Here's a repl session that will hopefully demonstrate how to do a few
things, including pull out an entire column. Just remember the library
turns CSVs into regular clojure data structures, so getting the data
you want out of the return value of the parse is just about indexing
into vectors.
user=> (use 'clojure-csv.core)
nil
user=> (def csv (parse-csv "1,2,3\n4,5,6\n7,8,9"))
#'user/csv
user=> (nth (nth csv 1) 2) ;; Get 2nd row, last column.
"6"
user=> (-> csv (nth 1) (nth 2)) ;; Another way to do it.
"6"
user=> (defn get-column [parsed-csv col] (map #(nth % col)
parsed-csv)) ;; Function to return a given column.
#'user/get-column
user=> (get-column csv 1) ;; Get second column as a sequence.
("2" "5" "8")
- David
On Wed, Jun 15, 2011 at 9:58 PM, octopusgrabbus
<octopusgrab...@gmail.com> wrote:
> I've got to go back and look at your documentation. I'm not sure how
> to pull the columns out of each row.
>
> On Jun 15, 5:04 pm, David Santiago <david.santi...@gmail.com> wrote:
>> I'm afraid I don't understand the question. What do you mean
>> "positionally?" When it parses the CSV file, it gives you back a
>> stream of rows, each row being a vector of the contents of each cell
>> of the CSV. If you are interested in cells at a given row/column, you
>> should be able to count into those vectors fairly naturally...
>>
>> - David
>>
>> On Wed, Jun 15, 2011 at 2:08 PM, octopusgrabbus<octopusgrab...@gmail.com>
>> wrote:
>> > Is it possible to use clojure-csv to extract data positionally in
>> > a .csv file, or should I use BufferedReader to read each line lazily
>> > and apply splitting the line up into fields by delimiter?
>>
>> > Thanks.
>> > cmn
>>
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