On 2022-06-07, Dave <[email protected]> wrote:
> Thanks a lot for this! isDigit was the method I was looking for and couldn’t
> find.
>
> I have another problem related to this, the following code uses the code you
> just sent. I am getting a files ID3 tags using eyed3, this part seems to work
> and I get expected values in this case myTitleName (Track name) is set to
> “Deadlock Holiday” and myCompareFileName is set to “01 Deadlock Holiday”
> (File Name with the Track number prepended). The is digit test works and
> myCompareFileName is set to “Deadlock Holiday”, so they should match, right?
>
> However the if myCompareFileName != myTitleName always gives a mismatch! What
> could cause two string that look the fail to not match properly?
Possibly leading or trailing spaces, or upper/lower case differences?
> myCompareFileName = myFile
> if myCompareFileName[0].isdigit() and myCompareFileName[1].isdigit():
> myCompareFileName = myCompareFileName[3:]
>
> if myCompareFileName != myTitleName:
> print('File Name Mismatch - Artist: ',myArtistName,' Album:
> ',myAlbumName,' Track:',myTitleName,' File: ',myFile)
> Thanks a lot
> Dave
>
>> On 7 Jun 2022, at 21:58, De ongekruisigde
>> <[email protected]> wrote:
>>
>> On 2022-06-07, Dave <[email protected]> wrote:
>>> Hi,
>>>
>>> I’m new to Python and have a simple problem that I can’t seem to find the
>>> answer.
>>>
>>> I want to test the first two characters of a string to check if the are
>>> numeric (00 to 99) and if so remove the fist three chars from the string.
>>>
>>> Example: if “05 Trinket” I want “Trinket”, but “Trinket” I still want
>>> “Trinket”. I can’t for the life of work out how to do it in Python?
>>
>>
>> s[3:] if s[0:2].isdigit() else s
>>
>>
>>> All the Best
>>> Dave
>>>
>>
>> --
>> <StevenK> You're rewriting parts of Quake in *Python*?
>> <knghtbrd> MUAHAHAHA
>> --
>> https://mail.python.org/mailman/listinfo/python-list
>
--
<StevenK> You're rewriting parts of Quake in *Python*?
<knghtbrd> MUAHAHAHA
--
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