I have text that looks like the following (but all in one string with
'\n' separating the lines):
1.0000E-08 1.58024E-06 0.0048
1.0000E-07 2.98403E-05 0.0018
1.0000E-06 8.85470E-06 0.0026
1.0000E-05 6.08120E-06 0.0032
1.0000E-03 1.61817E-05 0.0022
1.0000E+00 8.34460E-05 0.0014
2.0000E+00 2.31616E-05 0.0017
5.0000E+00 2.42717E-05 0.0017
total 1.93417E-04 0.0012
I want to capture the two or three floating point numbers in each line
and store them in a tuple. I want to find all such tuples such that I
have
[('1.0000E-08', '1.58024E-06', '0.0048'),
('1.0000E-07', '2.98403E-05', '0.0018'),
('1.0000E-06', '8.85470E-06', '0.0026'),
('1.0000E-05', '6.08120E-06', '0.0032'),
('1.0000E-03', '1.61817E-05', '0.0022'),
('1.0000E+00', '8.34460E-05', '0.0014'),
('2.0000E+00', '2.31616E-05', '0.0017'),
('5.0000E+00', '2.42717E-05', '0.0017')
('1.93417E-04', '0.0012')]
as a result. I have the regular expression pattern
fp1 = '([-+]?\d*\.?\d+(?:[eE][-+]?\d+)?)\s+'
which can find a floating point number followed by some space. I can
find three floats with
found = re.findall('%s%s%s' %fp1, text)
My question is, how can I use regular expressions to find two OR three
or even an arbitrary number of floats without repeating %s? Is this
possible?
Thanks,
Jeremy
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