Wow thanks for the lightning fast reply! This does exactly the right job. Matt
On Feb 1, 3:01 pm, Stephen Hansen <apt.shan...@gmail.com> wrote: > I'd like to know how to elegantly check a list for the membership of > any of its items to another list. Not caring for elegance, I would > use the following code: > That's one of the useful properties of sets: > >>> a = [1,2,3] > >>> b = [3,4,5,6] > >>> set(a) & set(b) > set([3]) > >>> set(a).intersection(b) > set([3]) > That's two spellings of the same thing. As for testing: an empty set like an > empty list will return false, so "if set(a) & set(b):" will be true or false > based on if there's any commonalities between the two lists. > --Stephen > > signature.asc > < 1KViewDownload -- http://mail.python.org/mailman/listinfo/python-list
