> On 8 Jan 2023, at 21:16, Raphael Santiago
> wrote:
>
> Maybe something like re""
> It should behave exactly like a raw string but would be useful for syntax
> highlighting and debugging. Perhaps also for type hinting expected regex
> input (don't
On 08Jan2023 12:44, Raphael Santiago wrote:
Maybe something like re""
It should behave exactly like a raw string but would be useful for syntax
highlighting and debugging. Perhaps also for type hinting expected regex
input (don't know if this is feasible).
A nice idea. (Though
Maybe something like re""
It should behave exactly like a raw string but would be useful for syntax
highlighting and debugging. Perhaps also for type hinting expected regex
input (don't know if this is feasible).
--
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Am Thu, Sep 30, 2021 at 12:29:16PM +0100 schrieb Shaozhong SHI:
> I am trying to look for a definitive guide for Regex in Python.
> Can anyone help?
If you tell us what you tried in order to look we can
perhaps guide you on how to take a better look.
Spoonfeeding doesn't seem to be a
> On 1 Oct 2021, at 10:58, Shaozhong SHI wrote:
>
> Hi, Barry,
>
> In cases of automating checking, validation and producing reports in the
> context of data quality control and giving specific feedback to production
> teams, regex is perhaps the only way.
>
>
Shaozhong SHI 在 2021年9月30日 星期四下午7:29:47 [UTC+8] 的信中寫道：
> Dear All,
>
> I am trying to look for a definitive guide for Regex in Python.
> Can anyone help?
>
> Regards,
>
> David
Try the rexegg.com which is a site dedicate to this subject and has many
reso
Hi, Barry,
In cases of automating checking, validation and producing reports in the
context of data quality control and giving specific feedback to production
teams, regex is perhaps the only way.
Perhaps, we can give each element of data specifications a name, that are
associated with a regex
> On 30 Sep 2021, at 19:35, dn via Python-list wrote:
>
> On 01/10/2021 06.16, Barry Scott wrote:
>>
>>
>>> On 30 Sep 2021, at 12:29, Shaozhong SHI wrote:
>>>
>>> Dear All,
>>>
>>> I am trying to look for a definitive gu
On 01/10/2021 06.16, Barry Scott wrote:
>
>
>> On 30 Sep 2021, at 12:29, Shaozhong SHI wrote:
>>
>> Dear All,
>>
>> I am trying to look for a definitive guide for Regex in Python.
>> Can anyone help?
>
> Have you read the python docs for the r
> On 30 Sep 2021, at 12:29, Shaozhong SHI wrote:
>
> Dear All,
>
> I am trying to look for a definitive guide for Regex in Python.
> Can anyone help?
Have you read the python docs for the re module?
Barry
>
> Regards,
>
> David
> --
> https://mai
Dear All,
I am trying to look for a definitive guide for Regex in Python.
Can anyone help?
Regards,
David
--
https://mail.python.org/mailman/listinfo/python-list
On Thu, Dec 24, 2020 at 12:56 PM dn via Python-list
wrote:
>
> On 24/12/2020 12:25, Chris Angelico wrote:
> > On Thu, Dec 24, 2020 at 9:42 AM dn via Python-list
> > wrote:
> >> Hang-on though, look at how much 'work' is involved, compared with a
> >&g
On 24/12/2020 12:25, Chris Angelico wrote:
On Thu, Dec 24, 2020 at 9:42 AM dn via Python-list
wrote:
Hang-on though, look at how much 'work' is involved, compared with a
single line of RegEx! Why go to such bother? There's several reasons.
Good question! Look at this al
On 24/12/2020 12:20, 2qdxy4rzwzuui...@potatochowder.com wrote:
On 2020-12-24 at 11:41:15 +1300,
dn via Python-list wrote:
On 24/12/2020 06:03, Sadaka Technology wrote:
hello guys,
I have this pattern for password validation (regex):
[...]
Is it my imagination, or does a password in
On Thu, Dec 24, 2020 at 10:21 AM <2qdxy4rzwzuui...@potatochowder.com> wrote:
> If you're going to wander out of ASCII, then don't forget to address
> Unicode confusables. Nothing is more embarrassing than scribbling your
> complicated password on a sticky note and then not being able to tell
> the
On Thu, Dec 24, 2020 at 9:42 AM dn via Python-list
wrote:
> Hang-on though, look at how much 'work' is involved, compared with a
> single line of RegEx! Why go to such bother? There's several reasons.
Good question! Look at this alternative:
def validate_password(att
On 2020-12-24 at 11:41:15 +1300,
dn via Python-list wrote:
> On 24/12/2020 06:03, Sadaka Technology wrote:
> > hello guys,
> >
> > I have this pattern for password validation (regex):
[...]
> > passwordpattern =
> > "^(?=.[a-z])(?=.[A-Z])(?=.\d)(?=.[@
On 24/12/2020 06:03, Sadaka Technology wrote:
hello guys,
I have this pattern for password validation (regex):
I want these rules to be applied:
Minimum 8 characters.
The alphabets must be between [a-z]
At least one alphabet should be of Upper Case [A-Z]
At least 1 number or digit between [0
On Thu, Dec 24, 2020 at 4:09 AM Sadaka Technology
wrote:
>
> hello guys,
>
> I have this pattern for password validation (regex):
>
> I want these rules to be applied:
>
> Minimum 8 characters.
> The alphabets must be between [a-z]
> At least one alphabet should be
Python issue!)
You're far, far better off writing a function that tests each rule
separately, so that you can tell the user _why_ the password isn't
allowed. If you use a regex, it's just pass/fail. The user won't have
any idea how to fix the problem.
--
Grant Edwards
On 2020-12-23 17:03, Sadaka Technology wrote:
hello guys,
I have this pattern for password validation (regex):
I want these rules to be applied:
Minimum 8 characters.
The alphabets must be between [a-z]
At least one alphabet should be of Upper Case [A-Z]
At least 1 number or digit between [0
On 12/23/20 10:03 AM, Sadaka Technology wrote:
hello guys,
I have this pattern for password validation (regex):
I want these rules to be applied:
Minimum 8 characters.
The alphabets must be between [a-z]
At least one alphabet should be of Upper Case [A-Z]
At least 1 number or digit between [0
hello guys,
I have this pattern for password validation (regex):
I want these rules to be applied:
Minimum 8 characters.
The alphabets must be between [a-z]
At least one alphabet should be of Upper Case [A-Z]
At least 1 number or digit between [0-9].
At least 1 character from [ _ or @ or
t compiling, but matching - most likely backtracking
> > from lots of promising but ultimately unsuccessful partial matches.
> >
> >> regex = r'data-stid="section-room-list"[\s\S]*?>\s*([\s\S]*?)\s*' \
> >>
> >>
>
> r'(?:cla
helps the OP much. Compiled
> regular expressions are cached, but more importantly, if a match takes
> long enough that specifying a timeout is useful, the time is almost
> certainly not spent compiling, but matching - most likely backtracking
> from lots of promising but ultimately unsucc
match takes
long enough that specifying a timeout is useful, the time is almost
certainly not spent compiling, but matching - most likely backtracking
from lots of promising but ultimately unsuccessful partial matches.
> regex = r'data-stid="section-room-list"
Hi,
Timeout: no idea. But check out re.compile and re.iterfind as they might
speed things up. I often compile a regex once upon import, then use it in
functions
On 27 Nov 2020 13:33, Shahique Khan wrote:
Hi Team,
I have noticed if our regex sometimes does not give a
Hi Team,
I have noticed if our regex sometimes does not give a result and on that
time regex took more time in returning response (empty response).
My Question is can we set a timeout parameter (in seconds/millisecond) with
re.find or anywhere in code to avoid CPU consumption if regex takes more
It is good to see a nice small piece of code which we can run. Thank
you.
So there are a number of things to comment about in the code below;
comments inline under the relevant piece of code (we prefer the "inline
reply" style here, it reads like a conversation):
On 01Oct2020 15:15, Raju wrot
title()group(3)
else:
output.title()
On Thursday, October 1, 2020 at 10:53:16 PM UTC+1, cameron...@gmail.com wrote:
> On 01Oct2020 12:41, Raju wrote:
> >I want to change the case on input string i was able to match using
> >python regex but couldn't find the
On 01Oct2020 12:41, Raju wrote:
>I want to change the case on input string i was able to match using
>python regex but couldn't find the way to change the case.
>
>For example string:
>Input: 7Section Hello Jim
>output: 7Section hello Jim
>
>I was doing if statment w
Hello Everyone,
I want to change the case on input string i was able to match using python
regex but couldn't find the way to change the case.
For example string:
Input: 7Section Hello Jim
output: 7Section hello Jim
I was doing if statment with regex
if re.match("(\d+\w* )(
Il 03/09/20 22:16, Chris Angelico ha scritto:
Hmm. Have you considered using CSS to do this? Markdown is generally
fairly easy to style with CSS.
Yes, infact these are files where I'll insert a tag (in the example
, to show the errors find at a second revision due they are of
another kind, b
On Fri, Sep 4, 2020 at 5:36 AM Termoregolato wrote:
>
> Il 03/09/20 16:10, Termoregolato wrote:
>
> > I need to change every occurrence of a sequence between two chars
>
> Thanks to all for your replies, it's time to learn regular expressions,
> but now I've some valid pointers from you.
>
> The w
Il 03/09/20 16:10, Termoregolato wrote:
I need to change every occurrence of a sequence between two chars
Thanks to all for your replies, it's time to learn regular expressions,
but now I've some valid pointers from you.
The work I must do here, to explain, is to get some markdown files, an
Derp, sorry about the noise. I mistook this message for a similar
dialog over on the Vim mailing list.
For Python, you want
re.sub(r"%%(.*?)%%", r"\1", s, flags=re.S)
or put the flag inline
re.sub(r"(?s)%%(.*?)%%", r"\1", s)
-tim
On 2020-09-03 09:27, Tim Chase wrote:
> On 2020-09-03 16:1
On 2020-09-03 16:10, Termoregolato wrote:
> -- original
> This is the %%text that i must modify%%, on a line, %%but also
> on the others%% that are following
>
> I need to change to
>
> -- desidered
> This is the text that i must modify, on a line, but
> also on the others that are following
Sho
group, but I presume that
that's intentional.
To solve this, you can make the asterisk "non-greedy" by adding a
question mark after it:
rebarredtext = r'~~([^>]*?)~~'
Now it matches as *little* as it possibly can.
Additionally, you can get the regex engine to
t;, "" + line + "")
but it changes only the biggest occurrence: how can I do to change all
occurrences? I'm really a regex newbie, TIA
-- test
This is the text that i must modify%%, on a line, %%but also
on the others that are following
--
https://mail.python.org/mailman/listinfo/python-list
Maggie Q Roth writes:
> There are two primary types of lines in the log:
>
> 60.191.38.xx/
> 42.120.161.xx /archives/1005
>
> I know how to write regex to match each line, but don't get the good result
> with one regex to match both lines.
>
> Can
On 25/10/19 12:22, Maggie Q Roth wrote:
> Hello
>
> There are two primary types of lines in the log:
>
> 60.191.38.xx/
> 42.120.161.xx /archives/1005
>
> I know how to write regex to match each line, but don't get the good result
> with one regex
On October 25, 2019 12:22:44 PM GMT+02:00, Maggie Q Roth
wrote:
>Hello
>
>There are two primary types of lines in the log:
>
>60.191.38.xx/
>42.120.161.xx /archives/1005
>
>I know how to write regex to match each line, but don't get the good
>resu
Hello
There are two primary types of lines in the log:
60.191.38.xx/
42.120.161.xx /archives/1005
I know how to write regex to match each line, but don't get the good result
with one regex to match both lines.
Can you help?
Thanks,
Maggie
--
https://mail.python.org/ma
>
> A site like http://www.pyregex.com/ allows you to check your regex with
> slightly fewer clicks and keystrokes than editing your program.
Thanks Jason
--
https://mail.python.org/mailman/listinfo/python-list
>
> If I have path: /home/admin/hello/yo/{h1,h2,h3,h4}
>
> import re
> r = re.search('{.}', path)
> # r should be ['h1,h2,h3,h4'] but I fail
>
> Why always search nothing?
>
A site like http://www.pyregex.com/ allows you to check your regex with
sl
On Fri, Aug 23, 2019 at 6:44 PM lampahome wrote:
>
> I want to parse a path string with multiple files and try to figure out a
> one-line way.
>
> If I have path: /home/admin/hello/yo/{h1,h2,h3,h4}
>
> What I thought is use regex.search, but the pattern always failed.
>
> I use below:
> import re
I want to parse a path string with multiple files and try to figure out a
one-line way.
If I have path: /home/admin/hello/yo/{h1,h2,h3,h4}
What I thought is use regex.search, but the pattern always failed.
I use below:
import re
path = /home/admin/hello/yo/{h1,h2,h3,h4}
r = re.search('{.}', path
On Mon, 2018-10-01 at 10:49 -0700, nanman3...@gmail.com wrote:
> I have a string like this:
>
> b'\tC:94.3%[S:89.9%,D:4.4%],F:1.7%,M:4.0%,n:1440\n'
>
> And I would like to extract the numbers corresponding to S,D,F and M in this
> string and convert them into an array like this:
>
> [ '89.9'
On 2018-10-01 18:49, nanman3...@gmail.com wrote:
I have a string like this:
b'\tC:94.3%[S:89.9%,D:4.4%],F:1.7%,M:4.0%,n:1440\n'
And I would like to extract the numbers corresponding to S,D,F and M in this
string and convert them into an array like this:
[ '89.9', '4.4', '1.7', '4.0']
Any he
I have a string like this:
b'\tC:94.3%[S:89.9%,D:4.4%],F:1.7%,M:4.0%,n:1440\n'
And I would like to extract the numbers corresponding to S,D,F and M in this
string and convert them into an array like this:
[ '89.9', '4.4', '1.7', '4.0']
Any help would be appreciated!
--
https://mail.python
On 2018-08-28 00:58, Malcolm wrote:
On 28/08/2018 7:09 AM, John Pote wrote:
On 26/08/2018 00:55, Malcolm wrote:
I am trying to understand why regex is not extracting all of the
characters between two delimiters.
The complete string is the xmp IFD data extracted from a .CR2 image
file.
I
On 28/08/2018 7:09 AM, John Pote wrote:
On 26/08/2018 00:55, Malcolm wrote:
I am trying to understand why regex is not extracting all of the
characters between two delimiters.
The complete string is the xmp IFD data extracted from a .CR2 image
file.
I do have a work around, but it's
On 26/08/2018 00:55, Malcolm wrote:
I am trying to understand why regex is not extracting all of the
characters between two delimiters.
The complete string is the xmp IFD data extracted from a .CR2 image file.
I do have a work around, but it's messy and possibly not future proof.
Do you
On 08/25/2018 04:55 PM, Malcolm wrote:
I am trying to understand why regex is not extracting all of the
characters between two delimiters.
The complete string is the xmp IFD data extracted from a .CR2 image file.
I do have a work around, but it's messy and possibly not future proof.
I am trying to understand why regex is not extracting all of the
characters between two delimiters.
The complete string is the xmp IFD data extracted from a .CR2 image file.
I do have a work around, but it's messy and possibly not future proof.
Any insight greatly appreciated.
Malcol
Wow. Thanks. That cleared everything up.
cs
--
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cseber...@gmail.com wrote:
> Why this regex for string literals
> can't handle escaped quotes? '"(\\.|[^"])*"'
>
> See this...
>
>>>> string_re = '"(\\.|[^"])*"'
>
>>>> re.match(string_re,
Why this regex for string literals
can't handle escaped quotes? '"(\\.|[^"])*"'
See this...
>>> string_re = '"(\\.|[^"])*"'
>>> re.match(string_re, '""')
<_sre.SRE_Match object; span=(0, 6),
On 21/07/18 14:39, Ganesh Pal wrote:
>> The dictionary is irrelevant to your question. It doesn't matter whether
>> the path came from a dict, a list, read directly from stdin, an
>> environment variable, extracted from a CSV file, or plucked directly from
>> outer space by the programmer. The proc
> The dictionary is irrelevant to your question. It doesn't matter whether
> the path came from a dict, a list, read directly from stdin, an
> environment variable, extracted from a CSV file, or plucked directly from
> outer space by the programmer. The process remains the same regardless of
> wher
On Sat, 21 Jul 2018 17:07:04 +0530, Ganesh Pal wrote:
> I have one of the dictionary values in the below format
>
> '/usr/local/ABCD/EDF/ASASAS/GTH/HELLO/MELLO/test04_Failures.log'
> '/usr/local/ABCD/EDF/GTH/HEL/OOLO/MELLO/test02_Failures.log'
> '/usr/local/ABCD/EDF/GTH/BEL/LO/MELLO/test03_Failur
def return_filename_test_case(filepath):
filename = os.path.basename(filepath)
testcase = filename.partition('_')[0]
return filename, testcase
On 21 July 2018 at 12:37, Ganesh Pal wrote:
> I have one of the dictionary values in the below format
>
> '/usr/local/ABCD/EDF/ASASAS/GTH/HELL
I have one of the dictionary values in the below format
'/usr/local/ABCD/EDF/ASASAS/GTH/HELLO/MELLO/test04_Failures.log'
'/usr/local/ABCD/EDF/GTH/HEL/OOLO/MELLO/test02_Failures.log'
'/usr/local/ABCD/EDF/GTH/BEL/LO/MELLO/test03_Failures.log'
I need to extract the file name in the path example, say
17 to 25 in the below code)
Here is my code :
root@X1:/Play_ground/SPECIAL_TYPES/REGEX# vim Friedrich.py
1 import re
2 from collections import OrderedDict
3
4 keys = ["struct", "loc", "size", "mirror",
5 "filename","
ck
> /var/1000111/test18.log
> 0
> 8
>
>
> Here is my sample code , its still not complete , I wanted to use regex
> and find and extract all the fields after " =", any suggestion or
> alternative way to optimize this further
>
>
> import re
> line
irmation bias, I've been seeing
> it everywhere." -- Jon Ronson
I resolve my problem and when I look to my solution I don't understand why I
didn't do it earlier :)
with open(path) as file:
result = []
for line in file:
find_regex = re.search(regex,line)
if find_re
On Fri, 15 Jun 2018 01:01:03 -0700, francois.rabanel wrote:
> I work with a file which contains millions lines, a simply file.read()
> and I'm running out of memory
Assuming each line is on average a hundred characters long, a million
lines is (approximately) 100 MB. Even on a computer with only
>
>>>> {'struct': 'data_block', 'log_file': '/var/1000111/test18.log', 'loc':
> '0', 'size': '8'}
>
>
MARB, as usual the solution you you look nice, Thanks for the excellent
solutions
Le vendredi 15 juin 2018 02:42:12 UTC+2, Cameron Simpson a écrit :
> On 15Jun2018 00:24, Steven D'Aprano
> wrote:
> >On Fri, 15 Jun 2018 10:00:59 +1000, Cameron Simpson wrote:
> >> Francois, unless your regex can cross multiple lines it is better to
> >> searc
On 15Jun2018 00:24, Steven D'Aprano
wrote:
On Fri, 15 Jun 2018 10:00:59 +1000, Cameron Simpson wrote:
Francois, unless your regex can cross multiple lines it is better to
search files like this:
with open(the_filename) as f:
for line in f:
... search the line for the r
On Fri, 15 Jun 2018 10:00:59 +1000, Cameron Simpson wrote:
> Francois, unless your regex can cross multiple lines it is better to
> search files like this:
>
> with open(the_filename) as f:
> for line in f:
> ... search the line for the regexp ...
>
> That w
e he tried to read the whole file into memory and match against
it. Guessing:
text = open(the_filename).read()
... search the text for the regexp ...
Francois, unless your regex can cross multiple lines it is better to search
files like this:
with open(the_filename) as f:
for
ith "os.rename" at the end.
>
> My problem is, if I work on a huge file, I'll try to avoid to read the
> file because it will be crash my computer :)
How does reading a file crash your computer?
> and I would to verify if the regex enter by the user, exist.
The only
to avoid to read the file
because it will be crash my computer :) and I would to verify if the regex
enter by the user, exist.
I don't know if it's possible, I'm looking for a solution since few hours... so
sorry if the question is easy or wtf :)
---
quot;--size=8" at the end? That's what your explanation implied.
How's this? (Supposing that the values contain no spaces):
>>> regex = re.compile
(r"--(struct|loc|size|mirror|log_file)\s*=\s*([^\s]+)")
>>> regex.findall (line)
[('struct', 'd
tion 1:
Please let me know the mistakes in the below code and suggest if it can
be optimized further with better regex
# This code has to extract various the fields from a single line (
assuming the line is matched here ) of a log file that contains various
values (and then store the extract
and I am able to extract all
the required fields , I have 2 further questions too , please suggest
Question 1:
Please let me know the mistakes in the below code and suggest if it can
be optimized further with better regex
# This code has to extract various the fields from a single line
On 13/06/18 09:08, Ganesh Pal wrote:
Hi Team,
I wanted to parse a file and extract few feilds that are present after "="
in a text file .
Example , form the below line I need to extract the values present after
--struct =, --loc=, --size= and --log_file=
Sample input
line = '06/12/2018 11
me.py --struct=data_block
--log_file=/var/1000111/test18.log --addr=None --loc=0 --mirror=10
--path=/tmp/data_block.txt size=8'
Expected output
data_block
/var/1000111/test18.log
0
8
Here is my sample code , its still not complete , I wanted to use regex
and find and extract all the fi
On 2018-04-27 21:04:49 -0700, Ed Manning wrote:
> Here is the source code.
>
>
> import re
>
>
> log = open("csg.txt", "r") # Opens a file call session.txt
> regex = re.compile(r'policy id \d+') # search for the policy ID
> regex1
Here is the source code.
import re
log = open("csg.txt", "r") # Opens a file call session.txt
regex = re.compile(r'policy id \d+') # search for the policy ID
regex1 = re.compile(r'log count \d+') # search for the policy ID
for match in log:
x = reg
On Wednesday, 18 April 2018 19:34:37 UTC+2, MRAB wrote:
> > Hi,
> >
> > I have a sql query in which all variables declared as :variable should be
> > changed to ${variable}.
> >
> > for example this sql:
> >
> > select *
> > from table
> > where ":x" = "1" and :y=2
> > and field in (:string)
On 2018-04-18 08:25, zljubi...@gmail.com wrote:
Hi,
I have a sql query in which all variables declared as :variable should be
changed to ${variable}.
for example this sql:
select *
from table
where ":x" = "1" and :y=2
and field in (:string)
and time between :from and :to
should be tran
Hi,
I have a sql query in which all variables declared as :variable should be
changed to ${variable}.
for example this sql:
select *
from table
where ":x" = "1" and :y=2
and field in (:string)
and time between :from and :to
should be translated to:
select *
from table
where "${x}"
-Original Message-
From: Python-list On Behalf Of MRAB
Sent: Friday, April 13, 2018 12:05 PM
To: python-list@python.org
Subject: Re: Python regex pattern from array of hex chars
> Use re.escape:
>
> regex = re.compile('[^{}]+'.format(re.escape(''.join
On 2018-04-13 18:28, Joseph L. Casale wrote:
I have an array of hex chars which designate required characters.
and one happens to be \x5C or "\". What foo is required to build the
pattern to exclude all but:
regex = re.compile('[^{}]+'.format(''.join(c for c in c
I have an array of hex chars which designate required characters.
and one happens to be \x5C or "\". What foo is required to build the
pattern to exclude all but:
regex = re.compile('[^{}]+'.format(''.join(c for c in character_class)))
I would use that in a re.sub t
or
want to see hundreds of lines.
+100
Cut your data down to a SMALL representative sample. Explain how it is
coming to you: it looks like you are reading the data in something
similar to key:value format. Is that correct?
If so, you don't need a regex. This is not Perl, we have more than one
t your data down to a SMALL representative sample. Explain how it is
coming to you: it looks like you are reading the data in something
similar to key:value format. Is that correct?
If so, you don't need a regex. This is not Perl, we have more than one
tool in our toolbox and don't hav
Hello,
I would like to match set of lines from the below data. this data comes
from one of the network
Part of data : [ If circuit type is OCHCC then I need Circuit name and
service ID from that group ]
Circuit ID: ad8a0165:25
*Circuit Name: T3A_100G_SD20*
Circuit Version: 0
Circuit Monitor: fal
> <<<< > Feature XYZ : 3 valid13 free
> > Feature PQR : 0 valid 16 free
> > Feature MNO : 0 valid 2 free
> >
> > """
> >
> > i am going to grep MEM values alone and i have
: 0 valid 2 free
>
> """
>
> i am going to grep MEM values alone and i have tried fallowing Regex:
>
> re.findall(r'MEMR\s+\:\s+([0-9]+)\s+valid \s+([0-9]+)\s+free ', str_output)
>
> it produce fallowing output::
> [('0&
On 30Mar2018 11:46, Iranna Mathapati wrote:
how to achieve fallowing expected output?
str_output= """
MOD1 memory : 2 valid1790 free
MOD2 memory : 128 valid 128 free
UDP Aware *MEMR*: 0 valid 0 free *
t; MOD2 memory : 128 valid 128 free
>> UDP Aware *MEMR*: 0 valid 0 free *MEMR
>> : 21 valid 491 free
>> <<<<> Feature XYZ : 3 valid13 f
Hi Team,
how to achieve fallowing expected output?
str_output= """
MOD1 memory : 2 valid1790 free
MOD2 memory : 128 valid 128 free
UDP Aware *MEMR*: 0 valid 0 free *MEMR
Hello,
this question also came up there:
https://python-forum.io/Thread-Working-with-Dict-Object
Greetings
Andre
--
https://mail.python.org/mailman/listinfo/python-list
On 13/02/18 18:08, Stanley Denman wrote:
On Tuesday, February 13, 2018 at 9:41:14 AM UTC-6, Mark Lawrence wrote:
On 13/02/18 13:11, Stanley Denman wrote:
I am trying to performance a regex on a "string" of text that python isinstance
is telling me is a dictionary. When I run the
On Tuesday, February 13, 2018 at 9:41:14 AM UTC-6, Mark Lawrence wrote:
> On 13/02/18 13:11, Stanley Denman wrote:
> > I am trying to performance a regex on a "string" of text that python
> > isinstance is telling me is a dictionary. When I run the code I get
On Tue, 13 Feb 2018 13:53:04 +, Mark Lawrence wrote:
> Was the string methods solution that I gave a week or so ago so bad that
> you still think that you need a regex to solve this?
Sometimes regexes are needed, but often Jamie Zawinski is right:
Some people, when confronted
On Tue, 13 Feb 2018 05:11:20 -0800, Stanley Denman wrote:
> I am trying to performance a regex on a "string" of text that python
> isinstance is telling me is a dictionary.
Please believe Python when it tells you that something is a dictionary.
Trust me, the interpreter knows. I
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