Your response worked p
On Sun, Feb 23, 2014 at 7:40 PM, C W wrote:
> Gabor,
> Your response worked perfectly, list(t = 1, q = factor(1, 1:4) was what I
> couldn't figure out. Thank you.
>
> In predict.lm(model, newdata), 2nd argument MUST be data.frame(). Why does
> list() also work?
>
Yes, it would be better to use
Gabor,
Your response worked perfectly, list(t = 1, q = factor(1, 1:4) was what I
couldn't figure out. Thank you.
In predict.lm(model, newdata), 2nd argument MUST be data.frame(). Why does
list() also work?
Mike
On Sun, Feb 23, 2014 at 7:32 PM, Gabor Grothendieck wrote:
> On Sun, Feb 23, 20
On Sun, Feb 23, 2014 at 7:25 PM, C W wrote:
> Gabor,
> Let me change newdata since it's confusing.
>
> Suppose I want to predict, year 1990, and quarter 2.
>> newdata <- data.frame(c(1990, 1, 0, 0)
>
> Since Q1 is a baseline, we will only see Q2, Q3, Q4. So, 4 parameters in
> total.
>
The formul
Gabor,
Let me change newdata since it's confusing.
Suppose I want to predict, year 1990, and quarter 2.
> newdata <- data.frame(c(1990, 1, 0, 0)
Since Q1 is a baseline, we will only see Q2, Q3, Q4. So, 4 parameters in
total.
Mike
On Sun, Feb 23, 2014 at 7:13 PM, Gabor Grothendieck wrote:
>
On Sun, Feb 23, 2014 at 6:56 PM, C W wrote:
> Gabor,
> I want the new data to be this,
> newdata <- data.frame(c(1, 0, 0, 0))
>
Its not clear what this means. There are two input variables so we
must specify two inputs.
For example, this would get the prediction for t=1 and for level 1 of
q whic
Gabor,
I want the new data to be this,
newdata <- data.frame(c(1, 0, 0, 0))
Here the code with the new data,
> dat <- rnorm(20)
> tsdat <- ts(dat, start=c(1900, 1), freq=4)
> q <- as.factor(rep(1:4, 5))
> t <- 1:20
> lm(tsdat~t+q)
Call:
lm(formula = tsdat ~ t + q)
Coefficients:
(Intercept)
On Sun, Feb 23, 2014 at 6:34 PM, C W wrote:
> Hello,
> I don't know how to use predict.lm() for ts object.
>
> Here's the time series regression.
> y = t + Q1 + Q2 + Q3 + Q4
>
> Here's my R code,
>
>> dat <- rnorm(20)
>> tsdat <- ts(dat, start=c(1900, 1), freq=4)
>> q <- as.factor(rep(1:4, 5))
>>
Hello list,
Does predict.lm() take ts object. I am aware that it requires data to come
in data.frame
Here's the time series regression.
y = t + Q1 + Q2 + Q3 + Q4
Here's my R code,
> dat <- rnorm(20)
> tsdat <- ts(dat, start=c(1900, 1), freq=4)
> q <- as.factor(rep(1:4, 5))
> t <- 1:20
> lm(ts
Hello,
I don't know how to use predict.lm() for ts object.
Here's the time series regression.
y = t + Q1 + Q2 + Q3 + Q4
Here's my R code,
> dat <- rnorm(20)
> tsdat <- ts(dat, start=c(1900, 1), freq=4)
> q <- as.factor(rep(1:4, 5))
> t <- 1:20
> lm(tsdat~t+q)
Call:
lm(formula = tsdat ~ t + q)
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