Re: Confidence interval is mathematically equivalent to hypothesis test

2018-10-14 Thread John Darrington
On Sun, Oct 14, 2018 at 10:07:09AM +0200, Dr. Oliver Walter wrote: Am 14.10.2018 um 09:41 schrieb John Darrington: > Which is why I suggested using one of the CDF functions. > There is no T function, but there is a F function, which I think is the > same if you set DF2 to

Re: Confidence interval is mathematically equivalent to hypothesis test

2018-10-14 Thread Dr. Oliver Walter
Am 14.10.2018 um 09:41 schrieb John Darrington: Which is why I suggested using one of the CDF functions. There is no T function, but there is a F function, which I think is the same if you set DF2 to 1. But you probably know better than me about those details. Perhaps IDF.F (0.05, N -1, 1) is

Re: Confidence interval is mathematically equivalent to hypothesis test

2018-10-14 Thread John Darrington
On Sun, Oct 14, 2018 at 09:28:47AM +0200, Dr. Oliver Walter wrote: Am 14.10.2018 um 08:46 schrieb John Darrington: > AGGREGATE OUTFILE * MODE ADDVARIABLES > /BREAK=g > /Mean = mean(V) > /sd = sd(v) > /n = n(v) > . > > compute

Re: Confidence interval is mathematically equivalent to hypothesis test

2018-10-14 Thread Dr. Oliver Walter
Am 14.10.2018 um 08:46 schrieb John Darrington: AGGREGATE OUTFILE * MODE ADDVARIABLES /BREAK=g /Mean = mean(V) /sd = sd(v) /n = n(v) . compute ci_upper=mean + sd/sqrt(n). compute ci_lower=mean - sd/sqrt(n). list. Sorry for interrupting, but this doesn't give a 95% (or 9

Re: Confidence interval is mathematically equivalent to hypothesis test

2018-10-14 Thread Werner LEMBERG
> If I understand the use case properly, I think that you can do what > you want with with an aggregate followed by a few simple compute > commands: [...] Thanks! Werner ___ Pspp-users mailing list Pspp-users@gnu.org https://lists.gnu.org/mailma