Trying regex 2015.07.19 I'd like to match recursive parenthesized expressions, with groups such that '(a(b)c)'
would give
group(0) -> '(a(b)c)'
group(1) -> '(b)'
but that's not what I get
import regex
#r = r'\((?>[^()]|(?R))*\)'
r = r'\(([^()]|(?R))*\)'
#r = r'\((?:[^()]|(?R))*\)'
m = regex.match (r, '(a(b)c)')
m.groups()
Out[28]: ('c',)
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