Many thanks.
On Jun 16, 12:18 pm, David Santiago wrote:
> Change the first line to something like (def csv (parse-csv (slurp
> "path/to/my/file.csv"))).
>
> - David
>
> On Thu, Jun 16, 2011 at 8:20 AM, octopusgrabbus
>
>
>
>
>
>
>
> wrote:
> > I would like to modify the examples given
>
> > u
Change the first line to something like (def csv (parse-csv (slurp
"path/to/my/file.csv"))).
- David
On Thu, Jun 16, 2011 at 8:20 AM, octopusgrabbus
wrote:
> I would like to modify the examples given
>
> user=> (def csv (parse-csv "1,2,3\n4,5,6\n7,8,9"))
> #'user/csv
> user=> (nth (nth csv 1)
I would like to modify the examples given
user=> (def csv (parse-csv "1,2,3\n4,5,6\n7,8,9"))
#'user/csv
user=> (nth (nth csv 1) 2) ;; Get 2nd row, last column.
"6"
user=> (-> csv (nth 1) (nth 2)) ;; Another way to do it.
"6"
user=> (defn get-column [parsed-csv col] (map #(nth % col)
parsed-csv))
Here's a repl session that will hopefully demonstrate how to do a few
things, including pull out an entire column. Just remember the library
turns CSVs into regular clojure data structures, so getting the data
you want out of the return value of the parse is just about indexing
into vectors.
user=
I've got to go back and look at your documentation. I'm not sure how
to pull the columns out of each row.
On Jun 15, 5:04 pm, David Santiago wrote:
> I'm afraid I don't understand the question. What do you mean
> "positionally?" When it parses the CSV file, it gives you back a
> stream of rows, e
I'm afraid I don't understand the question. What do you mean
"positionally?" When it parses the CSV file, it gives you back a
stream of rows, each row being a vector of the contents of each cell
of the CSV. If you are interested in cells at a given row/column, you
should be able to count into those
Is it possible to use clojure-csv to extract data positionally in
a .csv file, or should I use BufferedReader to read each line lazily
and apply splitting the line up into fields by delimiter?
Thanks.
cmn
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