On Thu, 22 Oct 2009 23:26:01 +0100, Jeremy <jlcon...@gmail.com> wrote:
I have text that looks like the following (but all in one string with
'\n' separating the lines):
1.0000E-08 1.58024E-06 0.0048
[snip]
5.0000E+00 2.42717E-05 0.0017
total 1.93417E-04 0.0012
I want to capture the two or three floating point numbers in each line
and store them in a tuple. I want to find all such tuples such that I
have
[('1.0000E-08', '1.58024E-06', '0.0048'),
[snip]
('5.0000E+00', '2.42717E-05', '0.0017')
('1.93417E-04', '0.0012')]
as a result. I have the regular expression pattern
fp1 = '([-+]?\d*\.?\d+(?:[eE][-+]?\d+)?)\s+'
which can find a floating point number followed by some space.
Hmm. Is ".01" really valid? Oh well, let's assume so. I'd
seriously recommend using a raw string r'....' to define fp1
with though; it's a good habit to get into with regular expressions,
and when (not if) the fact that none of your backslashes are
escaped matters, you won't waste hours wondering what just bit you.
I can
find three floats with
found = re.findall('%s%s%s' %fp1, text)
My question is, how can I use regular expressions to find two OR three
or even an arbitrary number of floats without repeating %s? Is this
possible?
Yes. On the off-chance that this is homework, I'll just observe that
the only difference between detecting repeated digits (say) and repeated
float-expressions is exactly what you apply the repetition operators to.
The documentation for the 're' module at python.org is your friend!
--
Rhodri James *-* Wildebeest Herder to the Masses
--
http://mail.python.org/mailman/listinfo/python-list
