I guess this is for anyone in the future. > predict(model, data.frame(t = 1, q = factor(1, 1:4))
This would be the answer. Thanks again, Gabor! Mike On Sun, Feb 23, 2014 at 8:23 PM, Gabor Grothendieck <ggrothendi...@gmail.com > wrote: > On Sun, Feb 23, 2014 at 7:40 PM, C W <tmrs...@gmail.com> wrote: > > Gabor, > > Your response worked perfectly, list(t = 1, q = factor(1, 1:4) was what > I > > couldn't figure out. Thank you. > > > > In predict.lm(model, newdata), 2nd argument MUST be data.frame(). Why > does > > list() also work? > > > > Yes, it would be better to use a data.frame here to be consistent with > the documentation even though a list does work. > > -- > Statistics & Software Consulting > GKX Group, GKX Associates Inc. > tel: 1-877-GKX-GROUP > email: ggrothendieck at gmail.com > [[alternative HTML version deleted]] ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.