On 2015-05-19 06:42, massi_...@msn.com wrote:
> I succesfully wrote a regex in python in order to substitute all
> the occurences in the form $"somechars" with another string. Here
> it is:
>
> re.sub(ur"""(?u)(\$\"[^\"\\]*(?:\\.[^\"\\]*)*\")""", newstring,
> string)
The expression is a little mo
Hi everyone,
I succesfully wrote a regex in python in order to substitute all the occurences
in the form $"somechars" with another string. Here it is:
re.sub(ur"""(?u)(\$\"[^\"\\]*(?:\\.[^\"\\]*)*\")""", newstring, string)
Now I would need to exclude from the match all the string in the form $"
Sorry, if I missed some further specification in the earlier thread or
if the following is oversimplification of the original problem (using
3 numbers instead of 32),
would something like the following work for your data?
>>> import re
>>> data = """2.201000e+01 2.15e+01 2.199000e+01 : (instan
On Friday, August 19, 2011, Carl Banks wrote:
> On Friday, August 19, 2011 10:33:49 AM UTC-7, Matt Funk wrote:
> > number = r"\d\.\d+e\+\d+"
> > numbersequence = r"%s( %s){31}(.+)" % (number,number)
> > instance_linetype_pattern = re.compile(numbersequence)
> >
> > The results obtained are:
> > re
On Friday, August 19, 2011, jmfauth wrote:
> On 19 août, 19:33, Matt Funk wrote:
> > The results obtained are:
> > results:
> > [(' 2.199000e+01', ' : (instance: 0)\t:\tsome description')]
> > so this matches the last number plus the string at the end of the line,
> > but no retaining the previous
On 19/08/2011 20:55, ru...@yahoo.com wrote:
On 08/19/2011 11:33 AM, Matt Funk wrote:
On Friday, August 19, 2011, Alain Ketterlin wrote:
Matt Funk writes:
thanks for the suggestion. I guess i had found another way around the
problem as well. But i really wanted to match the line exactly and i
On Friday, August 19, 2011 10:33:49 AM UTC-7, Matt Funk wrote:
> number = r"\d\.\d+e\+\d+"
> numbersequence = r"%s( %s){31}(.+)" % (number,number)
> instance_linetype_pattern = re.compile(numbersequence)
>
> The results obtained are:
> results:
> [(' 2.199000e+01', ' : (instance: 0)\t:\tsome desc
On 08/19/2011 11:33 AM, Matt Funk wrote:
> On Friday, August 19, 2011, Alain Ketterlin wrote:
>> Matt Funk writes:
>> > thanks for the suggestion. I guess i had found another way around the
>> > problem as well. But i really wanted to match the line exactly and i
>> > wanted to know why it doesn't
On 19 août, 19:33, Matt Funk wrote:
>
> The results obtained are:
> results:
> [(' 2.199000e+01', ' : (instance: 0)\t:\tsome description')]
> so this matches the last number plus the string at the end of the line, but no
> retaining the previous numbers.
>
> Anyway, i think at this point i will go
On Friday, August 19, 2011, Alain Ketterlin wrote:
> Matt Funk writes:
> > thanks for the suggestion. I guess i had found another way around the
> > problem as well. But i really wanted to match the line exactly and i
> > wanted to know why it doesn't work. That is less for the purpose of
> > gett
Matt Funk writes:
> thanks for the suggestion. I guess i had found another way around the
> problem as well. But i really wanted to match the line exactly and i
> wanted to know why it doesn't work. That is less for the purpose of
> getting the thing to work but more because it greatly annoys me
On 19 août, 17:20, Matt Funk wrote:
> Hi,
> thanks for the suggestion. I guess i had found another way around the
> problem as well. But i really wanted to match the line exactly and i
> wanted to know why it doesn't work. That is less for the purpose of
> getting the thing to work but more becaus
Hi,
thanks for the suggestion. I guess i had found another way around the
problem as well. But i really wanted to match the line exactly and i
wanted to know why it doesn't work. That is less for the purpose of
getting the thing to work but more because it greatly annoys me off that
i can't figure
> Hi Josh,
> thanks for the reply. I am no expert so please bear with me:
> I thought that the {32} was supposed to match the previous expression 32
> times?
>
> So how can i have all matches accessible to me?
$ python
Python 2.6.5 (r265:79063, Apr 16 2010, 13:57:41)
[GCC 4.4.3] on linux2
Type "he
Hi Josh,
thanks for the reply. I am no expert so please bear with me:
I thought that the {32} was supposed to match the previous expression 32
times?
So how can i have all matches accessible to me?
matt
On Thursday, August 18, 2011, Josh Benner wrote:
> On Thu, Aug 18, 2011 at 4:03 PM, Matt F
On Thu, Aug 18, 2011 at 4:03 PM, Matt Funk wrote:
> Hi guys,
>
> thanks for the suggestions. I had tried the white space before as well (to
> no
> avail). So here is the expression i am using (based on suggestions), but
> still
> no success:
>
> instance_linetype_pattern_str =\
>r'(([-+]?
Hi guys,
thanks for the suggestions. I had tried the white space before as well (to no
avail). So here is the expression i am using (based on suggestions), but still
no success:
instance_linetype_pattern_str =\
r'(([-+]?(\d+(\.\d*)?|\.\d+)([eE][-+]?\d+))?\s+){32}(.+)'
instance_linetype_
2011/8/18 Matt Funk :
> Hi,
> i am sorry if this doesn't quite match the subject of the list. If someone
> takes offense please point me to where this question should go. Anyway, i have
> a problem using regular expressions. I would like to match the line:
>
> 1.002000e+01 2.037000e+01 2.128000e+01
In Matt Funk
writes:
> 1.002000e+01 2.037000e+01 2.128000e+01 1.908000e+01 1.871000e+01 1.914000e+01
> instance_linetype_pattern_str = '([-+]?(\d+(\.\d*)?|\.\d+)([eE][-+]?\d+)?)
> {32}'
> instance_linetype_pattern = re.compile(instance_linetype_pattern_str)
Does your regexp account for the s
You don't seem to account for the whitespace between the floats. Try
> '([-+]?(\d+(\.\d*)?|\.\d+)([eE][-+]?\d+)?\s+){32}'
(just added \s+).
Martin
On 8/18/2011 9:49 PM, Matt Funk wrote:
> Hi,
> i am sorry if this doesn't quite match the subject of the list. If someone
> takes offense please poin
Hi,
i am sorry if this doesn't quite match the subject of the list. If someone
takes offense please point me to where this question should go. Anyway, i have
a problem using regular expressions. I would like to match the line:
1.002000e+01 2.037000e+01 2.128000e+01 1.908000e+01 1.871000e+01 1.91
On Oct 24, 12:00 am, Edward Dolan wrote:
> No, you're not missing a thing. I am ;) Something was happening with
> the triple-quoted
> strings when I pasted them. Here is hopefully, the correct
> code.http://codepad.org/OIazr9lA
> The output is shown on that page as well.
>
> Sorry for the line no
No, you're not missing a thing. I am ;) Something was happening with
the triple-quoted
strings when I pasted them. Here is hopefully, the correct code.
http://codepad.org/OIazr9lA
The output is shown on that page as well.
Sorry for the line noise folks. One of these days I'm going to learn
gnus.
-
On Oct 23, 3:48 am, Edward Dolan wrote:
> On Oct 22, 3:26 pm, Jeremy wrote:
>
> > My question is, how can I use regular expressions to find two OR three
> > or even an arbitrary number of floats without repeating %s? Is this
> > possible?
>
> > Thanks,
> > Jeremy
>
> Any time you have tabular da
I can see why this line could wrap
> 1.E-08 1.58024E-06 0.0048 1.E-08 1.58024E-06
> 0.0048
But this one?
> 1.E-07 2.98403E-05
> 0.0018
anyway, here is the code -> http://codepad.org/Z7eWBusl
--
http://mail.python.org/mailman/listinfo/python-list
On Oct 22, 3:26 pm, Jeremy wrote:
> My question is, how can I use regular expressions to find two OR three
> or even an arbitrary number of floats without repeating %s? Is this
> possible?
>
> Thanks,
> Jeremy
Any time you have tabular data such as your example, split() is
generally the first ch
> I have text that looks like the following
> (but all in one string with '\n' separating the lines):
>
>
> I want to capture the two or three floating point numbers in each line
> and store them in a tuple.
>
> I have the regular expression pattern
>
Jeremy
For a non-r
On Thu, 22 Oct 2009 23:26:01 +0100, Jeremy wrote:
I have text that looks like the following (but all in one string with
'\n' separating the lines):
1.E-08 1.58024E-06 0.0048
[snip]
5.E+00 2.42717E-05 0.0017
total 1.93417E-04 0.0012
I want to capture the two or
I have text that looks like the following (but all in one string with
'\n' separating the lines):
1.E-08 1.58024E-06 0.0048
1.E-07 2.98403E-05 0.0018
1.E-06 8.85470E-06 0.0026
1.E-05 6.08120E-06 0.0032
1.E-03 1.61817E-05 0.0022
1.E+00 8.3
Hi:
i'm so newbie in python that i don't get the right idea about regular
expressions. This is what i want to do:
Extract using python some information and them replace this expresion
for others, i use as a base the wikitext and this is what i do:
paragraphs = """
= Test '''wikitest'''=
[[Image
Seem to be a lot of regular expression questions lately. There is a
neat little RE demonstrator buried down in
Python24/Tools/Scripts/redemo.py, which makes it easy to experiment
with regular expressions and immediately see the effect of changes. It
would be helpful if it were mentioned in the RE d
'''\[(.*?)\]'''
?-> when this char after(*, +, ?, {n}, {n,}, {n,m}), the match pattern
is not greedy
e.g.1
String: 512.16[3][b]]
Pattern:'''\[(.*)\]'''
This will match "[3][b]]"
e.g.2
String: 512.16[3][b]]
Pattern:'''\[(.*)?\]'''
This will match "[3]" and "[b]"
--
http://mail.python.org/mailman
ProvoWallis wrote:
> Hi,
>
> I'm looking for a little advice about regular expressions. I want to
> capture a string of text that falls between an opening squre bracket
> and a closing square bracket (e.g., "[" and "]") but I've run into a
> small problem.
>
> I've been using this: '''\[(.*?)\]''
Hi,
I'm looking for a little advice about regular expressions. I want to
capture a string of text that falls between an opening squre bracket
and a closing square bracket (e.g., "[" and "]") but I've run into a
small problem.
I've been using this: '''\[(.*?)\]''' as my pattern. I was expecting
th
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