Is there a way to rbind this? Do I have to use use a package like 'zoo' and merge()?
p <- predict(model, data.frame(t = 1, q = factor(1, 1:4)) rbind(tsdat, p) On Sun, Feb 23, 2014 at 8:43 PM, C W <tmrs...@gmail.com> wrote: > I guess this is for anyone in the future. > > > predict(model, data.frame(t = 1, q = factor(1, 1:4)) > > This would be the answer. Thanks again, Gabor! > > Mike > > > On Sun, Feb 23, 2014 at 8:23 PM, Gabor Grothendieck < > ggrothendi...@gmail.com> wrote: > >> On Sun, Feb 23, 2014 at 7:40 PM, C W <tmrs...@gmail.com> wrote: >> > Gabor, >> > Your response worked perfectly, list(t = 1, q = factor(1, 1:4) was >> what I >> > couldn't figure out. Thank you. >> > >> > In predict.lm(model, newdata), 2nd argument MUST be data.frame(). Why >> does >> > list() also work? >> > >> >> Yes, it would be better to use a data.frame here to be consistent with >> the documentation even though a list does work. >> >> -- >> Statistics & Software Consulting >> GKX Group, GKX Associates Inc. >> tel: 1-877-GKX-GROUP >> email: ggrothendieck at gmail.com >> > > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.