On 2022-06-08, Christian Gollwitzer <aurio...@gmx.de> wrote: > Am 07.06.22 um 21:56 schrieb Dave: >> It depends on the language I’m using, in Objective C, I’d use isNumeric, >> just wanted to know what the equivalent is in Python. >> > > Your problem is also a typical case for regular expressions. You can > create an expression for "starts with any number of digits plus optional > whitespace" and then replace this with nothing:
Regular expressions are overkill for this and much slower than the simple isdigit based solution. >> chris@linux-tb9f:~> ipython >> Python 3.6.15 (default, Sep 23 2021, 15:41:43) [GCC] >> Type 'copyright', 'credits' or 'license' for more information >> IPython 7.13.0 -- An enhanced Interactive Python. Type '?' for help. >> >> In [1]: import re >> >> >> >> In [2]: s='05 Trinket' >> >> >> >> In [3]: re.sub(r'^\d+\s*', '', s) >> >> >> Out[3]: 'Trinket' >> > > If it doesn't match, it will do nothing: > >> In [4]: s='Es geht los' >> >> >> >> In [5]: re.sub(r'^\d+\s*', '', s) >> >> >> Out[5]: 'Es geht los' > > Some people on this list don't like regexes but for tasks like this they > are made and working well. Regular expressions are indeeed extremely powerful and useful but I tend to avoid them when there's a (faster) normal solution. > ^ is "starts with" > \d is any digit > \s is any space > + is at least one > * is nothing or one of > > Christian -- <StevenK> You're rewriting parts of Quake in *Python*? <knghtbrd> MUAHAHAHA -- https://mail.python.org/mailman/listinfo/python-list
