Hi,
I am new to R, I need your help. I have been said to create a GUI in
R,
I started using Tcltk package which was very easy to learn and code,
but i am unable to arrange the GUI's in proper order in the window
they are always arranged one below the other, please can anyone hel
Dear Uwe,
I appreciate that if you let me know why, when using the attached file, the
following script (two lines) doesn't work once in 10s of times.
Best, Reza
svm.pol4 <- ksvm(class.labs ~ ., data = train.data, prob.model = T, scale =
T, kernel = "polydot")
svm.pol.prd4 <- predict(svm.pol4, tra
Grace:
Confession: I loved that error message! -- and it seems pretty clear to me.
What does "to no avail" mean -- in particular, what happened when you
changed your NA's to 0? Presumably you did not get the same error
message, again, but something else, right? What else?
Modulo the above vague
Dear all,
I have two vectors
x <- c(1:20)
y <- c(1,5,10,14)
Now I would like to extract
x[ (y[n] + 2):(y[n+1] - 1) ]
for all elements except last one in y. This means I want to have
x[ c( (y[1]+2):(y[2]-1), (y[2]+2):(y[3]-1), (y[3]+2):(y[4]-1) ) ]
How is this possible if y is a vector of
HI,
I have this code:
BAGA <- c(10,20,20,30,30,30,30,40,
40,40,40,50,50,50,50,50,
60,60,60,60,60,70,70,70,
70,80,80,80,90,90,100)
BAGB <- c(10,10,10,10,10,20,20,20,
20,30,30,30,40,40,50,60,
70,70,80,80,80,90,90,90,
90,100,100,100,100
*Hi all,*
I'm trying to filter a file through the columns. This file below is a
example of my data frame. My true data frame has seven hundred thousand
columns and 500 hundred lines. I need to identify and to remove all columns
that all elements equal a number 1. In this my case, columns were de
On Aug 24, 2012, at 2:34 AM, Michael Meyer wrote:
Greetings,
I would like to plot a curve (in color red) on a surface in a 3D plot.
Say
x <- as.vector(seq(-1,1,0.2))
dim(x) <- c(length(x),1)
y <- as.vector(seq(-1,1,0.2))
dim(y) <- c(1,length(y))
z <- x%*%y # (x_
Three steps:
1) as.character to get character representation
2) as.POSIXct to convert to time
3) julian() or strptime() to get Julian date.
Read the docs (esp on part 2 and 3) to get the format strings just right.
Cheers,
Michael
On Aug 24, 2012, at 10:30 PM, Veerappa Chetty wrote:
> Hi,
>
Hi,
I have dates as follows:
1/4/2006 0:00:00 AM
It is a factor at present.
How do I find out the day of the week from this? How do I convert to Julian
date format?
Thanks.
Chetty
--
Professor of Family Medicine
Boston University
Tel: 617-414-6221, Fax:617-414-3345
emails: chett...@gmail.com,vc
You probably mean shQuote().
Regards,
Yihui
--
Yihui Xie
Phone: 515-294-2465 Web: http://yihui.name
Department of Statistics, Iowa State University
2215 Snedecor Hall, Ames, IA
On Fri, Aug 24, 2012 at 3:17 PM, Roebuck,Paul L wrote:
> On 8/24/12 2:59 PM, "R. Michael Weylandt"
> wrote:
>
>> On
Hah - I guess I didn't mean I understood it in full as I expect I will
run into it again without anticipating it.
But, now that I know the "old adage" I will look there first when I
run into a problem.
Also, I used the square root of machine precision instead - thanks for
that, too.
Thank you, t
On Fri, Aug 24, 2012 at 7:29 PM, Jennifer Sabatier
wrote:
> AHHH I GOT IT!!
>
> And I *think* I understand about floating point arithmetic..
Well then you're doing much better than the rest of us: it's quite a
difficult subject and only gets trickier as you think about it more.
(N
AHHH I GOT IT!!
And I *think* I understand about floating point arithmetic..
In this case vn$PM.DIST.TOT is the sum of proportions. So, it should
be anywhere 0 and 1.
In our case, if it's anything other than 1 when vn$PM.EXP is greater
than 0 then it means something is wrong wi
Sam,
Thanks for pointing this out, but I have to point out in turn that this isn't
a SparseM function,
it is part of the package e1071, maintained by David Meyer.
Roger
Roger Koenker
rkoen...@illinois.edu
On Aug 24, 2012, at 3:07 PM, Sam Steingold wrote:
> read.matrix.csr does not close
I see that you got other responses while I was composing an answer.
Your 'example.csv' did come through for me, but I still can't
replicate your PM.DIST_flag variable. Specifically, observations
30, 33, 36 and 40 are wrong.
I agree with Rui, that there's something else going on. The data
you've s
Hi,
You missed a close bracket.
node4:{
...
nodeDef:{
node4:{
...
# need a close bracket here
}
},
--
Noia Raindrops
noia.raindr...@gmail.com
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PLEASE
Hi there,
I'm using presence-absence data in a gam (i.e. 0 or 1 as values)
I am trying to run a gam with 'dummy covariates' i.e. 1~1
unfortunately my model:
*
model<-gam(1~1, data=bats, family=negbin)*
keeps putting out:
*
Error in gam(1 ~ 1, data = bats, family = negbin) :
Not enough (non-NA
Hi Michael,
Thanks for letting me know how to post data. I will try to upload it
that way in a second.
I can usually use code to make a reproducible dataset but this time
with the ifelse behaving strangely (perhaps, it's probably me) I
didn't think I could do it easily so I figured I would just
Oh, sorry, I first though you couldn't post data to the list, but then
I thought I remembered other people doing so, so I tried to post it.
Here is a copy.
Thanks,
Jen
On Fri, Aug 24, 2012 at 5:49 PM, Rui Barradas wrote:
> No data arrived to me.
>
> Rui Barradas
> Em 24-08-2012 22:46, Jennifer
On Fri, Aug 24, 2012 at 4:50 PM, R. Michael Weylandt
wrote:
> On Fri, Aug 24, 2012 at 4:46 PM, Jennifer Sabatier
> wrote:
>> Hi Michael,
>>
>> No, I never use attach(), exactly for the reasons you state. To do
>> due diligence I did a search of code for the function and it didn't
>> come up (I w
On Fri, Aug 24, 2012 at 4:46 PM, Jennifer Sabatier
wrote:
> Hi Michael,
>
> No, I never use attach(), exactly for the reasons you state. To do
> due diligence I did a search of code for the function and it didn't
> come up (I would have been shocked because I never us it!).
>
> Now that real data
No data arrived to me.
Rui Barradas
Em 24-08-2012 22:46, Jennifer Sabatier escreveu:
Hi Michael,
No, I never use attach(), exactly for the reasons you state. To do
due diligence I did a search of code for the function and it didn't
come up (I would have been shocked because I never us it!).
N
Hi Michael,
No, I never use attach(), exactly for the reasons you state. To do
due diligence I did a search of code for the function and it didn't
come up (I would have been shocked because I never us it!).
Now that real data is up, does your suggestion still apply? I am
reading it now.
Thanks
Hi All,
has anyone run into maximum depth of nested JSON arrays in either rjson or
RJSONIO ?
I seem to be able to get up to 10 depth levels without problem, but
crossing over to 11 either causes an error or fails to load the nodes
properly.
with RJSONIO I tried:
a = fromJSON('data/myJSON.json',
Off the wall / wild guess, do you use attach() frequently? Not
entirely sure how it would come up, but it tends to make weird errors
like this occur.
M
On Fri, Aug 24, 2012 at 4:36 PM, Jennifer Sabatier
wrote:
> Hi Rui,
>
> Thanks so much for responding but I think with my HTML problem the vn
>
Hi Rui,
Thanks so much for responding but I think with my HTML problem the vn
data you made must not be the same. I tried running your code on the
data (I uploaded a copy) and I got the same thing I had before.
Jen
On Fri, Aug 24, 2012 at 5:28 PM, Rui Barradas wrote:
>
> 165114 1 0 0 0 0 417
On 8/24/12 4:02 PM, "Matthew K. Hettinger" wrote:
> I looked in the archives and couldn't find anything that really
> addressed my question so here it is -
>
> Does anyone know of any web sites/environments that hosts R for free,
> web-based, multi-user access to the R engine. My apologies if th
BTW - no one else who has replied to this topic was snobby or
unfriendly and I thank you very much for trying to help me.
It's just Bert is not the first to respond to my request for help as
such. As someone looking forward to becoming an advanced R programmer
in my statistical work it is discour
Hello,
Michael's standard guess, FAQ 7.31, was also mine, but is wrong. The
error is in Jennifer's flag column, not the result of her ifelse. (!)
x <- scan(what="character", text="
PM.EXP PM.DIST.TOT PM.DIST_flag 0 0 0 0 0 0 0 0 0 177502 1 0 31403 1
0 0 0 0 1100549 1 0 38762 1 0 0 0
Hi Peter,
I'm really sorry, I thought I was in plain text. I don't use any
formatting in my emails and in Gmail the HTML looks the same as plain
text.
Anyway, I've attached the data (I didn't think we could do that but I
am frequently wrong).
I say many cases because this is just a subset of >3
Bert,
I will thank you not to condescend to me, as I am too damn old (40) to
be treated that way. You didn't even offer a solution to my problem.
You only came to chastise me with regards to your assumptions about
me, which is very annoying.
While I am at the beginner level of R, I am not an idi
On 2012-08-24 13:22, Jennifer Sabatier wrote:
Hi R-Helpers,
I don't think I need to post a dataset for this question but if I do, I
can. Anyway, I am having a lot of trouble with the ifelse command.
Here is my code:
vn$PM.DIST_flag <- ifelse( (vn$PM.EXP > 0.0) & (vn$PM.DIST.TOT != 1.0), 1,
0
I looked in the archives and couldn't find anything that really
addressed my question so here it is -
Does anyone know of any web sites/environments that hosts R for free,
web-based, multi-user access to the R engine. My apologies if the
question is too simplistic for this forum. The reason I
Another strategy is to sort by month, id, and, in reverse order,
distance and select the rows that start each month/id run. This
can be much faster than the other ways when there are lots of
month/id combinations.
f1 <- function (DATA)
{
stopifnot(is.data.frame(DATA),
a
... and if Michael is correct, there is a lesson here: Think of how
much time and aggravation you would have saved yourself if you had
FIRST made an effort to read the docs. The FAQ's are there for a
reason. As is An Introduction to R, which also should be read before
posting on this list.
If Mich
Oops, sorry, I thought I was in plain text. I can't tell the
difference because I use so little formatting in my emails.
Try this (a truncated version since I have to hand space everything):
PM.EXP PM.DIST.TOT PM.DIST_flag
0 00
6417 1
On Fri, Aug 24, 2012 at 3:22 PM, Jennifer Sabatier
wrote:
> Hi R-Helpers,
>
> I don't think I need to post a dataset for this question but if I do, I
> can. Anyway, I am having a lot of trouble with the ifelse command.
>
You probably should have: dput() makes it super easy as well.
> Here is my
Hi R-Helpers,
I don't think I need to post a dataset for this question but if I do, I
can. Anyway, I am having a lot of trouble with the ifelse command.
Here is my code:
vn$PM.DIST_flag <- ifelse( (vn$PM.EXP > 0.0) & (vn$PM.DIST.TOT != 1.0), 1,
0 )
And here is my output that doesn't make ANY
On 8/24/12 2:59 PM, "R. Michael Weylandt"
wrote:
> On Fri, Aug 24, 2012 at 2:48 PM, Roebuck,Paul
> wrote:
>> [Redirected from R-Devel...]
>>
>> Not that I recall running across such, but does R (or CRAN package)
>> provide something equivalent to PHP's escapeshellcmd() function
>> to escape she
On 8/23/12 7:37 AM, "David Lyon" wrote:
> Can someone show me some code to do normalization by the median of some
> control genes for the example below?
> Many Many Thanks in advance
>
>
> This strategy selects a subset of genes (called ³control genes²) and makes the
> median of their data distri
read.matrix.csr does not close the connection:
> library('SparseM')
Package SparseM (0.96) loaded.
> read.matrix.csr(foo)
...
Warning message:
closing unused connection 3 (foo)
>
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000
http://www.childpsy.net/ http://
I don't know PHP, but what does escapeshellcmd() provide over and
above what system() / system2() do?
Cheers,
Michael
On Fri, Aug 24, 2012 at 2:48 PM, Roebuck,Paul L wrote:
> [Redirected from R-Devel...]
>
> Not that I recall running across such, but does R (or CRAN package)
> provide something
Hi all,
I am encountering an RODBC problem in R 2.15.1 in windows 64 bit which I do not
encountered in the same set up in windows 32 bit (the latest binary version of
RODBC in both cases from the same depository gotten by
install.packages(RODBC), Oracle ODBC client software installed in 64 an
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On Behalf Of Marc Schwartz
> Sent: Friday, August 24, 2012 12:06 PM
> To: ramoss
> Cc: r-help@r-project.org
> Subject: Re: [R] if then in R versus SAS
>
>
> On Aug 24, 2012, at 1:03 PM, ramos
[Redirected from R-Devel...]
Not that I recall running across such, but does R (or CRAN package)
provide something equivalent to PHP's escapeshellcmd() function
to escape shell job control, wildcards, etc?
__
R-help@r-project.org mailing list
https://st
On Aug 24, 2012, at 1:03 PM, ramoss wrote:
> I am new to R and I have the following SAS statements:
>
> if otype='M' and ocond='1' and entry='a.Prop' then MOC=1;
> else MOC=0;
>
> How would I translate that into R code?
>
> Thanks in advance
See ?ifelse and ?Logic, both of which are covere
I am new to R and I have the following SAS statements:
if otype='M' and ocond='1' and entry='a.Prop' then MOC=1;
else MOC=0;
How would I translate that into R code?
Thanks in advance
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View this message in context:
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Sent
Thanks for your reply, Jim.
On 8/24/2012 12:14 PM, jim holtman wrote:
> I think your first problem is the coersion done by 'c' when you are
> mixing objects of various types: you have POSIXct and character.
Yes, that's something I may have confounded. Still, the warning I'm
getting is "In as.POSI
Here's another pretty straightforward solution, using the plyr pkg:
DF <- data.frame(id, month, distance, bearing)
# variables as defined in the OP
require(plyr)
DF1<-ddply(DF, .(id,month), summarize,
maxdist = max(distance),
maxbearing = bearing[which.max(distance)])
Peter
I used summary <-rbind.fill(agency,prop) & it worked like a charm. Thanks
everyone.
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Sent from the R help mailing list archive at Nabble.com.
_
How do I read/write libsvm data into/from R?
The libsvm format is sparse data like
[ :]*
e.g.,
1 10:3.4 123:0.5 34567:0.231
0.2 22:1 456:03
The "foreign" library does not seem to provide the necessary functionality.
Any suggestions? Code?
Thanks!
http://stackoverflow.com/questions/12112558/
Hello,
Your example doesn't run, lmList needs a 'data' argument.
set.seed(8109)
d <- rep(1:10, each=10)
x <- rnorm(100)
e <- rnorm(100)
y <- 2*x + e
dat <- data.frame(x=x, y=y, d=d, e=e)
model <- lmList(y ~ x | d, data = dat)
predict(model)
To the op: if you already have the larger data.farme
I think your first problem is the coersion done by 'c' when you are
mixing objects of various types: you have POSIXct and character. What
were your expections?
> x <- Sys.time()
> str(x)
POSIXct[1:1], format: "2012-08-24 13:12:31"
> y <- c(x, 'b')
> str(y)
POSIXct[1:2], format: "2012-08-24 13:1
Hi,
I am interested in implementing a special variant of
balloonplot. Let me
explain with an example dataset from the reference manual :
library(gplots)
data(Titanic)
dframe<-as.data.frame(Titanic)
survived<-dframe[dframe$Survived=="Yes",]
attach(survived)
balloonplot(x=Class,y=list(Age,Sex),z=F
Or use ave() to compute the within-group ranks (reversed, so max has rank 1)
and select
the elements whose ranks are 1:
f2 <- function (DATA)
{
stopifnot(is.data.frame(DATA), all(c("distance", "id", "month") %in%
names(DATA)))
revRanks <- ave(DATA[["distance"]], DATA[["id"]], DAT
Hello,
You must post a data example to get some help. Use
dput( head(tth, 50) ) # paste the output of this in a post
As for the warnings, they are not errors. They are telling you that it
can't make a replacement. substitute(x) is probably returning NULL and
the aggregate return value's colu
On Thu, 23 Aug 2012, Gary Dong wrote:
I'm wondering if the gls function reports pseudo R. I do not see it by
summary(). If the package does not report, can I calculate it in this
way?
Adjusted pseudo R squared = 1 - [(Loglik(beta) - k ) / Loglik(null)] where
k is the number of IVs.
We've b
What are your expectations as to what
"length(names(tth$Mins.to.hospital))" should be returning? You need
to at least provide some data so we can reproduce the error, or
'str(tth)'. My guess is that tth$Mins.to.hospital does not have any
'names' attributes and therefore your error. So what is th
Hi everybody,
I have a question about applying a specific function (with the calculations
I want to do), on a list of elements.
Each elements are like a data.frame (with nrows and ncolumns), and have the
same structure.
At frist, I had a big data.frame that I splitted in all my elements of my
lis
Hello,
You don't need to write a function. Try the following.
nms <- paste0("species", 1:4)
mat <- matrix(rnorm(16), ncol=4, dimnames = list(nms, nms))
?dist
dist(mat)
dist(mat, diag = TRUE, upper = TRUE)
Hope this helps,
Rui Barradas
Em 24-08-2012 11:56, Arbuckle escreveu:
Hi,
I should pr
The easiest way may be to use lmList in the nlme library:
#simulate data
d<-rep(1:10,each=10)
x<-rnorm(100)
e<-rnorm(100)
y<-2*x+e
require(nlme) #or install and load package
lmList(y~x|d)
#predicted values are obtained with:
predict(lmList(y~x|d)
HTH,
Daniel
jeff6868 wrote
>
> Hi everyb
Thank you kindly for both of the replies I've received, that does indeed work
perfectly. I had been looking at the description of that function and it
reads as though it only deals with 2-dimensional data. Thanks again!
Kev
--
View this message in context:
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I'm very new to R and just finding my way, so be gentle!
I've hit a swift halt doing some summary statistics on a simple continuous data
field, divided into two categories. I'm getting the following error message. I
am unclear why length(names(tth$Mins.to.hospital)) is zero and how to alter
t
On Fri, Aug 24, 2012 at 12:48:54PM +0200, Frederik Bertling wrote:
> Hi,
>
> I'm doing some easy calculations to normalize some values. This looks like
> this:
>
> x=mean(a+b+c+d ...)
> a=a-x
> b=b-x
> c=c-x
> d=d-x
> ...
> mean(a+b+c+d ...) ---> Should now be 0!
> However, I'm getting results li
Hello folks,
I found a strangeness while experimenting with POSIXct vectors and
lists. It seems that coerced NA's aren't "real" NAs, at least as
considered by is.na()?
> date_vec = c(as.POSIXct(now()), as.POSIXct(now()+1),NA,"b")
> date_vec
[1] "2012-08-22 15:00:46 COT" "2012-08-22 15:00:47 COT"
Yes, the resources operating systems usually kill for are memory.
No, you have not provided a reproducible example. In general, you need to do
something different, such as choose a different algorithm, run on a different
computer, or split your problem into smaller pieces.
--
Kev,
The dist() function handles more than 2 dimensions.
Using the example you provided ...
mydat <- structure(list(Species = c("spA", "spB", "spC", "spD"),
x = c(2.9, 5.5, 1.4, 8.3),
y = c(34.2, 46.5, 48.6, 56.1),
z = c(0.54, 0.45, 0.84, 0.48),
n = c(15.7, 19.
Hello,
This is FAQ 7.31 Why doesn't R think these numbers are equal?
As for your second question whether this behavior is desirable I think
so, we should be aware that floating-point arithmetics has limits. In
your case, a precision limit. At an R pompt run the instructions
?.Machine
.Machin
Sorry, I just double checked and the options statement should be:
options(gsubfn.engine = "R")
Again, I am not sure if that is sufficient given that there is clearly
something wrong with your version of R.
On Fri, Aug 24, 2012 at 8:59 AM, Gabor Grothendieck
wrote:
> I have never seen that befor
I have never seen that before. It has been independently verified that
gsubfn works on Fedora Red Hat as you can see here:
http://cran.r-project.org/web/checks/check_results_gsubfn.html
The message about Tcl/Tk in your log suggests that there is something
wrong with your version of R itself. See
Dear Duncan,
many thanks for helping. It works fine.
Cheers,
Marius
Duncan Murdoch writes:
> On 12-08-19 3:47 PM, Marius Hofert wrote:
>> Dear Duncan,
>>
>> I recently asked a question concerning patchDVI on r-help, see
>>
>> ,
>> | https://stat.ethz.ch/pipermail/r-help/2012-August/321780
On Aug 24, 2012, at 5:48 AM, Frederik Bertling
wrote:
> Hi,
>
> I'm doing some easy calculations to normalize some values. This looks like
> this:
>
> x=mean(a+b+c+d ...)
> a=a-x
> b=b-x
> c=c-x
> d=d-x
> ...
> mean(a+b+c+d ...) ---> Should now be 0!
> However, I'm getting results like -2.3152
Silje,
Thanks for reporting this. Should be fixed for version 1.7-20 (but
please let me know if not!)
best,
Simon
On 14/08/12 12:08, silje skår wrote:
Hi,
I am using the gam function in the mgcv package, I have random effects in
my model (bs="re") this has worked fine, but after I updated t
Hi,
Do you try 'RSiteSearch("Branch Bound")'?
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and
Hi,
I should preface this problem with a statement that although I am sure this
is a really easy function to write, I have tried and failed to get my head
around writing functions in R. I can use R where functions exist to do what
I want done, but have found myself completely incapable of writing
Hi,
Is there a Branch and Bound routines or library for R?.
Thanks,
David
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and provide comment
Thanks for your reply.
Does what you said by resources mean memory or something else? Inside my
loop, I removed the objects that are created but not used by the next loop
and did garbage collection as well. Do you have any idea how I should
modify my code such that the system won't kill it? Thanks
Hi,
I'm doing some easy calculations to normalize some values. This looks like
this:
x=mean(a+b+c+d ...)
a=a-x
b=b-x
c=c-x
d=d-x
...
mean(a+b+c+d ...) ---> Should now be 0!
However, I'm getting results like -2.315223e-18
This is really near to 0 but not very aesthetic.
Can I prevent this? Or is
> I would like to plot a curve (in color red) on a surface in a 3D plot.
Perhaps trans3d would be relevant?
?persp 's examples include an example of adding a line to a 3d plot using
trans3d
S
***
This email and any attachments are
Greetings,
I would like to plot a curve (in color red) on a surface in a 3D plot.
Say
x <- as.vector(seq(-1,1,0.2))
dim(x) <- c(length(x),1)
y <- as.vector(seq(-1,1,0.2))
dim(y) <- c(1,length(y))
z <- x%*%y # (x_iy_j)
# 3D plot of z(x,y)=xy:
persp(x,y,z
Hi,
Shortly after my first post I posted an answer including the fix I found; which
seems to work. Through the archives I found that my code snippet got filtered
out and appended as an attachment (which was not my intent).
This was my suggestion:
for(i in seq(length(ss$name))) {
color
On Thu, Aug 23, 2012 at 09:49:33PM -0700, Gopi Goteti wrote:
> I would like to know whether there is a faster way to do the below
> operation (updating vec1).
>
> My objective is to update the elements of a vector (vec1), where a
> particular element i is dependent on the previous one. I need to d
Hello,
I've put the short version here and if anyone wants to run the code with
CollocInfer, I've given the full version in the file "analysis".
I come at the question of array attributes and dimnames
to try to simplify.
In a CollocInfer LS.profile analysis using this array 'Y' constructed
as
Hello,
Each block of probs range from p00 to p10 is last value before the block.
Example:
probs: .1 .1 .5 .5 .5 .9 .9
vec1 : 0 0 0 0 0 1 1
probs: .9 .9 .5 .5 .5 .1 .1
vec1 : 1 1 1 1 1 0 0
So you can eliminate a loop.
# modification
f5 <- function () {
vec1 <- as.num
On Fri, Aug 24, 2012 at 10:34:14AM +0200, Petr Savicky wrote:
> On Thu, Aug 23, 2012 at 09:49:33PM -0700, Gopi Goteti wrote:
> > I would like to know whether there is a faster way to do the below
> > operation (updating vec1).
> >
> > My objective is to update the elements of a vector (vec1), wher
Hi
Well, I am not sure if this is what you want but same result can be achieved by
vec1 <- (probs>=p00)*(probs>=p10)
Petr
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Gopi Goteti
> Sent: Friday, August 24, 2012 6:50 AM
On Thu, Aug 23, 2012 at 09:49:33PM -0700, Gopi Goteti wrote:
> I would like to know whether there is a faster way to do the below
> operation (updating vec1).
>
> My objective is to update the elements of a vector (vec1), where a
> particular element i is dependent on the previous one. I need to d
On 24-08-2012, at 06:49, Gopi Goteti wrote:
> I would like to know whether there is a faster way to do the below
> operation (updating vec1).
>
> My objective is to update the elements of a vector (vec1), where a
> particular element i is dependent on the previous one. I need to do this on
> vec
Hello,
try this:
x <- c("SELECT [public_tblFiche].[Fichenr], [public_tblArtnr].[Artnr]", "SELECT
public_tblFiche.Fichenr, public_tblArtnr.Artnr")
# > The square backets [ and ] should removed
x <- gsub("[][]", "", x)
# > and xxx_xxx.xxx should become \"xxx\".\"xxx\"\".\"xxx\"
x <- gsub("([[:al
Hi,
In R under cygwin I have trouble to correctly display help in text
format. One problem arises when there are single qoutes in the text like
in "?help" which looks like this
helppackage:utils R Documentation
Documentation
Description:
Usage:
he
Hi,
Can someone please tell me what are the steps to follow for installing RHBASE
library for R 2.15.1.
Regards,
Divya
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