Am 08.06.22 um 19:57 schrieb De ongekruisigde:
On 2022-06-08, 2qdxy4rzwzuui...@potatochowder.com
<2qdxy4rzwzuui...@potatochowder.com> wrote:
On 2022-06-09 at 04:15:46 +1000,
Chris Angelico wrote:
If you insist:
>>> s = 'nm-iodine:x:996:57::/var/empty:/run/current-system/sw/bin/nologin'
Am 09.06.22 um 07:50 schrieb Dave:
Hi,
I’ve found you also need to take care of multiple disk CD releases. These have
a format of
“1-01 Track Name”
“2-02 Trackl Name"
Meaning Disk 1 Track1, Disk 2, Track 2.
Also A and B Sides (from Vinyl LPs)
“A1-Track Name”
“B2-Track Name”
Side A, Track
2022 2:50 am
Subject: Re: How to test characters of a string
Hi,
I’ve found you also need to take care of multiple disk CD releases. These have
a format of
“1-01 Track Name”
“2-02 Trackl Name"
Meaning Disk 1 Track1, Disk 2, Track 2.
Also A and B Sides (from Vinyl LPs)
“A1-Track Name”
“B
Hi,
I’ve found you also need to take care of multiple disk CD releases. These have
a format of
“1-01 Track Name”
“2-02 Trackl Name"
Meaning Disk 1 Track1, Disk 2, Track 2.
Also A and B Sides (from Vinyl LPs)
“A1-Track Name”
“B2-Track Name”
Side A, Track 1, etc.
Cheers
Dave
> On 8 Jun 202
On 2022-06-08, 2qdxy4rzwzuui...@potatochowder.com
<2qdxy4rzwzuui...@potatochowder.com> wrote:
> On 2022-06-09 at 04:15:46 +1000,
> Chris Angelico wrote:
>
>> On Thu, 9 Jun 2022 at 04:14, <2qdxy4rzwzuui...@potatochowder.com> wrote:
>> >
>> > On 2022-06-09 at 03:18:56 +1000,
>> > Chris Angelico wr
On Wed, 8 Jun 2022 01:53:26 + (UTC), Avi Gross
declaimed the following:
>
>So is it necessary to insist on an exact pattern of two digits followed by a
>space?
>
>
>That would fail on "44 Minutes", "40 Oz. Dream", "50 Mission Cap", "50 Ways to
>Say Goodbye", "99 Ways to Die"
>
>It looks
On 2022-06-08, 2qdxy4rzwzuui...@potatochowder.com
<2qdxy4rzwzuui...@potatochowder.com> wrote:
> On 2022-06-08 at 08:07:40 -,
> De ongekruisigde wrote:
>
>> Depending on the problem a regular expression may be the much simpler
>> solution. I love them for e.g. text parsing and use them all the
On 2022-06-09 at 04:15:46 +1000,
Chris Angelico wrote:
> On Thu, 9 Jun 2022 at 04:14, <2qdxy4rzwzuui...@potatochowder.com> wrote:
> >
> > On 2022-06-09 at 03:18:56 +1000,
> > Chris Angelico wrote:
> >
> > > On Thu, 9 Jun 2022 at 03:15, <2qdxy4rzwzuui...@potatochowder.com> wrote:
> > > >
> > > >
On Thu, 9 Jun 2022 at 04:14, <2qdxy4rzwzuui...@potatochowder.com> wrote:
>
> On 2022-06-09 at 03:18:56 +1000,
> Chris Angelico wrote:
>
> > On Thu, 9 Jun 2022 at 03:15, <2qdxy4rzwzuui...@potatochowder.com> wrote:
> > >
> > > On 2022-06-08 at 08:07:40 -,
> > > De ongekruisigde wrote:
> > >
> >
On 2022-06-09 at 03:18:56 +1000,
Chris Angelico wrote:
> On Thu, 9 Jun 2022 at 03:15, <2qdxy4rzwzuui...@potatochowder.com> wrote:
> >
> > On 2022-06-08 at 08:07:40 -,
> > De ongekruisigde wrote:
> >
> > > Depending on the problem a regular expression may be the much simpler
> > > solution. I
On Thu, 9 Jun 2022 at 03:15, <2qdxy4rzwzuui...@potatochowder.com> wrote:
>
> On 2022-06-08 at 08:07:40 -,
> De ongekruisigde wrote:
>
> > Depending on the problem a regular expression may be the much simpler
> > solution. I love them for e.g. text parsing and use them all the time.
> > Unrival
On 2022-06-08 at 08:07:40 -,
De ongekruisigde wrote:
> Depending on the problem a regular expression may be the much simpler
> solution. I love them for e.g. text parsing and use them all the time.
> Unrivaled when e.g. parts of text have to be extracted, e.g. from lines
> like these:
>
>
> On 7 Jun 2022, at 23:24, Dave wrote:
>
> Yes, it was probably just a typeo on my part.
>
> I’ve now fixed the majority of cases but still got two strings that look
> identical but fail to match, this time (again by 10cc), “I’m Mandy Fly Me”.
>
> I’m putting money on it being a utf8 problem
On 2022-06-08, Christian Gollwitzer wrote:
> Am 07.06.22 um 23:01 schrieb Christian Gollwitzer:
>
>>> In [3]: re.sub(r'^\d+\s*', '', s) Out[3]: 'Trinket'
>>>
>
> that RE does match what you intended to do, but not exactly what you
> wrote in the OP. that would be '^\d\d.' start with exactly two
On 2022-06-08, Dave wrote:
> I hate regEx and avoid it whenever possible, I’ve never found something that
> was impossible to do without it.
I love regular expressions and use them where appropriate. Saves tons of
code and is often much more readable than the pages of code required to
do the sam
On 2022-06-08, dn wrote:
> On 08/06/2022 10.18, De ongekruisigde wrote:
>> On 2022-06-08, Christian Gollwitzer wrote:
>>> Am 07.06.22 um 21:56 schrieb Dave:
It depends on the language I’m using, in Objective C, I’d use isNumeric,
just wanted to know what the equivalent is in Python.
>>
-Original Message-
From: Christian Gollwitzer
To: python-list@python.org
Sent: Tue, Jun 7, 2022 6:01 pm
Subject: Re: How to test characters of a string
Am 07.06.22 um 21:56 schrieb Dave:
> It depends on the language I’m using, in Objective C, I’d use isNumeric, just
> wanted to know
On 2022-06-07 23:24, Dave wrote:
Yes, it was probably just a typeo on my part.
You've misspelled "typo"!
I’ve now fixed the majority of cases but still got two strings that look
identical but fail to match, this time (again by 10cc), “I’m Mandy Fly Me”.
Try printing the asciified string:
I hate regEx and avoid it whenever possible, I’ve never found something that
was impossible to do without it.
> On 8 Jun 2022, at 00:49, dn wrote:
>
> On 08/06/2022 10.18, De ongekruisigde wrote:
>> On 2022-06-08, Christian Gollwitzer wrote:
>>> Am 07.06.22 um 21:56 schrieb Dave:
It depen
On 08/06/2022 10.18, De ongekruisigde wrote:
> On 2022-06-08, Christian Gollwitzer wrote:
>> Am 07.06.22 um 21:56 schrieb Dave:
>>> It depends on the language I’m using, in Objective C, I’d use isNumeric,
>>> just wanted to know what the equivalent is in Python.
>>>
>>
>> Your problem is also a t
rotfl! Nice one!
> On 8 Jun 2022, at 00:24, 2qdxy4rzwzuui...@potatochowder.com wrote:
>
> On 2022-06-07 at 23:07:42 +0100,
> Regarding "Re: How to test characters of a string,"
> MRAB wrote:
>
>> On 2022-06-07 21:23, Dave wrote:
>>> Thanks a
Yes, it was probably just a typeo on my part.
I’ve now fixed the majority of cases but still got two strings that look
identical but fail to match, this time (again by 10cc), “I’m Mandy Fly Me”.
I’m putting money on it being a utf8 problem but I’m stuck on how to handle it.
It’s probably the si
It depends on the language I’m using, in Objective C, I’d use isNumeric,
just wanted to know what the equivalent is in Python.
If you know the answer why don’t you just tell me and if you don’t, don’t
post!
>>>
>>> People ask home work questions here and we try to teach
On 2022-06-08, Christian Gollwitzer wrote:
> Am 07.06.22 um 21:56 schrieb Dave:
>> It depends on the language I’m using, in Objective C, I’d use isNumeric,
>> just wanted to know what the equivalent is in Python.
>>
>
> Your problem is also a typical case for regular expressions. You can
> crea
Am 07.06.22 um 23:01 schrieb Christian Gollwitzer:
In [3]: re.sub(r'^\d+\s*', '', s) Out[3]: 'Trinket'
that RE does match what you intended to do, but not exactly what you
wrote in the OP. that would be '^\d\d.' start with exactly two digits
followed by any character.
Christian
-
Am 07.06.22 um 21:56 schrieb Dave:
It depends on the language I’m using, in Objective C, I’d use isNumeric, just
wanted to know what the equivalent is in Python.
Your problem is also a typical case for regular expressions. You can
create an expression for "starts with any number of digits pl
On 2022-06-07 at 23:07:42 +0100,
Regarding "Re: How to test characters of a string,"
MRAB wrote:
> On 2022-06-07 21:23, Dave wrote:
> > Thanks a lot for this! isDigit was the method I was looking for and
> > couldn’t find.
> >
> > I have another problem rel
On 2022-06-07 21:23, Dave wrote:
Thanks a lot for this! isDigit was the method I was looking for and couldn’t
find.
I have another problem related to this, the following code uses the code you
just sent. I am getting a files ID3 tags using eyed3, this part seems to work
and I get expected val
On 2022-06-08 at 07:29:03 +1000,
Chris Angelico wrote:
> On Wed, 8 Jun 2022 at 07:24, Barry wrote:
> >
> >
> >
> > > On 7 Jun 2022, at 22:04, Dave wrote:
> > >
> > > It depends on the language I’m using, in Objective C, I’d use isNumeric,
> > > just wanted to know what the equivalent is in Py
A, ok will do, was just trying to be a brief as possible, will post more
fully in future.
> On 7 Jun 2022, at 23:29, Chris Angelico wrote:
>
> On Wed, 8 Jun 2022 at 07:24, Barry wrote:
>>
>>
>>
>>> On 7 Jun 2022, at 22:04, Dave wrote:
>>>
>>> It depends on the language I’m using, in
On Wed, 8 Jun 2022 at 07:24, Barry wrote:
>
>
>
> > On 7 Jun 2022, at 22:04, Dave wrote:
> >
> > It depends on the language I’m using, in Objective C, I’d use isNumeric,
> > just wanted to know what the equivalent is in Python.
> >
> > If you know the answer why don’t you just tell me and if yo
> On 7 Jun 2022, at 22:04, Dave wrote:
>
> It depends on the language I’m using, in Objective C, I’d use isNumeric,
> just wanted to know what the equivalent is in Python.
>
> If you know the answer why don’t you just tell me and if you don’t, don’t
> post!
People ask home work questions h
Hi,
Found it! The files name had .mp3 at the end, the problem was being masked by
null objects (or whatever) being returned by eyed3.
Checked for null objects and then stripped off the .mp3 and its mostly working
now. I’ve got a few other eyed3 errors to do with null objects but I can sort
tho
Hi,
No, I’ve checked leading/trailing whitespace, it seems to be related to the
variables that are returned from eyed3 in this case, for instance, I added a
check for None:
myTitleName = myID3.tag.title
if myTitleName is None:
continue
Seems like it can return a null object (or none?).
>
It depends on the language I’m using, in Objective C, I’d use isNumeric, just
wanted to know what the equivalent is in Python.
If you know the answer why don’t you just tell me and if you don’t, don’t post!
> On 7 Jun 2022, at 22:08, 2qdxy4rzwzuui...@potatochowder.com wrote:
>
> On 2022-06-07
On 2022-06-07, Dave wrote:
> Thanks a lot for this! isDigit was the method I was looking for and couldn’t
> find.
>
> I have another problem related to this, the following code uses the code you
> just sent. I am getting a files ID3 tags using eyed3, this part seems to work
> and I get expected
On 2022-06-07, Stefan Ram wrote:
> Dave writes:
>>Example: if "05 Trinket" I want "Trinket"
>
> We're not supposed to write complete solutions,
Okay, wasn't aware of this group policy; will keep it in mind.
--
You're rewriting parts of Quake in *Python*?
MUAHAHAHA
--
https://mail.python.
On 2022-06-07 at 21:35:43 +0200,
Dave wrote:
> I’m new to Python and have a simple problem that I can’t seem to find
> the answer.
> I want to test the first two characters of a string to check if the
> are numeric (00 to 99) and if so remove the fist three chars from the
> string.
> Example: i
Thanks a lot for this! isDigit was the method I was looking for and couldn’t
find.
I have another problem related to this, the following code uses the code you
just sent. I am getting a files ID3 tags using eyed3, this part seems to work
and I get expected values in this case myTitleName (Track
On 2022-06-07, Dave wrote:
> Hi,
>
> I’m new to Python and have a simple problem that I can’t seem to find the
> answer.
>
> I want to test the first two characters of a string to check if the are
> numeric (00 to 99) and if so remove the fist three chars from the string.
>
> Example: if “05 Tr
On 08/06/2022 07.35, Dave wrote:
> Hi,
>
> I’m new to Python and have a simple problem that I can’t seem to find the
> answer.
> I want to test the first two characters of a string to check if the are
> numeric (00 to 99) and if so remove the fist three chars from the string.
>
> Example: if
Hi,
I’m new to Python and have a simple problem that I can’t seem to find the
answer.
I want to test the first two characters of a string to check if the are numeric
(00 to 99) and if so remove the fist three chars from the string.
Example: if “05 Trinket” I want “Trinket”, but “Trinket” I st
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