On 2015-08-18 22:55, Ben Bacarisse wrote:
Neal Becker <ndbeck...@gmail.com> writes:
Trying regex 2015.07.19
I'd like to match recursive parenthesized expressions, with groups such that
'(a(b)c)'
would give
group(0) -> '(a(b)c)'
group(1) -> '(b)'
but that's not what I get
import regex
#r = r'\((?>[^()]|(?R))*\)'
r = r'\(([^()]|(?R))*\)'
#r = r'\((?:[^()]|(?R))*\)'
m = regex.match (r, '(a(b)c)')
The (?R) syntax is Perl -- it's no implemented in Python. Python and
Perl regexs are very similar in syntax (for very good reasons) but
neither (?R) nor the numbered or named versions of it are in Python.
He's using the regex module from PyPI:
https://pypi.python.org/pypi/regex
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