Hi all,
This was more a question of programming aesthetics for me than one of
great practical significance. I was looking to perform a certain
function on files in a directory so long as those files weren't found
in certain standard directories. In other words, I was using os.walk
() to get mult
Thanks all!! I found the following to be most helpful: any(substr in
long_string for substr in list_of_strings)
This bang-for-your-buck is one of the many many reasons why I love
Python programming :)
Matt Dubins
--
http://mail.python.org/mailman/listinfo/python-list
Hi all,
For one of my projects, I came across the need to check if one of many
items from a list of strings could be found in a long string. I came
up with a pretty quick helper function to check this, but I just want
to find out if there's something a little more elegant than what I've
cooked up
Frame.focus_force() method. Observe:
self.userid = tkSimpleDialog.askstring("UTSCID Entry","UTSCID:")
self.focus_force()
Now, the next tkSimpleDialog.askstring call that I made ACTUALLY gets
the keyboard focus automatically.
Cheers,
Matt
On Feb 4, 10:21 am, inkhorn wrote:
&
Hi all,
As part of the program I've created and am maintaining, the user has
to type in his/her username and password into tkinter simple dialog
windows. What you'll see below is that I've nested an askstring
dialog window within a call to use the ftp module to login to an FTP
server.
result = s
Wow thanks for the lightning fast reply! This does exactly the right
job.
Matt
On Feb 1, 3:01 pm, Stephen Hansen wrote:
> I'd like to know how to elegantly check a list for the membership of
> any of its items to another list. Not caring for elegance, I would
> use the following code:
> That's
Dear all,
I'd like to know how to elegantly check a list for the membership of
any of its items to another list. Not caring for elegance, I would
use the following code:
blah = [1,2,3]
yadda = [3,4,5,6]
blah[0] or blah[1] or blah[2] in yadda
Please tell me how to change the preceding code into
