MRAB writes:
> On 2015-08-18 22:55, Ben Bacarisse wrote:
>> Neal Becker writes:
>>
>>> Trying regex 2015.07.19
>>>
>>> I'd like to match recursive parenthesized expressions, with groups such that
>>> '(a(b)c)'
>>>
>>> would give
>>> group(0) -> '(a(b)c)'
>>> group(1) -> '(b)'
>>>
>>> but that's
On 2015-08-18 22:55, Ben Bacarisse wrote:
Neal Becker writes:
Trying regex 2015.07.19
I'd like to match recursive parenthesized expressions, with groups such that
'(a(b)c)'
would give
group(0) -> '(a(b)c)'
group(1) -> '(b)'
but that's not what I get
import regex
#r = r'\((?>[^()]|(?R))*\)
Neal Becker writes:
> Trying regex 2015.07.19
>
> I'd like to match recursive parenthesized expressions, with groups such that
> '(a(b)c)'
>
> would give
> group(0) -> '(a(b)c)'
> group(1) -> '(b)'
>
> but that's not what I get
>
> import regex
>
> #r = r'\((?>[^()]|(?R))*\)'
> r = r'\(([^()]|(?
On 2015-08-18 15:25, Neal Becker wrote:
Trying regex 2015.07.19
I'd like to match recursive parenthesized expressions, with groups such that
'(a(b)c)'
would give
group(0) -> '(a(b)c)'
group(1) -> '(b)'
but that's not what I get
import regex
#r = r'\((?>[^()]|(?R))*\)'
r = r'\(([^()]|(?R))*\)
On 8/18/2015 10:25 AM, Neal Becker wrote:
Trying regex 2015.07.19
I'd like to match recursive parenthesized expressions, with groups such that
'(a(b)c)'
Extended regular expressions can only match strings in extended regular
languages. General nested expressions are too general for that. Yo
Trying regex 2015.07.19
I'd like to match recursive parenthesized expressions, with groups such that
'(a(b)c)'
would give
group(0) -> '(a(b)c)'
group(1) -> '(b)'
but that's not what I get
import regex
#r = r'\((?>[^()]|(?R))*\)'
r = r'\(([^()]|(?R))*\)'
#r = r'\((?:[^()]|(?R))*\)'
m = regex.m
