thanks rui, it helps indeed..
at first, I've been trying to data.frame the output of mean (mycenfit)
by the following:
my.df<-as.data.frame(do.call(rbind, mean(mycenfit)))
and it worked out correctly!
...but because I also needed the information about "n" and "n.cen",
which are not provided b
Great. Thanks AK.
On Thursday, April 10, 2014 11:14 PM, arun wrote:
Hi,
Ok, In that case,
change `lst1New`. Also, in your files, there was no "Sim" column. So, I
changed the name.
lst1New <- lapply(lst1,function(x) {lst2 <- setNames(lapply(x,function(y) {dat
<- read.table(y,sep=" ",head
Hi,
Ok, In that case,
change `lst1New`. Also, in your files, there was no "Sim" column. So, I
changed the name.
lst1New <- lapply(lst1,function(x) {lst2 <- setNames(lapply(x,function(y) {dat
<- read.table(y,sep=" ",header=TRUE, stringsAsFactors=FALSE);names(dat)[5] <-
"Sim"; dat[,1:5]}),na
I think you have calculated the wrong probabilities. Shouldn't it be
> x <- c(2,2,6,2,1,1,1,3)
> MASS::fractions(table(x)/length(x))
x
1 2 3 6
3/8 3/8 1/8 1/8
>
Yours sincerely / Med venlig hilsen
Frede Aakmann Tøgersen
Specialist, M.Sc., Ph.D.
Plant Performance & Modeling
Technology
Thank you very much for both of you!
Cheers,
Sheng
On Thu, Apr 10, 2014 at 7:02 PM, Erin Hodgess wrote:
> thank you! Just wanted to make sure.
>
>
> On Thu, Apr 10, 2014 at 6:00 PM, Uwe Ligges <
> lig...@statistik.tu-dortmund.de
> > wrote:
>
> >
> >
> > On 11.04.2014 00:36, Erin Hodgess wrote:
Yes, the initial question is answered and the code works.
I suppose that I should not have added more to it.
I should have posted a new topic.
Sorry that I am not at all an R user.
Just trying to determine if I want to use it.
I just read your link.
Sorry to be more stupid than you expect.
I did no
Hi Steve,
Thanks for you reply. I have tried what you suggested and checked the limma
guide sessions. Now I am getting the results from only one treatment which
is great but the problem is all my adjusted Pvalues (adj.P.Val) are >0.05.
Don't really know how to solve this, I know my data works be
Peter
Your proposal appears to work better than expected:
On a 64-bit machine, it reported
64 when R64 was launched
32 when R62 was launched
On a 32-bit machine, it reported 32.
The underlying issue for me is that I am calling c code — I want t
Hi,
I'm inserting a ton of old trading history into the blotter package for
some analysis.
A bunch of the trades were for options (and a few for futures.) Blotter
uses the Financial Instruments package to define the meta-data, and
documentation there is clear on how to setup an option and relate
The behaviour that you get is exactly the behaviour that I, at least,
would expect, and it seems to me to be exactly the correct behaviour.
I do not understand what you are complaining about.
cheers,
Rolf Turner
On 11/04/14 06:31, ivo welch wrote:
I just spent about an hour bug-tracking.
thank you! Just wanted to make sure.
On Thu, Apr 10, 2014 at 6:00 PM, Uwe Ligges wrote:
>
>
> On 11.04.2014 00:36, Erin Hodgess wrote:
>
>> Hello!
>>
>> I like to build from source on Windows (64 bit).
>>
>> Will the Rtools be updated along with the new tar.gz file, please?
>>
>
> The Rtools p
On 11.04.2014 00:36, Erin Hodgess wrote:
Hello!
I like to build from source on Windows (64 bit).
Will the Rtools be updated along with the new tar.gz file, please?
The Rtools page tells us:
Rtools31.exeR 3.0.x to 3.1.x
So this is the right one...
Best,
Uwe Ligges
Thanks,
Erin
Hello!
I like to build from source on Windows (64 bit).
Will the Rtools be updated along with the new tar.gz file, please?
Thanks,
Erin
--
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: erinm.hodg...@gmail.com
I just spent about an hour bug-tracking. I had expected the following to
throw an error:
d <- data.frame( x=1:5, y=6:10 )
valid <- c(TRUE, FALSE)
d[valid,]
I understand that R recycles "when fit," but I had not expected it to
recycle, then truncate, and not give even a warning. maybe ther
But your original approach was more concise - just use unique() for the input
vector (since neither length nor order matter) and the probabilities:
a <- c(1,1,1,1,2,5)
set.seed(11235813)
out <- sample(unique(a), 100, replace=TRUE, prob = unique(a))
out
[1] 5 5 5 2 5 5 1 1 5 2 5 2 5 5 1 5 1 2
On Apr 10, 2014, at 5:58 AM, Kumsa wrote:
> I'm trying to produce a 3d plot with wireframe function or any other
> package in R . I want to show how z changes in response to x and y. But I
> fail to produce a 3d surfaceplot with a wireframe command which gives me
> different error messages.
Hi!
I am trying to do a glmer.nb but get this error:
Error in eval(expr, envir, enclos) :
..2 used in an incorrect context, no ... to look in
My data structure is data.frame
Here my data set: d1_2
Year ID Age Reproductive_status Rank_Residuals Asso.Y1 TotalY1
1994 109 8 Lactating 0.23947902 9 4
On 10 Apr 2014, at 16:49 , Alwina Hermann wrote:
> Dear R team,
>
> I'm not sure if I use the right distribution list, but I hope in case if
> not, you will forward it to the reference person.
>
> Following problem occured:
> I used R to calculate the p-value for the two sided binomial test
Sorry, there's a bug. merge() sorts the data.frame so we need to sort x
also.
sample(sort(x), 1, prob = prob)
Rui Barradas
Em 10-04-2014 21:34, Rui Barradas escreveu:
Hello,
Inline.
Em 10-04-2014 21:04, Nordlund, Dan (DSHS/RDA) escreveu:
-Original Message-
From: r-help-boun...@r-pr
Hello,
Inline.
Em 10-04-2014 21:04, Nordlund, Dan (DSHS/RDA) escreveu:
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Simone Gabbriellini
Sent: Thursday, April 10, 2014 11:59 AM
To: Rui Barradas
Cc: r-help@r-project.org
Subject:
I believe that b. is .Machine$sizeof.pointer*8.
I am not aware of a method to figure out the difficult part of a.: whether a 32
bit R is running on 64 bit Windows. I'd expect that you have to ask the OS
somehow. Google coughs up one or two interesting pointers.
-pd
On 10 Apr 2014, at 21:48
Look at
Sys.info()
R.version()
Hope this is helpful,
Dan
Daniel J. Nordlund, PhD
Research and Data Analysis Division
Services & Enterprise Support Administration
Washington State Department of Social and Health Services
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Simone Gabbriellini
> Sent: Thursday, April 10, 2014 11:59 AM
> To: Rui Barradas
> Cc: r-help@r-project.org
> Subject: Re: [R] how to select an element from a vector based on a
>
I think you are looking for analysis of covariance.
Try the ancova function in the HH package.
install.packages("HH")
library(HH)
?ancova
demo("ancova")
On Thu, Apr 10, 2014 at 10:48 AM, Patzelt, Edward wrote:
> R -
>
> I've got a DV with 2 IVs one of which has 5 levels. I tried using the
> "peq
Hi,
I use packages "momocs" and "ade4" to dertermine morphometry of
woodpeckers'
cavities entrances.
I have few questions about the PCA
(non-normalized) (see image enclosed) :
1) *What do show the confidence
ellipses ?* Some papers say that ellipses
include 95 % of the data, but it
seems
3.0.2
Windows
Colleagues,
If I am setting up code for others and I dont know their configuration, what
is the simplest way to find out the following within R:
a. is the system 32- or 64-bit?
b. if the system is 64-bit, is R 32- or 64-bit?
Dennis
Dennis Fisher MD
P < (The "P
Dear Friends
I am running some SDM to assess the potential distribution of some plant
species. We want to run 3 models using presence data only (BIOBLIM, DOMIAN,
MAHAL). I am using the Dismo library for R.
We would like to evaluate the three models using the AUC the Kappa COR
(Pearson correl
I'm trying to produce a 3d plot with wireframe function or any other
package in R . I want to show how z changes in response to x and y. But I
fail to produce a 3d surfaceplot with a wireframe command which gives me
different error messages.
## Generate data
x <- seq(from=0, to=100,by=1)
y <-
Hi,
We are planning to use R tool for one of the project. We would like to create
the dll .
My level is novice. Could you please help me to create the dll in R and how to
call the R dll in .Net.
Thanks for the support
Thanks,
Vijay
CAUTION - Disclaimer *
This
R -
I've got a DV with 2 IVs one of which has 5 levels. I tried using the
"pequod" package; however found that it is not able to graph/simple slope a
moderator with multiple levels. Is there a package available to do this?
(data below)
dat$gpa <- as.factor(dat$gpa)
mod1 <- lmres(item25 ~ psd * g
Dear R team,
I'm not sure if I use the right distribution list, but I hope in case if
not, you will forward it to the reference person.
Following problem occured:
I used R to calculate the p-value for the two sided binomial test (exact -
Pearson).
For a very little difference for my forecast I
Hello, Rui,
it does, indeed!
thanks,
Simone
2014-04-10 20:55 GMT+02:00 Rui Barradas :
> Hello,
>
> Use ?sample.
>
> sample(x, 1, prob = x)
>
> Hope this helps,
>
> Rui Barradas
>
> Em 10-04-2014 19:49, Simone Gabbriellini escreveu:
>
>> Hello List,
>>
>> I have an array like:
>>
>> c(4, 3, 5, 4,
Hello,
Use ?sample.
sample(x, 1, prob = x)
Hope this helps,
Rui Barradas
Em 10-04-2014 19:49, Simone Gabbriellini escreveu:
Hello List,
I have an array like:
c(4, 3, 5, 4, 2, 2, 2, 4, 2, 6, 6, 7, 5, 5, 5, 10, 10, 11, 10,
12, 10, 11, 9, 12, 10, 36, 35, 36, 36, 36, 35, 35, 36, 37, 35,
35, 38
Hello List,
I have an array like:
c(4, 3, 5, 4, 2, 2, 2, 4, 2, 6, 6, 7, 5, 5, 5, 10, 10, 11, 10,
12, 10, 11, 9, 12, 10, 36, 35, 36, 36, 36, 35, 35, 36, 37, 35,
35, 38, 35, 38, 36, 37, 36, 36, 37, 36, 35, 35, 36, 36, 35, 35,
36, 35, 38, 35, 35, 35, 36, 35, 35, 35, 6, 5, 8, 6, 6, 7, 1,
7, 7, 8, 9,
Group T Status Dear R users. I am trying to program the comp()
routine in package survMisc.
1 2081 0 I am reading the data on the left with
d=read.table( "C:\\e.t.c",fill=TRUE,header=TRUE)
1 1602 0 Then I load the packages 'survival' and
Hello,
Perhaps the easiest way is with ?capture.output:
dat <- read.table(text = capture.output(print(mycenfit)),
stringsAsFactors = FALSE)
str(dat)
'data.frame': 3 obs. of 5 variables:
$ n : int 3 3 3
$ n.cen : int 1 1 2
$ median: int 2 2 NA
$ mean : num 2.33 2.33 2
$ sd
given this reproducible example:
#start code
df<-structure(list(lq = c(TRUE, FALSE, TRUE, FALSE, TRUE, FALSE, TRUE,
FALSE, FALSE), value = c(1, 3, 1, 2, 0.5, 2, 1, 2, 3), group =
structure(c(1L, 1L, 2L, 2L, 3L, 3L, 3L, 1L, 2L), .Label = c("A", "B",
"C"), class = "factor")), .Names = c("lq", "v
On 10 Apr 2014, at 16:59 , Paul Johnson wrote:
> I've been reading quite a while on this question, testing lots of
> ideas. The quote function seems to work, but I worry about how the R
> runtime environment finds all the pieces if I pass them through this
> way.
>
> mySpecialFeature <- functio
Dear eveRybody
In the package rockchalk, I have functions that take regressions and
make tables and plots. Sometimes I'll combine a model with various
arguments and pass the resulting list around to be executed, usually
using do.call. While debugging a function on a particularly large
dataset, I
Ok, that is why i have suspected.
Thanks for the clear explanation.
[]s
Cassiano
2014-04-09 18:37 GMT-03:00 Peter Langfelder :
> On Wed, Apr 9, 2014 at 11:27 AM, Cassiano dos Santos
> wrote:
> > I am testing a call to a C function from R, using .C interface. The test
> > consists in passing
I am probably going to push it to CRAN today or tomorrow.
Bill
On Apr 10, 2014, at 1:22 AM, sagnik chakravarty wrote:
> Thanks a lot Bill and Revelle for your helpful response.
> It would have been great if I could know when we can expect the release of
> the edited version 1.4.4.
>
> Sagnik
Thanoon,
My reply to your previous post should be more than enough for you to
accomplish your goal. Please look over that script again:
ords <- seq(4)
p <- 10
N <- 1000
percent_change <- 0.9
R <- as.data.frame(replicate(p, sample(ords, N, replace = T)))
or alternatively as Mr. Barradas suggest
In traditional R graphics I can generate text annotations that are
vertical, and that lie outside the plot region, using the mtext function.
I'd like to do the same thing in ggplot2. Is it possible? The documentation
for 'annotate' does not mention such possibilities.
Thanks.
[[alternati
Hi all,
Can anyone please explain the following results (why does median()
work here but not mean())? Is there a fix or work around for this?
Thanks,
Dan
> by(urpdata[,2],urpdata[,12],mean,na.rm=TRUE)
Error in FUN(X[[1L]], ...) : could not find function "FUN"
> by(urpdata[,2],urpdata[,12],med
>
> Message: 11
> Date: Wed, 09 Apr 2014 18:39:30 +0100
> From: Michael Dewey
> To: Julien Riou , r-help@r-project.org
> Subject: Re: [R] Meta-analysis of prevalence at the country level with
> mgcv/gamm4
> Message-ID:
> Content-Type: text/plain; charset="us-ascii"; format=flowed
>
Hi M
Hello!
I am sorry if my question sounds naive; it's because I am not a computer
scientist.
I understand that two factors impact a PC's speed, the processor and
(indirectly), the RAM size.
I would like to run a speed test in R (under Windows). I found lots of
different code snippets testing the sp
(Resend with correct Subject field.)
The build system rolled up R-3.1.0.tar.gz (codename "Spring Dance") this
morning.
The list below details the changes in this release.
You can get the source code from
http://cran.r-project.org/src/base/R-3/R-3.1.0.tar.gz
or wait for it to be mirrored at a
The build system rolled up R-3.1.0.tar.gz (codename "Spring Dance") this
morning.
The list below details the changes in this release.
You can get the source code from
http://cran.r-project.org/src/base/R-3/R-3.1.0.tar.gz
or wait for it to be mirrored at a CRAN site nearer to you.
Binaries for
Hello,
At an R prompt type
?rbinom
?replicate
Hope this helps,
Rui Barradas
Em 10-04-2014 02:28, thanoon younis escreveu:
hi
i want to simulate multivariate dichotomous data matrix with categories
(0,1) and n=1000 and p=10.
thanks alot in advance
[[alternative HTML version deleted
Hi
Your approach seems to be rather complicated. Just change your values into NA.
data$ej[data$ej=="-97"] <- NA
Then you can use is.na function to select and replace na values. However it
seems to me that your data are not numeric and I am not sure if it is intended
or not.
If you want mo
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